Topic 3: Redox Flashcards
define Oxidation number
the oxidation number of an atom shows the number of electrons which it has lost or gained as a result of forming a compound.
what formula will the chlorate (V) ion have
ClO₃⁻. in anions that end in -ate the quantity of oxygen will b the umber of combined oxygen atoms to give the anion the smallest negative charge
Do oxidising agents gain or lose electrons
oxidising agents gain electrons.
oxidising agent is reduced.
Do reducing agents gain or lose electrons
reducing agents lose electrons.
reducing agent is oxidised
what is a disproportionation reaction
when a species undergoes simultaneous oxidation and reduction
steps to write a half equation:
balance for key atoms
balance for electrons
balance for hydrogen and oxygen by adding H⁺ and H₂O (acidic conditions)
H₂O and OH⁻ (alkali conditions)
write the half equation of the conversion of hydrogen peroxide, H₂O₂, to oxygen, O₂
H₂O₂ -> O₂ + 2H⁺ + 2e⁻
find the formula of chromate (VI)
CrO₄^2-
The chlorate(V) anion has the formula ClO₃⁻.
write the formula of the following ions:
a) Chlorate (I)
b) Chlorate(VII)
C) Name the compound whose formula is Ba(ClO₂)₂
a) Chlorate (I) ClO⁻
b) Chlorate (VII) ClO₄⁻
c) Barium Chlorate (III)
assign the oxidation numbers of oxygen in the following potassium oxides
a) Potassium peroxide (K₂O₂)
b) Potassium superoxide (KO₂)
a) -1
b) -0.5
- Iron(II) can be oxidised by some substances, including bromine, to iron(III) according to the following half-equation: Fe2+ → Fe3+ + e—
a. Write a half-equation representing what happens to bromine (Br2) when it is used to oxidise iron(II). [2]
b. Combine both half-equations to form a chemical equation for the oxidation of iron(II) by bromine. [2]
c. Identify, giving a reason, the following species in the reaction:
i. The reducing agent. [2]
ii. The species whose oxidation number decreases. [2]
d. Iron(III) can be reduced back to iron(II) by iodide ions. Use appropriate half-equations to create a chemical equation for this redox reaction. [4]
- a. Br2 + 2e— → 2Br— Br2 and 2Br— [1] 2e— [1].
b. 2Fe2+ + Br2 → 2Fe3+ + 2Br— 2Fe2+ and 2Fe3+ [1] Br2 and 2Br— [1]
c.
i. Fe2+ / iron(II) [1] Loses electrons / increases oxidation number / gives electrons away [1]
ii. Br2 / bromine [1] Oxidation number changes from 0 to -1 [1]
d. 2Fe3+ + 2I— → 2Fe2+ + I2 Fe half-equation: Fe3+ + e— → Fe2+ [1] I— half-equation: 2I— → I2 + 2e— [1] Doubling of Fe half-equation for equal electrons on both sides [1] Correct addition of half-equations [1]
in this reaction;
Cl2+ 2Br-→2Cl-+ Br2
what safety precautions should be taken
An answer that makes reference to the following points:
chlorine/bromine toxic/poisonous
(Carry out the experiment in a) fume cupboard
OR
bromine corrosive
wear gloves