Unit 2 Day 4 Flashcards

1
Q

What is AD?

A

mutation rate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What is AR?

A

carrier rate

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

population genetics

A

the study of allele frequencies and changes in allele frequencies in populations

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

mutation rates

A

a measure of the rate at which various types of mutations occur over time. Mutation rates are typically given for a specific class of mutation, for instance point mutations, small or large scale insertions or deletions.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

fitness

A

individual reproductive success and is equal to the average contribution to the gene pool of the next generation that is made by an average individual of the specified genotype or phenotype.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

consanguinity

A

the property of being from the same kinship as another person. In that aspect, consanguinity is the quality of being descended from the same ancestor as another person.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

hardy Weinberg principle

A

allele and genotype frequencies in a population will remain constant from generation to generation in the absence of other evolutionary influences.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

population genetics

A

the study of allele (mutation) frequencies and changes in allele (mutations) frequencies in populations
-we are interested in deleterious mutations and a few beneficial ones

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

what are population genetics important for?

A

understanding allele frequency in populations and how those frequencies change

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

population sampling by phenotype leads to what?

A

estimates of allele frequency the underlying genetic mechanism

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

what are the basic principles of population genetics?

A

estimate mutation rates
determine fitness
effects of consanguinity
addition of new mutations to gene pool

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

hardy weinberg frequency

A

p+q=1

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

hardy weinberg equation

A

p² + 2pq + q² = 1

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

what is q in the hardy weinberg equation

A

q equals all of the alleles in individuals who are homozygous recessive (aa) and the other half of the alleles in people who are heterozygous (Aa)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

what is p in the hardy weinberg equation

A

p equals all of the alleles in individuals who are homozygous dominant (AA) and half of the alleles in people who are heterozygous (Aa) for this trait in a population.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

what can we learn from hardy weinberg principles?

A
  • new mutations occur regularly
  • most mutations are benign
  • next gen DNA sequencing will determine whether the estimates we derive of mutation rates are correct
  • by observing the number of cases of disease in a pop, it is possible to calculate rates of mutation for diff conditions
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Assumptions of Hardy Weinberg principle

A

population matings are random

allele frequencies remain constant over time

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

why do allele frequencies remain constant over time?

A
  • No appreciable rate of mutation
  • All genotypes are equally fit (equal chance to pass alleles to next generation)
  • No significant immigration/emigration of individuals with different allele frequencies
19
Q

allele frequency estimation is useful for?

A
  • autosomal recessive where you estimate carrier rates

- applied genetic counseling for couples (integrate family history)

20
Q

what is the carrier frequency

A

2pq

21
Q

what is prevalence of disease

A

q^2

22
Q

why sex?

A

allows introduction of genetic variation to propagate new genetic traits
-benefits organisms who live in changing env., need to fend off disease, need to purge deleterious mutations

23
Q

variation occurs due to ?

A

parental genomes

recombination in meiosis

24
Q

sexual dimorphism

A

phenotypic differences btw males and females

reproductive organs, body habitus

25
Q

Jacob’s syndrome

A
47, XYY
learning disabilities
speech delay
developmental delay
behavioral/emotional difficulties
autism
tall
1/1000 boys
26
Q

Triplet X syndrome

A
47XXX
tall
risk of:
learning disabilities, delayed speech
delayed motor milestones
seizures
kidney abnormalities
1/1000 newborn girls
27
Q

gonad determination is…?

A

chromosomal
-y=male
-x and no y=female
(normal cases)

28
Q

are fetuses inherently female?

A

no.
both ovaries/testes result from common, bipotent gonad
gene directed processes

29
Q

what do the gonads tell the body to develop?

A

secondary sex charachteristics

phenotypic features

30
Q

genital ducts

A

2 in males and females
mesonephric/wolffian ducts=male structures
paramesonephric/mullerian ducts=female structures

31
Q

Mesonephric/Wolffian ducts

A

-SRY on Y chromosome; SOX9 gene
(transcription factors produce MIS, regression of paramesonephric ducts)
-FGF9 (causes tubes from mesonephric duct to penetrate gonadal ridge, differentiation testes)
-SF1/NR5A1 (differentiation sertoli and leydig cells)

32
Q

what effect does testosterone have on wolffian ducts?

A

elongate to form epididymis, seminal vesicles, vas deferens

33
Q

Mullerian/paramesonephric ducts

A
  • WNT4 protein (signaling factor for ovary, inhibited by SOX9)
  • DHH gene (nuclear hormone receptor, upregualted WNT4, downregulated SOX9)
  • RSPO1 gene (coactivator of WNT path)
34
Q

what effect does estrogen have on mullein ducts?

A

female structures

forms uterus, cervix, broad ligament, fallopian, upper 1/3 of vagina

35
Q

androgen exposure for males results in what?

A

penis
scrotum
location of urethral opening

36
Q

estrogen exposure for females results what?

A

clitoris
labia majora/minora
lower 2/3 of vagina

37
Q

when does external genitalia develop?

A

at 3 weeks
from mesenchymal cells
form genital tubercle, genital swelling

38
Q

what tests are ordered for disorders of sexual differentiation

A
first day of life
FISH (sex chromosomes)
karyotype (chromosome microarray)
hormone studies
ultrasound
surgical consult with urology
39
Q

Androgen insensitivity syndrome (AIS)

A
46 XY (genetically male)
X-linked AR
abnormality of androgen receptor (doesn't recognize/respond)
phenotypes range from mild to full reversal of sexualization
40
Q

5-alpha reductase deficiency

A

46 XY
mutation means body can’t convert testosterone to dihydrotestosterone
phenotype=undervirilized male with increased virilization at puberty

41
Q

SRY Gene disorders

A

46 XY, 46 XX
Y linked gene
-deletion/absence of gene=phenotypically normal female
-ectopic presence of SRY gene in 46XX is a phenotypically normal male
-mutations in 46 XY= decreased/absent production of anti mullein hormone

42
Q

Denys-Drash and Frasier Syndrome

A

Sex reversal w/ 46XY
mutations in WT1 gene
different chronic kidney diseases
increased risk wilms tumor

43
Q

congenital adrenal hyperplasia

A

ambiguous genitalia 46XX
21-hydroxylase deficiency
salt wasting