Transition metals Flashcards

1
Q

what is a transition element

A
  • element that forms at least one stable ion with an incomplete D sublevel
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2
Q

what is a ligand

A
  • a molecule or ion that forms a co-ordinate bond with a transition metal atom or ion
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3
Q

what is a complex

A
  • a central metal atom or ion surrounded by ligands joined by coordinate bonds
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4
Q

what is the coordination number

A
  • the number of coordinate bonds to the central metal atom or ion
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5
Q

what complexes have a linear shape and describe their features

A
  • Ag⁺ complexes only
  • bond angle = 180
  • coordination number of 2
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6
Q

what complexes have a square planar shape and describe their features

A
  • only platinum (Pt²⁺) and nickel(Ni²⁺)
  • bond angle = 90
  • coordination number of 4
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7
Q

what complexes have a tetrahedral shape and describe their features

A
  • when ligands are too big to fit 6 (Cl⁻)
  • bond angle = 109.5
  • coordination number of 4
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8
Q

what complexes have an octahedral shape and describe their features

A
  • most complexes
  • bond angle = 90
  • coordination number of 6
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9
Q

what is a monodentate ligand

A
  • a ligand that forms one coordinate bond to the transition metal ion
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10
Q

why do complexes containing Cl ligands form a different structure than those containing H₂O ligands

A
  • Cl ligands are bigger than ligands and therefore can only fit 4 Cl ligands
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11
Q

what type of isomerism occurs in metal complexes + explain

A
  • Cis-Trans Isomerism
  • Cis = ligands are 90 degrees away
  • Trans = ligands are 180 degrees away
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12
Q

what shape of metal complexes does Cis-Trans isomerism occur in?

A
  • octahedral
  • square planar
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13
Q

what is a bidentate ligand

A
  • ligand which forms two co-ordinate bonds to a metal ion via two different atoms on the same ligand
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14
Q

what are the two bidentate ligands

A
  • 1,2 diaminoethane (H₂NCH₂CH₂NH₂)
  • ethanedioate ions (C₂O₄)²⁻
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15
Q

what type of isomerism occurs in metal complexes containing at least 2 bidentate ligands

A
  • optical isomerism
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16
Q

what is a multidentate ligand

A
  • a ligand that can form 2 or more coordinate bonds to a transition metal ion
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17
Q

what multidentate ligand do we need to know

A
  • (EDTA)⁴⁻
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18
Q

why does EDTA most effective in alkaline conditions

A
  • the OH⁻ reacts with the H⁺ causing equilibrium to shift to the right ensuring the EDTA can form 6 coordinate bonds
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19
Q

what are the uses of EDTA

A
  • used to treat patients with lead poisoning by making the toxic ions present in the body harmless (chelation therapy)
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20
Q

what is Haemoglobin and what does it contain

A
  • its an iron complex that transport oxygen around the body
  • it contains the central iron ion and a multidentate ligand called a porphyrin ring which forms 4 coordinate bonds (haem unit)
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21
Q

describe the structure of haemoglobin in oxygen rich conditions

A
  • each haem unit is bonded to a protein called globin via a lone pair on the nitrogen of the globin
  • 4 coordinate bond from the porphyrin ring to the Fe leaving one more space for oxygen to bind and act as a monodentate ligand via coordinate bonding
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22
Q

why does carbon monoxide prevent the transport of oxygen

A
  • when carbon monoxide is inhaled it forms a coordinate bond with the Fe²⁺ ion in the haem unit blocking the O₂ from binding
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23
Q

where do Cl⁻ ligands come from

A
  • Concentrated HCl
24
Q

what is the chelate effect

A
  • ligand substitution reaction between multidentate ligand and monodentate ligand complexes to form more stable multidentate ligand complexes due to an increase in entropy
25
Q

why does the chelate effect work

A
  • increase in entropy as more moles of products are produced than moles of reactants therefore product is more stable
26
Q

why would the ΔG value for a ligand substitution reaction between ligands that form the same type of coordinate bond always be negative

A
  • increase in entropy as more moles of products are produced than moles of reactants therefore product is more stable
  • enthalpy change will be 0 as the same bonds that are broken are made again
  • since ΔG = ΔH - TΔS , ΔS is positive, ΔH=0, ΔG will be negative
27
Q

describe how to reduce Vanadium (V) to Vanadium (II)

A
  • dissolve NH₄VO₃ in sodium hydroxide solution to ensure VO₂⁺ is the main ion present
  • transfer to a small conical flask and add small amount of zinc powder + HCl
  • put cotton wool in the neck of the flask and swirl contents of the flask together slowly
28
Q

why is cotton wool put in the neck of the conical flask when reducing vanadium ions

A
  • to allow H₂ gas to escape but also minimise the oxidation of the vanadium ions
29
Q

what are the colours of the vanadium ions in their variable oxidation states

A
  • V⁵⁺ (VO₂⁺) - yellow
  • V⁴⁺ (VO²⁺) - blue
  • V³⁺ (V[H₂O]₆)³⁺- green
  • V²⁺ (V[H₂O]₆)²⁺- violet
30
Q

how are vanadium ions reoxidised

A
  • let them stand in air due to the O₂
  • add concentrated nitric acid
31
Q

what causes colour changes of transition metals (3)

A
  • change in oxidation state
  • change in coordination number
  • change in ligand/type of ligand
32
Q

why are transition metals coloured

A
  • d orbitals to split in energy level
  • certain wavelengths of light are absorbed by sample causing electrons to be promoted from ground state to excited state
  • wavelengths of light that aren’t absorbed are transmitted giving off a certain colour
33
Q

equations to calculate energy gap when given frequency of light absorbed

A
  • ΔE = hv
  • energy gap = Planck’s constant x frequency of light absorbed
34
Q

equations to calculate energy gap when not given frequency of light absorbed

A

ΔE = hc/λ
- energy gap = (Planck’s constant x speed of light)/wavelength of light absorbed

35
Q

how would you determine the concentration of a transition metal ion

A
  • add an appropriate ligand to intensify the colour
  • set the colorimeter wavelength to λmax
  • make up standard solutions of known concentrations of the metal ion, some higher and some lower
  • measure absorbance of standard solutions and plot a graph of absorbance value against known concentrations (calibration graph)
  • measure the absorbance of the unknown solution and determine its concentration from the graph
36
Q

how to intensify the colour of a pale complex

A
  • add a suitable ligand to intensify the colour
37
Q

what are Heterogeneous catalysts

A
  • catalysts that are in a different phase to the reactants
  • usually a solid and the reaction takes place on the surface
38
Q

what are some important heterogeneous catalytic processes

A
  • the Haber process - industrial production of Ammonia
  • the Contact process - production of sulfuric acid
39
Q

how do heterogeneous catalysts work

A
  • reactants are adsorbed onto active sites on catalysts surface
  • reaction occurs with lower activation energy as bonds are weakened or new bonds are made between reactants that are being held close together
  • the products are desorbed
40
Q

how is the efficiency of a heterogeneous catalyst maximised

A
  • by using a thin coating of the catalyst on a support medium in order to maximise surface area to save costs
41
Q

what are the equations and catalyst involved in the production of Ammonia

A
  • catalyst = Fe (s)
  • N₂ (g)+ 3H₂ (g) ⇌ 2NH₃ (g)
42
Q

what are the equations and catalysts involved in the contact process

A
  • catalyst = V₂O₅ (s)
  • overall eq = 2SO₂ (g) +O₂ (g) → 2SO₃
  • actual eq = SO₂ + V₂O₅ → V₂O₄ + SO₃
    ½O₂ + V₂O₄ → V₂O₅
43
Q

how can heterogeneous catalysts be poisoned

A
  • impurities adsorb to the surface blocking the active site lowering its efficiency or making it totally ineffective
44
Q

examples of poisoned heterogeneous catalysts

A
  • lead poisoning of catalytic converters in cars
  • the hydrogen in the Haber process is contaminated with sulfur leading to sulfur poisoning
45
Q

what are homogenous catalysts

A
  • catalysts that are in the same phase as the reactants
  • usually in the aqueous state
46
Q

what are some important homogeneous catalytic processes

A
  • reaction between iodide ions (I⁻) and persulfate ions (S₂O₈²⁻) with Fe²⁺/Fe³⁺ as a catalyst
47
Q

why does the reaction between iodide ions (I⁻) and persulfate ions (S₂O₈²⁻) have a high activation energy

A
  • both reactants are negatively charged and therefore repel each other
  • high energy is needed to overcome that repulsion
48
Q

why does the reaction between iodide ions (I⁻) and persulfate ions (S₂O₈²⁻) occur faster with Fe²⁺/Fe³⁺ ions

A
  • opposite charges on the ions attract , therefore lower the activation energy making the reaction faster
49
Q

what is the overall equation involved in the reaction between iodide ions (I⁻) and persulfate ions (S₂O₈²⁻) with Fe²⁺/Fe³⁺ as a catalyst

A

overall : S₂O₈²⁻ + 2I⁻ → 2SO₄²⁻ + I₂

50
Q

what are the actual equations involved in the reaction between iodide ions (I⁻) and persulfate ions (S₂O₈²⁻) with Fe²⁺/Fe³⁺ as a catalyst

A

actual : S₂O₈²⁻ + Fe²⁺ → 2SO₄²⁻ + 2Fe³⁺
2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂

51
Q

what is autocatalysis

A
  • when one of the products from a reaction is a catalyst for the reaction
52
Q

what is an example of autocatalysis

A
  • the reaction between ethanedioate ions (C₂O₄²⁻) and manganate ions (MnO₄⁻) with Mn²⁺ catalyst
53
Q

what is the source of ethanedioate ions

A
  • ethanedioic acid
54
Q

what is the overall equation involved in the reaction between ethanedioate ions (C₂O₄²⁻) and manganate ions (MnO₄⁻)

A

5C₂O₄²⁻ + 2MnO₄⁻ + 16H⁺ → 2Mn²⁺ + 10CO₂ +8H₂O

55
Q

what are the actual equations involved in the reaction between ethanedioate ions (C₂O₄²⁻) and manganate ions (MnO₄⁻)

A

step 1: 8H⁺ + MnO₄⁻ + 4Mn²⁺ → 5Mn³⁺ + 4H₂O
step 2: 2Mn³⁺ + C₂O₄²⁻ → 2CO₂ + 2Mn²⁺

56
Q

why does the rate of autocatalysed reactions change over time

A
  • reaction is slow at first until some of the catalyst is formed
  • after a substantial amount of catalyst is formed the rate of reaction increases until the reactant runs out