Transition Metals Flashcards
colour of chromium
bluish white metal
write interconvertble reaction between chromate and dichromate
CrO4 2- + H+ —> Cr2O7 2- + H2O
yellow chromate orange dichromate
toxic side effects of chromate VI
- cancer in oral cavity/ small intestine
- kidney failure
- ulcers in the stomach
- damage to blood cells by causing haemolysis
- toxicity in the liver
physical property of manganese
hard silver white metal
reaction of heating of KMnO4
2KMnO4 –> K2MnO4 +MnO2 +O2
potassium manganage VII reduction in alkaline solution
MnO4- + 2H2O + 3e- —-> MnO2 + 4OH-
forms manganese IV oxide, a black precipitate/brown pp
potassium manganate VII reduction in acidic solution
MnO4- +8H+ +5e- —-> Mn2+ +4H2O
purple soln to a colourless solution of manganese II
can KMnO4 be used to analyse solutions containing Cl- ions, or acidified using HCl?
no because it is a stronger oxisidisng agent than potasium dichromate and will oxidise Cl- to Cl2
when is alkaline potassium manganate VII utilised?
to oxidize alkenes to diols
explain the non existence of Iron III Iodide
down group 7, the oxidising power decreases allowing for I- to be a great reducing agent that wants to be oxidized to I2, whilst reducing Fe3+ to Fe2+
explain the non existence of Fe III carbonate
in aq environemnets, iron III is bound to ligands as [Fe(H2O)6]3+. due to strong interactions the omplex can hydrolyse to liberate H+. carbonate is abase and captures H+. thisfurther facilitates the formation of hydroxyl complexes so much that it will produce H2CO3 and Fe(OH)3. H2CO3 will decompose into water and CO2.
as a solid it is hygroscopic and therefore absorb water. the above iwll then take place.
in what 3 forms does iron occur?
-haematite- Fe2O3
magnetite Fe3O4
carbonate FeCO3
acidity of IronIII and Iron II
iron IIIcomplex is hydrolysed to libertae 3 protons while iron II can liberate 2. Iron III is more acidic.
test for Iron III ions
addition of potasium thiocyanate . colour change from yellow to deep red .
[Fe(H2O)6]3+ + SCN- —> [Fe(H2O)5SCN]2+ +H2O
formation of Cu2O as seen in fehlings test
Cu2O (reddish brown) is made by the reduction of alkaline CuII solution. reducing agents like aldehydes and reducing sugars will reduce Cu2+ (blue) ion to Cu2O.
2Cu2+ +2OH- +2e- —> Cu2O +H2O
test for reducing sugars and aldehydes.