Transition metals - catalys Flashcards

1
Q

Define Hetergenous Catalysts

A

when the catalyst is in a different phase to the reactants. they act by proving an alternate pathway with a lower activation emergy. this speeds up rate of reaction and they don’t get used up.

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2
Q

Define Homogenous Catalysts

A

when the catalyst is in the same phase as the reactants. they act by proving an alternate pathway with a lower activation emergy. this speeds up rate of reaction and they don’t get used up.

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3
Q

define catalyts

A

they increase the rate of reaction without getting used up, by providing an alternate pathway with a lower activaton energy. they never get used up and a re-formed at the end. saves time, money and energy so good for the environment.

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4
Q

what states are heterogenous catalysts usually in

A

they are usually in solids, whereas the reactants and products are gasaous or in solution.

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5
Q

what are the steps in hetergenus catalysis.

A
  1. Reactants form bonds with atoms at the active sites on the surface of the catalyst. - they are adsorbed onto the surface. this adsorption leads to catalytic activity.
  2. As a result the bonds in the reactants are weakened/or the bonds being held in a more reactive configuration, resulting in it breaking.
  3. New bonds form between the reactants held close together on the catalysts surface.
  4. This in turn weakens the bonds between product and catalyst and product leaves - the product deabsorbs.
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6
Q

what is used to make the weak bonds on the atoms of the metals with the reactants

A

Transition metals can use the partially filled 3d and 4s electrons to make the weak bond.

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7
Q

what factor increases the rate of reaction at the adsoroption stage.

A

there is a higher concentration of reactans at the surface of the solid catalyst = leading to a higher collision frequency.

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8
Q

what helps determine the effectiveness of catalytic activity.

A

strength of adsorption. some metals have too strong adsorption and rhe producsta can’t be released easily. some metals like Ag have too weak adsorption, and the reactants do not absorb in high enough concentration.

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9
Q

what increases the effectiveness of a solid catalyst

A

increasing the surfae area, this can be done by using a support medium. this maximisies the surface area and minimises the cost, eg - Rh on a ceramic support in catalytic converter.

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10
Q

why are TMs with variable oxidation states good catalysts

A

electrons in the d-orbitals as they are very close to each other and need the same enrgy to reveive and lose them easily, which speeds up reactions.

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11
Q

give examples of heterogenous catalysts and what proces they are used in

A

V2O5/vanadium (V) = in the contact process = making H2SO4
Fe = the Haber process = making ammonia

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12
Q

what are ther two steps to make H2SO4 in the contact process

A
  1. V2O5 oxidises SO2 to SO3
    V2O5 + SO2 -> V2O4 + SO3
  2. V2O4 is oxidised by oxygen in the air and V2O5 is reformed.
    V2O4 + 1/2O2 -> V2O5
    this SO3 is bubbles through water to make H2SO4.
    overall equation =
    SO2 + 1/2O2 __V205___> SO3
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13
Q

Whats a problem with hetergenous catalysts

A

they can get poisoned, this is when the active sites on the catalyst gets blocked by impurities. this reduces the surface area of the catalyst for the reactants to bind to nd slows down the reaction.

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14
Q

give an example where poisoning becomes a problem

A

in the haber process = N2(g) + 3H2(g) ___Fe___> 2NH3 (g)
here the hyfrogen comes from methane. methane contains sulfur impurities. Any sulfur that isnt removed will absorb to the surface of iron and frm iron sulfide which reduces the surface aea and hence reduces the efficiency of iron = recusing the rate.

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15
Q

what effects does a poisoned catalyst have on yeild and cost

A
  • less product made.
  • the catalyst would need to be replaced.
  • and the cost of the chemical process will also increase.
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16
Q

what is the difference in activation energy with homogenous catalysts. and normal catalysts

A

homogenous catalysts energy profiles have 2 activation energy bumpes. the dip in betweeen both is where the intermediates are producesd, these then react to form products . and the catalyst is reformed again.

17
Q

give an example of a proces that uses a homoegenous catalyst

A

oxidation of iodide ions using peroxodisulfate (S2O4^2-), with Fe2+ as a catalyst.
the reaction is very slow to start with as here we are reacting 2 negative ions, so there is very high repulsion. as a result it has high activation energy.
S2O4^2- + 2I2^- –> I2 + 2S2O4^2-

18
Q

explain what happens at the 2 steps of the oxidation of iodide ions using peroxodisulfate (S2O4^2-).

A

Using Fe2+ as a catalyst, lowers the activation energy and speed up the reaction.
1. first the peroxodisulfate (S4O4^2-) is reduced.
S2O4^2-(aq) + 2Fe2+(aq) –> 2Fe3+(aq) + SO4^2-(aq)
- here the Fe2+ is oxidised to Fe3+ and the S2O4^2- is reduced to SO4^2-.
2. the Fe3+ as the intermediate product is then used to form the I2
2Fe3+(aq) + 2I-(aq) -> 2Fe2+(aq) + I2(aq)
- here the Fe3+ ions can also act as the catalyst cos the two steps can occur in any order.

19
Q

what conditions are neccessary for smth to act as a homogenous catalyst

A

it’s electrode potential must lie in between the electrode potentials of the two reactants. it will reduce the more postive elecrtrode potential first and then oxidises the more negative electrode potnetial (NO PRoblem in the order of OILRIG).
- using electrode potential values to find a catalyst only shows that catalysis is possible but it doesnt garantee that the rate of reaction will be increased.

20
Q

Autocatalysis and give an example

A

another form of homogenous catalst where the product acts as the catalyst. eg= where Mn2+ is the catalyst in a reaction between C2O4^2- and MnO4^-
2MnO4^-(aq) + 5C2O4^2-(aq) + 16H+(aq) –> 2Mn^2+(aq) + 10CO2(g) + 8H2O(l)
- this reaction is very slow as we are reacting two negatively chanrged ions, so have a greater activation energy.

21
Q

Describe the steps in reaction where Mn2+ catalyses the reaction between C2O4^2- and MnO4^-

A
  1. 4Mn2+ + MnO4- + 8 H+ -> 5Mn3+ + 4 H2O
    the Mn2+ catalyses the reaction by converting MnO4- into Mn3+
  2. 2Mn3+ + C2O42- –> 2Mn2+ + 2 CO2
    then the Mn3+ formed reacts with C2O42- and Mn2+ ions are reformed.
22
Q

following the rate of an autocatalysis reaction.

A

by removing samples at set times and titrating to work out the concentration of MnO4- .
It could also be done by use of a spectrometer measuring the intensity of the purple colour. This method has the advantage that it does not disrupt the reaction mixture, using up the reactants and it leads to a much quicker determination of concentration.