Topic 3 - Redox I Flashcards

1
Q

What is meant by the term oxidation number?

A

The number of electrons that have been taken or gained from an element.

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2
Q

How do you calculate the oxidation number of elements in compounds & ions.

A
  • Gp 1 metals = +1
  • Gp 2 metals = +2
  • Al = +3
  • H = +1 (except in hydrides = -1 NaH)
  • F = -1
  • Cl, Br, I = -1 (except w/ O or F)
  • O = -2 (except in peroxides H₂O₂ & w/ F = -1
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3
Q

What is oxidation & reduction?

A

Oxidation is the loss of electrons or ↑ in ox number

Reduction is the gain off electrons or ↓ in ox number

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4
Q

What are oxidising & reducing agents?

A

Ox agents are electron acceptors (gain e⁻) & are reduced in the reaction
Red agents are electron donors (loose e⁻) & are oxidised in the reaction

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5
Q

What is a disproportionation reaction?

A

When an element in a single species is simultaneously oxidised & reduced.

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6
Q

How can ox no. be used to classify between redox & disproportionation reactions?

A

If the ox no of an element is both oxidised & reduced, the reaction is disproportionate, if not then it’s redox.

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7
Q

How do you classify the ox no of an element in a compound or ion?

A

By using roman numerals. (I, II, III, IV, V, VI…)

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8
Q

How do you write formula given the ox no?

A

If you know the ox no you can figure out the ration of the elements need in the compound.

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9
Q

What ions do metals form?

A

(+ve) ions by loss of e⁻ with an ↑ in ox no

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10
Q

What ions do non metals form?

A

(-ve) ions by gain of e⁻ with a ↓ in ox no

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11
Q

How do you write ionic half equations?

A

-work out ox no
-add electrons to equal change in ox no (red = e⁻ to L/ ox = e⁻ to R)
-make sure sum of charges is equal on both sides
(if has O, balance by adding H⁺/H₂O in acidic conditions or OH⁻)

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12
Q

How do you combine half equations?

A
  • multiply them to get equal no of electrons

- add them together & cancel electrons (balance H⁺ too)

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