Unit 1-Problem Solving

Question 0

Vertical Imbalance:
ex)
OD -3.00-2.00x180
OS -2.00-1.00x120

Reding lvl 10mm

Answer 0

Find total sph power
OD -5.00 OS -2.25
Difference is 2.75
Reading lvl 10mm (1cm)
2.75x1= 2.74

Question 1

How to find vertical imbalance?
ex)
OD: +3.00-0.50x135
OS: +2.00-1.00x030

10mm
(Remember 10mm=1cm)

Answer 1

Find total sph power for each eye
OD +2.75 OS +1.25
Difference is 1.50
Reading lvl is 10mm
1.50x1= Vertical imbalance is 1.50

Question 2

Axis is 30 away 180?

Answer 2

25% felt

Question 3

Axis is 45 away from 180?

Answer 3

50% felt

Question 4

Axis is 60 away from 180?

Answer 4

75% felt

Question 5

Axis is 90 away from 180?

Answer 5

100% felt

Question 6

Vertex Distance:

Remember to move decimal over 3 places.

Answer 6

Dxd/1000= new rx

Question 7

Prentice’s Rule

Question 8

A plus lens moved closer to the eye will…

Answer 8

Become less effective

Question 9

A new rx with a large increase in plus power will require the patient to converge _______ when reading.

Answer 9

More

Question 10

Temporary prism applied to evaluate acceptance of vertical imbalance.

Answer 10

Fresnel Prism

Question 11

If the panto is increased the distance optical center should be…

Answer 11

Lowered.

Question 12

Minus lenses moved closer to the eye become….

Answer 12

More effective.