Topic 7: Equilibrium Flashcards

1
Q

reversible rxn

A

rxn in which products can react with one another under suitable conditions to produce rxns

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2
Q

dynamic equilibrium

A
  • conc. of reactants and products don’t change over time
  • backward & forward rxns are occurring simultaneously
  • with the rate of both reactions equal
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3
Q

physical equilibrium

A

equilibrium set up in physical processes

e.g. melting of solids, evaporation of bromine

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4
Q

chemical equilibrium

A

equilibrium set up in chemical processes

e.g. decomposition of CaCO3

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5
Q

what happens when bromine is placed in a sealed container at room temp?

A
  • bromine is a volatile liquid with a boiling point close to room temp
  • significant number of particles will have enough energy to evaporate
  • concentration of bromine vapour increases in the closed system
  • as the vapour can’t escape, many of its particles will condense back
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6
Q

equilibrium law

A

at a given temp, the ratio of conc of products (raised to the power of molar coefficients) to conc of reactants (raised to the power of molar coefficients) is a constant

this constant is called Kc

NOTE: in aqueous rxns, the conc of the solvent won’t appear in the equilibrium constant expression as its conc won’t change

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7
Q

Meaning of Kc’s value

A
  • if Kc > 0 at a given temp, products are favoured over reactions
  • if Kc
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8
Q

situation where Kc won’t apply

A

non-reversible rxns

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9
Q

Reaction quotient

A
  • denoted by Q
  • measures relative amount of reactants & products during a rxn at a particular point in time
  • helps in figuring out which direction a rxn is likely to proceed using pressure/conc of reactants
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10
Q

difference between Kc and Q

A

Kc: describes rxn at equilibrium
Q: describes rxn not at equilibrium

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11
Q

Meaning of Q’s value

A
  • if Kc > Q: rxn is in favour of products (forward)
  • if Kc = Q: equilibrium
  • if Kc
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12
Q

effect of inverting the rxn on Kc

A

inverts the value of Kc

1/Kc

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13
Q

effect of doubling rxn coefficients on Kc

A

square the expression Kc

Kc^2

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14
Q

effect of halving reaction coefficients

A

square root of Kc

Kc^(1/2)

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15
Q

effect of adding together 2 rxns on Kc

A

multiply the 2 Kc values

Kc1 x Kc2

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16
Q

Le Chatelier’s principle

A

a system of equilibrium, when subjected to change, will respond to minimise the effect of the change

17
Q

Factors affecting equilibrium

A
  • concentration
  • pressure
  • change in temp
  • catalyst
18
Q

Factors affecting equilibrium: concentration

A
  • increase in product conc: backwards reaction favoured
  • decrease in product conc: forwards reaction favoured
  • increase in reactant conc: forwards reaction favoured
  • decrease in reactant conc: backwards reaction favoured
19
Q

factors affecting equilibrium: pressure

A
  • increase in pressure = shift towards side with less no of moles
  • decrease in pressure = shift towards side with higher no of moles
20
Q

factors affecting equilibrium: change in temp

A
  • increase in temp = shift to endothermic side (ΔH = +tive)
  • decrease in temp = shift to exothermic side (ΔH = -tive)
  • due to temp having diff effects on forward/backward rxns due to diff activation energies
21
Q

factors affecting equilibrium: catalyst

A
  • catalysts have no overall effect on equilibrium position

- it only speeds up the attainment of equilibrium

22
Q

Haber’s Process

A

N2 (g) + 3H2 (g) 2NH3 (g) [ΔH = -93 kJ/mol]

23
Q

conditions for Haber’s process, Contact process, methanol production

A

Favourable:

  • low temp
  • high pressure

Actual:
- moderate conditions
450 degrees and 200 atm

24
Q

Why are moderate conditions taken instead of favourable conditions?

A

low temp = slow rate of rxn = more time taken to produce yield = inefficient

high pressure = risk of explosion = costly to rebuild infrastructure

25
Q

Contact process

A
  1. Combustion of sulphur-containing compounds
    S(s) + O2 (g) -> SO2 (g)
  2. Oxidation of SO2 to SO3
    2SO2 (g) + O2 2SO3 (g) [ΔH = -196 kJ/mol]
    catalyst: vanadium (V) oxide
  3. SO3 + H2SO3 (concentrated) -> H2S2O7 (oleum)
    H2S2O7 + H2O -> H2SO4

Alternatively,
SO3 + H2O -> H2SO4
But it’s highly exothermic and produces corrosive mist so it’s generally not used.

26
Q

Production of Methanol

A

CO (g) + 2H2 (g) CH3OH (g) [ΔH = -90 kJ/mol]

- catalyst: Al2O3 OR CuO3 OR ZnO3