Unit 1 Flashcards
Same molec
Same T
Different V
VP?
Same VP
Same molec
Diff Temp
VP?
Higher temp -> higher KE -> more molec in gas phase -> higher VP
Which molecule would you expect to have a lower H(l) at room temperature?
A. H2CO
B. CH3OH
Lower H(l) -> most stable -> the one with H bonding
Strong IMF -> most stable -> lowest E and lowest H(l)
Answer: B
Which molecule would you expect to have a lower H(g) at room temperature?
A. H2CO
B. CH3OH
Lower H(g) -> most stable -> IMF
Ideal gas -> no IMF
Answer: same
🔺S equation
🔺S = qrev/T = 🔺H/T
Which molecule would you expect to have a higher S(g) at room temperature?
A. H2CO
B. CH3OH
Higher S(g) -> more molec in gas phase -> weaker IMF Answer: A
🔺G° equation
🔺G° = 🔺H° - T🔺S°
What is 🔺G and 🔺Suniv for a spontaneous process?
Favored
Spontaneous -> 🔺G = negative
🔺Suniv = positive
What is 🔺G and 🔺Suniv for a nonspontenous process?
“Uphill”
🔺G = positive
🔺Suniv = negative
Does breaking IMFs require energy or release energy? Endo or exo? Sign of 🔺H? Examples?
Requires energy
Endo
🔺H = positive
Ex. Vaporization (l -> g), fusion (s -> l), sublimation (s -> g)
Does forming IMFs require energy or release energy? Endo or exo? Sign of 🔺H? Examples?
Releases energy
Exo
🔺H = negative
Ex. Condensation (g -> l), freezing (l -> s), deposition (g -> s)
At equilibrium, 🔺G = ? Greactants = ?
🔺G = 0 Greactants = Gproducts
MP/FP equation
T = 🔺Hfus / 🔺Sfus
Boiling point definition
When VP = the current atmospheric pressure -> liquid boils
Normal boiling point definition
Boiling point at atmospheric pressure (1 atm)
What will be the boiling point of water in Denver? Assume the atmospheric pressure is 0.82 atm.
A. >100 °C
B. <100 °C
C. 100 °C
0.82 atm -> not as many molecules in the gas phase
Patm ⬇️, Tbp⬇️
BP ⬇️
Answer: B
What’s the difference between boiling point and evaporation?
BP specific @ P
Evaporation -> room temp -> min KE needed to break IMF
Partial pressure equation
PV = nRT
* PA = nRT / V *
BP equation
T = 🔺Hvap / 🔺S
Which of the below substances would you expect to have the largest value for 🔺Hvap?
A. Methane
B. Water
C. Acetone
B
Clausius-Clapeyron Equation
ln(P2/P1) = 🔺Hvap/R (1/T1 - 1/T2) 1 molec. 2 temps 🔺Hvap -> J/mol R -> 8.314 J/mol•K T -> K
Warming solid/liquid/gas equation
q = mC🔺T
Comes out in J or kJ
Phase change equation
Melting solid -> q = n🔺Hfus
Boiling liquid -> q = n🔺Hvap
Comes out in J or kJ
For a phase change, we assume that 🔺T=? 🔺G=?
🔺T=0
🔺G=0
Equilibrium
Triple point definition
All 3 phases exist at this T & P
Critical point definition
The T & P limits for gas/liquid phases
Cannot distinguish gas/liquid above critical
If there is a positive slope, can you melt dry ice by applying a higher pressure? Is the solid or liquid more dense?
No
The solid
If there is a negative slope, can you melt ice by applying a higher pressure? Is the solid or liquid more dense?
Yes
The liquid
🔺Hsolution equation
🔺Hsolution = 🔺HLE + 🔺Hsolvation
Is dissolution for a solid solute endothermic or exothermic? Why?
Endothermic 🔺Hsolution = 🔺HLE + 🔺Hsolvation Positive = positive + negative 🔺HLE > 🔺Hsolvation Solute bonds > solvent bonds Ionic/ ion-ion bonds > H bonds
What is the sign of 🔺Ssolution when we dissolve a solid solute in a liquid solvent?
🔺Ssolution = positive
What will happen to a supersaturated aqueous sodium chloride solution when the temperature is increased?
A. No change.
B. The solubility will increase
C. The solubility will decrease
Solid solute ⬆️ T, ⬆️ KE ⬆️ solubility Breaking the solute-solute bonds in the lattice Answer: B