Transition Metals Test PRi Flashcards

1
Q

Q1a) Identify a suitable reagent, give the formula for copper containing species and write equation for reaction of [Cu(H2O)6]2+ ⟶ Pale Blue ppt.

A

Reagent – Ammonia
Species – [Cu(H2O)4(OH)2]
Equation – [Cu(H2O)6]2+ + 2NH3 ⟶ [Cu(H2O)3(OH)3] + 2NH4+

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2
Q

Q1b) Reagent, species and equation for Reaction 2

A

Reagent – Ammonia in excess
Species – [Cu(H2O)2(NH3)4]2+
Equation – [Cu(H2O)4(OH)2] + 4NH3 ⟶ [Cu(H2O)2(NH3)4]2+ + 2H2O + 2OH-

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3
Q

Q1c) Reagent, species and equation for Reaction 3

A

Reagent – Na2CO3
Species – [Cu(H2O)6]2+
Equation – [Cu(H2O)6]2+ + CO3(2-) ⟶ CuCO3 + 6H2O

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4
Q

Q1d) Reagent, species and equation for Reaction 4

A

Reagent – HCl (Conc/xs)
Species – [Cu(H2O)6]2+
Equation – [Cu(H2O)6]2+ + 4Cl- ⟶ [CuCl4]2- + 6H2O

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5
Q

Q2a) Explain why the reaction between I- ions and S2O82- ions is slow

A

They are both negatively charged

-ve ions repel one another

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6
Q

Q2b) Other than having variable oxidation states, explain why Fe2+ ions are good catalysts for this reaction

A

Positive ions attract -ve ions in catalysed process

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7
Q

Q2c) Write a half-equation for the reduction of S2O8(2-) ions to SO4(2-) ions

A

S2O8(2-) + 2e- ⟶ 2SO4(2-)

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8
Q

Q2d) Construct an overall equation for the reaction between S2O8(2-) ions and I- ions

A

S2O8(2-) + 2I- ⟶ 2SO4(2-) + I2

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9
Q

Q3a) Calculate the entropy change for the reaction between ammonia and oxygen

A

∆S = S(s products) - Σ(s reactants)

((4x211) + (6x189)) - ((4x193) + (5x205)) = 181 J/K/mol

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10
Q

Q3b) Calculate a value for the Gibbs free-energy change (∆G), in kJ/mol, for the reaction between ammonia and oxygen at 600ºC

A
∆G = ∆H - T∆S 600ºC = 873K
∆G = -905 - 873(181x10-3) = -1063 kJ/mol
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11
Q

Q3c) The reaction between ammonia and oxygen was carried out at a higher temperature.
Explain how this change affects the value of ∆G for this reaction

A

1) ∆G becomes more negative

2) Entropy change/∆S is +ve/T∆S gets bigger

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12
Q

Q3d) Platinum acts as a heterogeneous catalyst in the reaction between ammonia and oxygen. It provides an alternative reaction route with a lower activation energy.
Describe the stages of this alternative route

A

1) Reactants absorbed onto Platinum surface/Pt provides surface/active site
2) Reaction on surface. Bond breaking/forming occurs on surface
3) Desorption of the product or words to that effect (wtte)

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13
Q

Q3e) Deduce the change in oxidation state of Nitrogen, when NH3 is oxidised to NO

A

Oxidation state changes from -3 to +2 (or +5 overall)

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14
Q

Q3f) When ammonia reacts with oxygen, Nitrous Oxide (N2O) can be produced instead of NO
Give an equation for this reaction

A

2NH3 + 2O2 ⟶ N2O + 3H2O

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15
Q

Q4a) Explain, in terms of electrons, why the complexes are different colours. (You are NOT required to explain why the observed colours are red-violet and green)

A

1) In each of P & Q, oxidation state of Cr = +3
2) In each of P & Q, electron config is same/3d3
3) Ligands are different
4) Different energies of electrons/different orbital energies
5) Different wavelengths of light absorbed
6) Different wavelengths of light transmitted/reflected

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16
Q

Q4b) Write an equation to show how the [Co(NH3)6]2+ ion reacts with 1,2-diaminoethane
Explain the thermodynamic reasons why this reaction occurs

A

1) 4 particles form 7 particles
2) Entropy increases
3) ∆H approx. 0/no net change in bond enthalpies
4) ∆G -ve
5) [Co(NH3)6]2+ + 3(NH2CH2CH2NH2) ⟶ [Co(NH2CH2CH2NH2)3]2+ + 6NH3

17
Q

Q4c) i) Draw displayed structure of Cisplatin. Show value of one of the bond angles at Platinum. State the charge if any

A

90º. Charge = 0

18
Q

Q4c) ii) When Cisplatin is ingested, an initial reaction involves one of the Chloride ligands being replaced by water.
Write an equation for this reaction

A

(NH3)2PtCl2 + H2O ⟶ [(NH3)2PtCl(H2O)]+ + Cl

19
Q

Q4c) iii) Suggest how the risk associated with the use of this drug can be minimised

A

Use in small amounts/short bursts/target application/monitor the patients

20
Q

Q4d) Explain, with the aid of equations, how and why Vanadium (V) oxide is used in the Contact Process

A

1) V2O5 + SO2 ⟶ V2O4 + SO3
2) V2O4 + 1/2 O2 ⟶ V2O5
3) Act as a catalyst
4) Speeds up overall reaction b/w SO2 & O2

21
Q

Q5a) Use information to calculate a value for the mass of FeSO4.7H2O in the sample of X
X dissolved in 250cm3 of water
After xs acid added, 25cm3 reacted with 21.3cm3 of 0.015M K2Cr2O7

A

1) Mol of Cr2O7(2-) = (21.3÷1000) x 0.0150 = 3.195x10-4
2) Cr2O7(2-) : Fe2+ = 1:6
3) Mol of Fe2+ = 6 x (3.195x10-4) = 1.917x10-3
4) Original is 250cm3 = (1.917x10-3) x 10 = 1.917x10-2
5) Mass of FeSO4.7H2O = (1.917x10-2) x 277.9 = 5.33g

22
Q

Q5b) Suggest ONE property of an impurity that would cause the calculated mass of FeSO4.7H2O in X to be greater than the actual mass of X.
Explain your answer

A

Impurity is a reducing agent

23
Q

Q6) Which one of the following reactions in aqueous solution has the most +ve change in entropy?
A - hexaaquacopper (II) + Ammonia ⟶ tetraaminodiaquacopper + Water
B - hexaaquacopper (II) + Chloride ⟶ tetrachlorocuprate + water
C - hexaaquacopper (II) + EDTA ⟶ EDTAcuprate + water
D - hexaaquacopper (II) + 1,2-diaminoethane ⟶ [Cu(EDTA)2(H2O2]2+ + Water

A

C – [Cu(H2O)6]2+ + EDTA4- ⟶ [Cu(EDTA)]2- + 6H2O

24
Q
Q7) The Vanadium does NOT have an oxidation state of +3 in:
A - [V(H2O)6]3+
B - [V(C2O4)3]3-
C - [V(OH)3(H2O)3]
D - [VCl4]3-
A

D – [VCl4]3-

25
Q

Q8) Which one of the following would lead to an inaccurate result?
A - Transferring weighed sample of Iron (II) Sulphate into a wet conical flask
B - Failing to measure accurately the volume of water used to dissolve each weighed sample of Iron (II) Sulphate
C - Transferring standard solution of K2Cr2O7 from its original container to burette using a wet beaker
D - Failing to measure accurately the volume of dilute H2SO4 added to the mixture before titration

A

C – Transferring standard solution of K2Cr2O7(2-) from its original container to burette using a wet beaker

26
Q

Q9) Which one of the following would lead to the greatest error in the calculation of the percentage of Iron (II) in the sample?
A - An error of 0.005g made when weighing out a sample of mass 0.987g
B - An end point error of 0.1cm3 in 25cm3
C - Error of 5cm3 when measuring out 25cm3 of dilute H2SO4
D - Using the average of the Titration values 25.4, 25.7 and 25.9 when the correct value is 25.5cm3

A

D – Using the average of the titration values 25.4, 25.7 and 25.9 when the correct value is 25.5cm3

27
Q

Q10)

A

D