Transcription Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

Transcription

A
  • Process in which nucleotide sequence of gene is used as a template to direct synthesis of RNA made up of complementary base sequences
  • DNA molecules too large to move through nuclear pores in nuclear envelope → info on DNA transcribed into smaller mRNA
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Gene

A
  • Specific sequence of nucleotides in a DNA molecule which codes for a specific sequence of amino acids in one polypeptide chain
  • Located in fixed position (locus) on chromosome
  • Specifies a particular biological function → phenotype
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Components of a gene (3)

A
  1. Promoters → recognition site for binding of RNA polymerase and regulatory proteins (general transcription factors) → initiate transcription
  2. Termination sequence
  3. Transcription unit → template and non-template strand
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Key features of transcription (5)

A
  1. Formation of single-stranded RNA
  2. Synthesis in 5’ to 3’ direction
  3. Catalysed by RNA polymerase (multimeric complex) → assembly of ribonucleotides and formation of phosphodiester bonds
  4. Complementary base pairing
  5. Recognition sequences → begins at promoter, ends at termination sequence
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

DNA strands (2)

A
  1. Template = non-coding = antisense

2. Non-template = coding = sense

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Transcription steps (3)

A
  1. Initiation
  2. Elongation
  3. Termination
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q
  1. Initiation (Eukaryotes) (3)
A
  1. General transcription factors first assemble along
    the promoter at TATA box, before recruiting RNA polymerase & positioning it correctly on the promoter, forming transcription initiation complex.
  2. RNA polymerase unzips the 2 strands of the DNA double helix by breaking H bonds between complementary base pairs
  3. Only one strand is used as the template to synthesise
    mRNA.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q
  1. Initiation (Prokaryotes) (4)
A
  1. Sigma factor associates with core RNA polymerase forming the RNA polymerase holoenzyme
  2. As the holoenzyme scans along the DNA, its sigma factor recognises and binds to the promoter.
  3. RNA polymerase unzips the 2 strands of the DNA double helix at promoter by breaking H bonds between complementary base pairs
  4. Only one strand is used as a template to synthesise mRNA.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q
  1. Elongation (Eukaryotes and prokaryotes) (5)
A
  1. Free ribonucleotides bind to template DNA strand by complementary base pairing.
  2. A forms 2 H bonds with U, T forms 2 H bonds with A, C forms 3 H bonds with G*
  3. RNA polymerase catalyses formation of phosphodiester bonds between adjacent ribonucleotides to form sugar phosphate backbone
  4. mRNA strand synthesised and elongated in the 5’ to 3’ direction
  5. As the RNA polymerase continues to move down the template strand, the region of DNA that has just been transcribed reanneals.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q
  1. Termination (Eukaryotes) (2)
A
  1. RNA polymerase transcribes a (termination) sequence on the DNA, which codes for a polyadenylation signal (AAUAAA) in the pre-mRNA.
  2. Proteins (endonucleases) bind at a point (10 to 35 nucleotides) downstream of the polyadenylation signal to cut and free the pre-mRNA from the polymerase.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q
  1. Termination (Prokaryotes) (2)
A
  1. After transcribing through a termination sequence the transcribed terminator folds back to form a hairpin loop
  2. The loop acts as a termination signal that causes the mRNA and RNA polymerase to be released
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Post-transcriptional modification (Eukaryotes) (3)

A
  1. Addition of methylguanosine cap to 5’ end of pre-mRNA
  2. RNA Splicing
  3. Synthesis of poly A tail (polyadenylation)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q
  1. Addition of methylguanosine cap to 5’ end of pre-mRNA (3)
A
  1. 5’ cap protects mRNA from degradation by ribonucleases that degrade RNA form the 5’end
  2. Serves as a recognition signal for the small ribosomal subunit to assemble & begin translation
  3. Facilitates the export of mature mRNA from the nucleus
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q
  1. RNA Splicing
A
  • Requires ATP

- Spliceosomes excise introns (non-coding seq) & join exons (coding seq)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q
  1. Synthesis of poly A tail (polyadenylation) (3)
A
  1. Enzyme poly A polymerase which adds adenine nucleotides downstream of polyadenylation sequence, AAUAAA.
  2. Protects mRNA from degradation by ribonucleases → more stable template for translation
  3. Directs the export of mRNA through nuclear pores into the cytoplasm
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Types of RNA (3)

A
  1. Messenger RNA (mRNA)
  2. Ribosomal RNA (rRNA)
  3. Transfer RNA (tRNA)
17
Q

Messenger RNA

A
  • Single stranded
  • Protein-coding region + untranslated regions
  • UTR includes 5’ cap and poly-A tail
18
Q

Role of mRNA (3)

A
  1. Serves as a messenger that takes info out of nucleus via nuclear pore to cytoplasm where translation takes place
  2. Acts as template for translation
  3. Each codon within coding region of mRNA represents an amino acid in a polypeptide → sequence of codons determines polypeptide sequence