UDEMY

Question 1

@AccessControl.authorizationCheck: #NOT_REQUIRED

DEFINE VIEW ENTITY demo_flight_info_join AS

SELECT FROM scarr AS a
LEFT OUTER JOIN scounter AS b
LEFT OUTER JOIN sairport AS c
ON c.id = b.airport
ON a.carrid = b.carrid
{
a.carrid AS carrier_id,
c.id AS airport_id,
b.countnum AS counter_number
}

choose correct answer

Answer 1

scounter will be joined to sairport first and the result will be joined with scarr.

Question 2

To enhance the existing UI for an SAP Fiori app, Which extensibility type does SAP recommend you use?

Answer 2

Key user

Question 3

Which of the following string functions are predicate functions?

There are 2 correct answers.

Answer 3

• matches()
• contains_any_of()

Question 4

What is true for using the expression itab_1 = corresponding #( itab_2 )? There are 2 correct answers.

Answer 4

• Fields with the same name and the same type will be copied from itab_2 to itab_1.
• itab_1 and itab_2 must have at least one field name in common.

Question 5

What are the advantages of using a field symbol for internal table row access?

There are 2 are answers.

Answer 5

• Using a field symbol is faster than using a work area.
• A MODIFY statement to write changed contents back to the table is not required.

Question 6

Which patterns raise an exception?

There are 3 correct answers.

Answer 6

• DATA: lv_target TYPE p DECIMALS 2.
  CONSTANTS: lc_con TYPE i VALUE 3.

lv_target = EXACT (2 / lc_con).

• DATA: lv_target TYPE d.
  CONSTANTS: lc_date TYPE d VALUE ‘20331233’.

lv_target = EXACT ( lc_date).

• DATA: lv_target TYPE c LENGTH 5.
  CONSTANTS: lc_con TYPE string VALUE “0123456789ABCDEF”.

lv_target = EXACT ( lc_con + 5 (6) ).

Question 7

What are some characteristics of secondary keys for internal tables?

There are 3 correct answers.

Answer 7

• Multiple secondary keys are allowed for any kind of internal table.
• Sorted secondary keys do NOT have to be unique.
• Secondary keys must be chosen explicitly when you actually read from an internal table.

Question 8

Which of the following results in faster access to internal tables?

There are 3 correct answers.

Answer 8

• In a sorted internal table, specifying the primary key partially from the left without gaps.
• In a hashed internal table, specifying the primary key completely.
• In a sorted internal table, specifying the primary key completely.

Question 9

DATA lo_sup TYPE REF TO cl_sup.
DATA lo_sub TYPE REF TO cl_sub.

lo_sub = NEW #( ).
lo_sup = lo_sub.

Here cl_sup is a superclass of cl_sub, when accessing the subclass instance through lo_sup, what can you do?

There are 2 correct answers.

Answer 9

• Call inherited public redefined methods.
• Access the inherited public components.

Question 10

IF <cond>.</cond>

RAISE EXCEPTION TYPE zexptn

EXPORTING
param_1 = value_1
param_2 = value_2
previous = value_3

ENDIF>

Answer 10

• The code creates an exception object and raises an exception.
• zexptn is a dictionary structure, and param1 and param2 are same structure.

Question 11

INTERFACE intf_1.
METHODS m1.
ENDINTERFACE.

CLASS cls_1 DEFINITION.
INTERFACES intf_1
ENDCLASS.

CLASS cls_2 DEFINITION.
DATA: lo_intf TYPE REF TO intf_1.
ENDCLASS.

There are 3 correct answers.

Answer 11

• Class cls_2 uses the interface.
• In class cls_2, the interface method is named lo_intf->m1
• Class cls_1 implements the interface.