Unit Circle Flashcards

1
Q

Locate the following:

π

π/2

3π/2

0

A

π = 180°

π/2 = 90°

3π/2 = 270°

2π = 360° = 0°

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2
Q

Locate the following:

π/3

π/4

π/6

A

π/3 = 60°

π/4 = 45°

π/6 = 30°

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3
Q

On the unit circle the x and y coordinates are found by?

A

cosØ = x

sinØ = y

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4
Q

The cartesion form of the unit circle is:

x² + y² = 1

what is the equivalent parametric form?

A

cos²Ø + sin²Ø = 1

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5
Q

cosØ =

sinØ =

tanØ =

A

x

y

sin/cos

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6
Q

What are the reciprocal functions of:

cosØ

sinØ

tanØ

A

1/cosØ = secØ

1/sinØ = cosecØ

1/tanØ = cotØ

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7
Q

The parametric equation for unit circle is:

cos²Ø + sin²Ø = 1

Divide this by cos²Ø:

A

1 + tan²Ø = sec²Ø

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8
Q

The parametric equation for unit circle is:

cos²Ø + sin²Ø = 1

Divide this by sin²Ø:

A

cot²Ø + 1 = cosec²Ø

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9
Q

Complete the following:

cosØ =

secØ =

sinØ =

cosecØ =

tanØ =

cotØ =

A

cosØ = x

secØ = 1/cos

sinØ = y

cosecØ = 1/sin

tanØ = sin/cos

cotØ =cos/sin

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10
Q

What is meant by the periodic property of sin and cos?

A

cosØ = cos(Ø + 2kπ)

sinØ = sin(Ø + 2kπ)

*π = 180°, therefore 2π = 360°

so any multiple of 2π will result in the same position on the circle.

e.g. Ø + 2kπ, Ø = 90, k =3

90 + 2(3)180

90+ 1080

90 + 3(360)

e.g start at 90 and go around 3 full circles. You end up where you started, at 90.

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11
Q

CAST divides the unit circle into 4 quadrants.

Which quadrant do the following belong to?

π - Ø

π + Ø

2π - Ø

A

π - Ø = 2nd

π + Ø = 3rd

2π - Ø = 4th

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12
Q

In which quadrant is:

tan positive?

cos positive?

sin positive?

A
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13
Q

secØ =

cosecØ =

cotØ =

A

1/cos

1/sin

cos/sin

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14
Q

sin(-Ø) =

cos(-Ø) =

A

sin(-Ø) = -sin(Ø)

cos(-Ø) = -cos(Ø)

Can you explain why?

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15
Q

sin(-Ø) = -sin(Ø)

cos(-Ø) = -cos(Ø)

Can you explain why?

A

sin(x) is an odd function (symmetrical about the origin) - therefore f(x) = -f(x)

cos(x) is an even function (symmetrical about the y-axis).

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16
Q

sin ( x + y) =

sin (x - y) =

A

sin ( x + y) = sinx cosy + cosx siny

sin (x - y) = sinx cosy - cosx siny

17
Q

cos π/4 = 1/√2

sin π/4 = ?

tan π/4 = ?

A

sin π/4 = 1/√2

tan π/4 = 1