TUTORIAL 1 Flashcards
What sort of patient might retinoscopy be useful for?
-Children
-babies
patients with problems with mobility/unable to sit still for long periods
-patients -subjective response
-patients with suspect cataract, keratoconus, tear film issue
-When we want to know about a patients accommodation
-Malingerers/suspect malingeres
What do you think would happen if you did not remove the working distance allowance at the end of retinoscopy?
- Final estimate too positive by +1.50DS*** (assuming WD is 2/3m)
- Patient’s vision will be blurred by this amount
- Remember this is done because you’re working close to patient instead of at infinity (which would be impossible!) – make sure to keep your WD constant
Using the table below, think about what happens to the light from
your retinoscope when your viewing distance or the lens changes? (IN CS BOOK AS EX 2)
- When working distance is 0.66m (2/3) and lens in front of eye is +1.50DS the reflex movement is Neutral- (causes light to converge and focus on back on retina) (3/2= +1.50DS- so we know it will focus on retina hence neutral as know eye is calibrated/emetropic)
- If your WD is 0.66m, and lens in front of eye is +2.00DS the reflex movement is against movement (light focuses in front of retina) - makes eye more myopic than it actually is
- If your WD is 0.3m (1/3) and lens is +2.00DS- as 0.3m is 1/3 which the reciprocal is 3/1= +3.00DS. So we know a +3.00D lens infront of the eye allows light to focus on the retina. A +2.00D lens in front of eye won’t converge light enough to focus on retina instead focuses behind retina. Appears as though eye is hyperopic
What happens if a with movement is seen in one meridian and against in the other ?
- You should neutralise the with movement with a positive Sphere lens
- then neutralise against with a minus cyl lens
What happens if a with movement is seen in both meridians?
You should neutralise the slowest movement first with a sphere lens and against with a minus cyl lens
What happens if no movement is seen in one direction and with in the other?
- Neutralise with movement first with a sph lens and then neutralise against with a minus cyl lens.
- Always neutralise slowest with movement first and that leaves you with an against movement which you then have to neutralise after.
What happens if “against” movement seen in both meridians?
Neutralise the fastest “against” movement first with sph lens
What happens if No movement seen in one direction and “against” in the other?
No sphere lens needed, add –ve cylinder in against meridian
Why do we correct with movement first?
want to correct the most positive meridian first
or if 2 against moments correct the least. negative one.
How to neutralise astigmatic lenses?
-Need to neutralise a with movement first
-then move ret beam to perpendicular axis and neutralise the against
-Add the negative cyl lens on top of spherical lens on dummy lens
-Check for reversal: putting a +/- 0.25 lens to check if changes the movement from with to against and vice versa
-And change the WD. a little bit to see reversal
-Correct WD allowance- remove +1.50 as at 2/3m= 1.50D
so take away 1.50.
What would be the final Rx if we were working at 1/2 metre from the patient? for e.g
- do reciprocal= 2/1= +2.00D
- TAKE AWAY -2.00D from the Sphere lens
What are the common powers?
High powers (dull/no movement) confused with reversal
• Neutralised incorrect meridian first resulting in +ve cyl
• Low cyl powers confused for reversal therefore not corrected
• Cylinder axis off – recheck constantly especially in high powers/changes