Unit 1 - Chapter 4 Flashcards

1
Q

Drawing Lewis structures

A

determine the total number of valence electrons, taking into account charge if it’s an ion
place the least electronegative as a central atom surrounded by the other atoms
determine the electron distribution by arranging the electrons between the central atom and the outer atom, then completing the octets for the outer atoms, then as lone pairs around the central atom

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Molecules of second row elements

A

second row elements have the second energy level as their valence shell
with only s and p orbitals, their bonding capacity is limited by the octet rule

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Resonance structures

A

when drawing Lewis structures, sometimes there are two or more acceptable diagrams for one molecule
these molecules are classified as resonance structures, and the real structure cannot be represented by a single diagram
the true molecule is a hybrid of all of the possible diagrams
Lewis structures are therefore the best approximation

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Measurable properties of covalent bonds

A

bond length = average distance between two nuclei of bonded atoms (shorter = stronger)
bond energy = energy released as bond forms (higher = stronger)
by measuring these properties on resonance structures, all bonds have the same length and energy

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Molecules of third row elements and beyond

A

elements with a valence shell beyond the second energy level have access to s, p, and d orbitals
their valence shell is therefore not limited by the octet rule
with these elements, the concept of formal charge allows us to draw the best structure

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Formal charge

A

the apparent charge on atoms in a Lewis structure that arises when the atoms have not made equal contributions of electrons to the covalent bonds
once formal charges have been assigned to each atom in the Lewis structure, they can be reduced by shifting lone pairs to form double bonds
minimizing formal charge in this way does not charge the fact that a structure is a resonance structure
minimizing formal charge may also expose the presence of a resonance structure

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

The best Lewis structure

A

all atoms have a formal charge of zero
if formal charge can’t be reduced to zero, remaining charges are as small as possible
formal charges add to zero if molecule is neutral, or add to charge of ion
any negative charges are on most electronegative ion

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

VSEPR theory

A

valence shell electron pair repulsion theory
valence shell electron pairs around central atom determine the shape of a molecule due to optimal arrangement
repulsion forces between electron pairs will position the valence electron pairs into a geometric arrangement that minimizes repulsion forces

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

AXE formula

A
A = the central atom
X = the number of atoms bonded to A
E = the number of lone electron pairs around A
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Molecular polarity

A

a molecule is polar when there is an asymmetric distribution of electron density towards the more electronegative atom, resulting in a permanent electrical dipole
this means that one side of the molecule has a partial positive charge, the other a partial negative
this polarity is caused by the asymmetric arrangement of polar covalent bonds
if bonds are nonpolar or polar bonds are symmetrically arranged, no electrical dipole exists and molecule is nonpolar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Valence bond theory

A

proposed that a covalent bond forms when two half-filled valence orbitals from two atoms overlap
the two overlapping orbitals form one bonding orbital = a volume of space between two atomic nuclei in which there is a high probability of finding the now spin paired bonding electrons
electron promotion = amount of energy used to unpair electrons, this increases the number of half-filled valence orbitals that can now bond

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Problems with valence bond theory

A

a good bonding theory will explain bond length, energy, angles, and shape
for most molecules, the VB theory does not match experimental observations
eg. based on VB theory, the water molecule should have a bond angle of 90, however in reality, the bond angle is 104.5

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Linus Pauling and orbital hybridization

A

when bonding, the pure atomic orbitals of the central atom are replaced with new, hybrid orbitals
hybridizing electrons from one s orbital and three p orbitals results in four identical hybrid orbitals called sp3 orbitals that are arranged in a tetrahedral pattern
hybrid orbitals are intermediate in energy to the original pure orbitals

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Sigma bonds

A

a sigma bond is formed when two orbitals overlap in a direct head-to-head fashion
the bonding orbital formed by this overlap lies directly between and in the same plane as the two atomic nuclei
this very effective overlap results in a very strong bond

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Pi bonds

A

pi bonds are formed by the less effective side-by-side overlap of two p orbitals
this results in a bonding orbital forming above and below the plane of the nuclei
this less effective orbital overlap results in the pi bond being weaker than the sigma bond
double bond = one sigma bond and one pi bond
triple bond = one sigma bond and two pi bonds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Orbital hybridization and resonance structures

A
benzene = the unhybridized p orbitals from each carbon will overlap to create one large delocalized pi bonding orbital that forms a donut-like ring above and below the plane of the molecule
carbonate  = the ion’s negative charge is spread out over the entire molecule rather than having it concentrated on one atom due to the delocalized pi bonding orbital that is formed
17
Q

Classifying pure substances

A

can be classified according to = type of particles occupying the lattice points in their crystals, nature of the attraction forces acting between the particles as a solid
nature of the attraction forces between particles is responsible for many of the observed physical properties

18
Q

Molecular solids

A

particles occupying lattice points = neutral molecules
attraction force between particles = Van der Waals forces (London dispersion, Dipole-dipole, Hydrogen bonds)
the covalent bonds do not directly affect the physical properties
eg. propane, acetone

19
Q

London dispersion forces

A

very weak attractive forces that exist between all molecules resulting from the random movement of electrons creating instantaneous dipoles
they are the only VDWF that exist in non-polar molecules
increase in strength as the number of electrons in the molecules increases

20
Q

Dipole-dipole forces

A

attraction forces between the oppositely charged poles of polar molecules
the permanent nature of the dipoles in polar molecules makes dipole-dipole forces much stronger than LDF
dipole-dipole forces increase in strength as the change in electronegativity between the atoms increases

21
Q

Hydrogen bonds

A

form between polar molecules that have OH or NH groups in molecular structures, as well as sometimes HF
exceptionally strong dipole-dipole force (90% of strength) due to the large difference in electronegativity and the small size of the atoms involved
recent research also suggests a slight covalent character to the H-bond which contributes 10% of strength
H-bonds form between the partially positive hydrogen of one atom and the partially negative O or N of another molecule

22
Q

Properties of molecular solids

A

physical state = exists in all three states, depends on strength of VDWF between molecules
MP/BP = low, state change involves overcoming weak VDWF, covalent bonds are not broken
solubility = like dissolves like, since water forms H-bonds, polar compounds that also H-bond will be more soluble than other polar molecules
conductivity = molecules are non-electrolytes, when dissolved in water molecules remain neutral, except for molecules that ionize in water (acids/bases)

23
Q

Ionic solids

A

particles occupying lattice points = positive and negative ions
attraction force between particles = ionic bonds
ionic bond = electrostatic attraction force between oppositely charged ions
results when atoms of lower electronegativity combine with atoms of higher electronegativity
eg. NaCl, HCl

24
Q

Energy associated with ionic bond formation

A

eg. NaCl
energy is used to vapourize sodium
energy is used to break the bonds in a chlorine molecule
ionization energy is used to remove an electron from sodium
energy is released (electron affinity) as the chlorine gains an electron
stable ions come together to form a solid, releasing energy (lattice energy)

25
Q

Factors affecting the strength of ionic bonds

A

lattice energy = the energy released when oppositely charged gaseous ions come together to form a solid ionic crystal
lattice energy is proportional to the strength of ionic bond, so energy equal to the amount of lattice energy must be added to break ionic bonds
factors influence the strength of the bonds = ionic charges (more = more), size (smaller = more)

26
Q

Properties of ionic solids

A

physical state = ionic bonds are strong, localized, and directional making the structure hard, brittle, and solid
MP/BP = are proportional to bond strength, generally have high MP and BP
solubility = ions are attracted to water molecules and form hydration spheres, weaker bonds = more solubility
conductivity = soluble ionic compounds are strong electrolytes, aqueous solutions are conductive as well as liquid, but solids to do not conduct

27
Q

Metallic solids

A

particles occupying lattice points = metal atoms
attraction force between particles = metallic bonds
properties that contribute to metallic bonds = few valence electrons (many empty valence orbitals), low ionization energy (easily lose electrons)
eg. aluminum, iron

28
Q

Electron sea model

A

metallic bonds form when the valence orbitals of all metal atoms overlap to create one large orbital that contains all of the valence electrons
the valence electrons now form one large delocalized electron sea that permeates the entire solid
the metal atoms are now positively charged ions (kernels) suspended in the sea
the bond is the attraction between the kernels and the negative electron sea

29
Q

Factors affecting strength of metallic bonds

A

number of electrons contributed (more electrons = stronger)

positive charge on the metallic kernels (higher charge = stronger)

30
Q

Properties of metallic solids

A

physical state = usually malleable and ductile, bonds are strong but non-directional, layers of atoms are able to slide over and between each other
MP/BP = proportional to bond strength, more electrons = higher MP, transition metals usually have extremely high MP and BP as they can contribute s and d electrons
solubility = insoluble, reactive metals may react with water producing hydrogen gas and a metal hydroxide
conductivity = electrons are not confined to any particular kernel and move free throughout the solid

31
Q

Network solids

A

particles occupying lattice points = nonmetal atoms
attraction force between particles = covalent bonds
nature of covalent bond = simultaneous attraction force of two atomic nuclei on a shared pair of valence electrons, strong and directional bond

32
Q

3D network solid

A

eg. diamond, quartz
each atom uses sp3 hybridization and forms strong sigma bonds to four other atoms
the interlocking network of covalent bonds results in a 3D crystal with a tetrahedral lattice structure

33
Q

2D network solid

A

eg. graphite, mica
in graphene, carbon atoms use sp2 hybridization and form three strong sigma bonds resulting in a covalent network of flat hexagonal rings
each carbon also has an unhybridized p orbital which overlaps with the other p orbitals to form a delocalized pi system above and below the graphene sheet
graphite consists of a stack of graphene sheets held together by weak LDF

34
Q

Properties of network solids

A

physical state = strong directional covalent bonds lead to hard, brittle solids
MP/BP = requires that all of the strong covalent bonds are broken, very high MP and BP
solubility = insoluble in all solvents
conductivity = do not conduct electricity as electrons are localized in strong covalent bonds, except for the delocalized pi system in graphite allowing it to conduct electricity