Unit 2 Flashcards
Every polynomial becomes infinite as x does
becomes positively/negatively infinite, depending only on the sign of the leading coefficient and the degree of the polynomial
horizontal asymptote: y=b is a horizontal asymptote of the graph if
lim (x-> ∞) f(x) = b or lim (x->-∞) f(x)
THEOREMS ON LIMITS
lim kf(x) =
k lim f(x)
lim [f(x) + g(x)] =
lim f(x) + lim g(x)
lim f(x)g(x) =
(lim f(x))(lim g(x))
lim f(x)/g(x) =
lim f(x) / lim g(x) (if lim g(x) does not equal 0)
lim (x->c) k =
k
lim (x-> ∞) 1/x =
0
Limit of a Quotient of Polynomials
the limit of a quotient of two polynomials P(x)/Q(x) , as x approaches a finite value, can be found by directly substituting the value into the polynomials because all polynomials are continuous
Rational Function Theorem
states that if a polynomial equation with integer coefficients has a rational solution, that solution can be expressed as a fraction p/q, where p is a factor of the constant term (term without any variable) and q is a factor of the leading coefficient
CONTINUOUS FUNCTIONS
- polynomials
- rational functions P(x)/Q(x) except where Q(x)=0
- absolute value functions
- trigonometric, inverse trigonometric, exponential, logarithmic functions
Extreme Value Theorem
if f is continuous on the closed interval [a, b], then f attains a minimum value and a maximum value somewhere in that interval
Intermediate Value Theorem
if f is continuous on the closed interval [a, b], and M is a number such that f(a) </= M </= f(b), then there is at least one value, c, in the interval [a, b], such that f(c) = M
derivatives do not exist where _____ exist
asymptotes, holes, vertical tangents, and sharp points
instantaneous rate
derivative at the given point
average rate
slope of the endpoints (dy/dx)
position
feet: s(t) = -16t^2 + Vot + So
meters: s(t) = -4.9t^2 + Vot + So
- Vot is initial velocity
- So is initial height
velocity
derivative of position, integral of acceleration
acceleration
derivative of acceleration
quotient rule
low dHi - Hi dlow over the bottom squared and away we go
DERIVATIVES
d/dx (tanx) =
sec^2 x
d/dx (cotx) =
-csc^2 x