Topic 7 - inheritance population evolution and ecosystems Flashcards
What is the genotype?
The genetic constitution of an organism
What is the phenotype?
The expression of the genes and its interaction with the environment
What is homozygous?
A pair of homologous chromosomes carrying the same alleles for a single gene.
What is heterozygous?
A pair of homologous chromosomes carrying two different alleles for a single gene.
What is a recessive allele?
An allele only expressed if no dominant allele is present.
What is the dominant allele?
An allele that will always be expressed in the phenotype.
What is meant by codominant?
Both alleles are equally dominant and expressed in the phenotype
What is meant by multiple alleles?
More than two alleles for a single gene
What is sex linkage?
A gene whose locus is on the X chromosome.
What is autosomal linkage?
Genes that are located on the same chromosome
What is epistasis?
When one gene modifies or masks the expression of a different gene at the different locus.
What is meant by monohybrid?
Genetic inheritance cross of a characteristic determined by one gene.
What is meant by dihybrid?
Genetic inheritance cross for a characteristic determined by two genes.
The type of inheritance is monohybrid what is the genetic diagram coding?
Single letter capital or lowercase for dominant or recessive.
The type of inheritance is codominant what is the genetic diagram coding?
Gene*allele
Multiple alleles is the title inheritance. What is the genetic diagram coding?
Gene*allele
Sex linkage is the type of inheritance. What is the genetic diagram coding?
Chromosome*allele
The type of inheritance is autosomal linkage. What is the genetic diagram coding?
Example: Aa Bb
Epistasis is the type of inheritance. What is the genetic diagram coding?
Example: EE Bb
Monohybrid inheritance: cystic fibrosis is caused by a recessive allele. If two carriers reproduce what is the probability they will have a child with cystic fibrosis? What is the probability they will have a girl with cystic fibrosis? (Parental genotypes = Ff x Ff
Punnet square of parental genotypes: creates FF, Ff, Ff, ff.
25% probability that the child will have cystic fibrosis.
50% (chance of having a girl) x 25% (probability of having cystic fibrosis) = 12.5%.
Codominant inheritance: cows can be red, white or roan in colour; red and white are both dominant. If two roan cows reproduce what is the probability they will produce red offspring?
Parental genotypes = CRCW(roan) x CRCW(roan)
Punnet Square = CRCW (roan), CRCR (red), CWCW (white), CRCW (roan)
25% probability of getting a red cow.
Multiple alleles: parents with blood group AB and blood group O reproduce. IA and IB codominant and IO is recessive. What is the probability they will have an offspring with a blood group A?
Parental genotypes = IAIB x IOI*O
Create the punnet square = IBIO (blood group B), IAIO (blood group A), IAIO (blood group A), IBIO (blood group B).
50% chance of the offspring having blood group A.
Sex linkage = colour blindness is caused by recessive allele found on the X chromosome. If a non-colourblind male we produces with a female carrier of the allele, what is the probability their children will be colourblind?
Workout parental genotypes = XRXr and XrY.
Do the punnet square = XRXr (normal vision), XRXRXR (normal vision), XrY (colour blind), X*RY (normal vision).
The probability of the child having colour blindness is 25% .
Epistasis:
Gene 1: controls whether pigment will be expressed.
Allele E: dominant and codes for pigment production
Allele e: recessive and codes for no pigment production.
Gene 2: controls which pigment is expressed (if pigment is being expressed)
Allele B: dominant and codes for black fur
Allele b: recessive and codes for brown fur
Parental genotypes = Ee Bb x Ee E Bb
Parental phenotypes: both black ( EB Eb eB eb x EB Eb eB eb).
Do a punnet square and work out all the possible combinations: EEBB (black), EEBb(black), EeBB(black), EeBb(black), EEBb(black), EeBB(black), EeBb(black), EeBb(black), EeBb(black), Eebb(brown), Eebb(brown), Eebb(brown), eeBB(yellow), eeBb(yellow), eeBb(yellow), eebb(yellow), The ratios of the genotype should be 9:3:3:1.