Topic 3 Flashcards

Organisms exchange substances with their environment

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1
Q

Describe the relationship between the size and structure of an organism and
its surface area to volume ratio (SA:V)

A

● As size increases, SA:V tends to decrease
● More thin / flat / folded / elongated structures increase
SA:V

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2
Q

How is SA:V calculated?

A

Divide surface area (size length x side width x number of sides) by volume (length x width x depth

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3
Q

Suggest an advantage of calculating SA:mass for organisms instead of SA:V

A

Easier / quicker to find / more accurate because irregular shapes

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4
Q

What is metabolic rate?

A

● Metabolic rate = amount of energy used up by an organism within a given period of time
● Often measured by oxygen uptake → as used in aerobic respiration to make ATP for energy release

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5
Q

Explain the relationship between SA:V and metabolic rate

A

As SA:V increases (smaller organisms), metabolic rate increases because:
● Rate of heat loss per unit body mass increases
● So organisms need a higher rate of respiration
● To release enough heat to maintain a constant body temperature ie. replace lost heat

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6
Q

Explain the adaptations that facilitate exchange as SA:V reduces in larger
organisms

A
  1. Changes to body shape (eg. long / thin)
    ● Increases SA:V and overcomes (reduces) long diffusion distance /
    pathway
  2. Development of systems, such as a specialised surface / organ for gaseous exchange e.g. lungs:
    ● Increases (internal) SA:V and overcomes (reduces) long diffusion distance / pathway
    ● Maintain a concentration gradient for diffusion eg. by ventilation / good blood supply
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7
Q

Explain how the body surface of a single-celled organism is adapted for gas
exchange

A

● Thin, flat shape and large surface area to volume ratio
● Short diffusion distance to all parts of cell → rapid diffusion eg. of O2 / CO2

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8
Q

Describe the tracheal system of an insect

A
  1. Spiracles = pores on surface that can open / close to allow diffusion
  2. Tracheae = large tubes full of air that allow diffusion
  3. Tracheoles = smaller branches from tracheae, permeable to allow gas exchange with cells
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9
Q

Explain how an insect’s tracheal system is adapted for gas exchange

A

● Tracheoles have thin walls
○ So short diffusion distance to cells

● High numbers of highly branched tracheoles
○ So short diffusion distance to cells
○ So large surface area

● Tracheae provide tubes full of air
○ So fast diffusion

● Contraction of abdominal muscles (abdominal
pumping) changes pressure in body, causing air to
move in / out
○ Maintains concentration gradient for diffusion

● Fluid in end of tracheoles drawn into tissues by
osmosis during exercise (lactate produced in
anaerobic respiration lowers ψ of cells)
○ Diffusion is faster through air (rather than
fluid) to gas exchange surface

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10
Q

Explain structural and functional compromises in terrestrial insects that
allow efficient gas exchange while limiting water loss

A

● Thick waxy cuticle / exoskeleton → Increases diffusion distance so less water loss (evaporation)

● Spiracles can open to allow gas exchange AND close to reduce water loss (evaporation)

● Hairs around spiracles → trap moist air, reducing ψ gradient so less water loss (evaporation)

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11
Q

Explain how the gills of fish are adapted for gas exchange

A

● Gills made of many filaments covered with many lamellae
○ Increase surface area for diffusion

● Thin lamellae wall / epithelium
○ So short diffusion distance between water / blood

● Lamellae have a large number of capillaries
○ Remove O2 and bring CO2 quickly so maintains
concentration gradient

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12
Q

what is the Counter current flow?

A
  1. Blood and water flow in opposite directions through/over lamellae
  2. So oxygen concentration always higher in water (than blood near)
  3. So maintains a concentration gradient of O2 between water and blood
  4. For diffusion along whole length of lamellae
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13
Q

Explain how the leaves of dicotyledonous plants are adapted for gas
exchange

A

● Many stomata (high density) → large surface area for gas exchange (when opened by guard cells)

● Spongy mesophyll contains air spaces → large surface area for gases to diffuse through

● Thin → short diffusion distance

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14
Q

Explain structural and functional compromises in xerophytic plants that
allow efficient gas exchange while limiting water loss

A

Xerophyte = plant adapted to live in very dry conditions eg. Cacti and marram grass

● Thicker waxy cuticle
○ Increases diffusion distance so less evaporation

● Sunken stomata in pits / rolled leaves / hairs
○ ‘Trap’ water vapour / protect stomata from wind
○ So reduced water potential gradient between leaf / air
○ So less evaporation

● Spines / needles
○ Reduces surface area to volume ratio

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15
Q

Describe the gross structure of the human gas exchange system

A

Trachea
Bronchi
Bronchioles
Capillary network (surrounding alveoli)
Alveoli (air sacs)

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16
Q

Explain the essential features of the alveolar epithelium that make it
adapted as a surface for gas exchange

A

● Flattened cells / 1 cell thick → short diffusion distance

● Folded → large surface area

● Permeable → allows diffusion of O2 / CO2

● Moist → gases can dissolve for diffusion

● Good blood supply from large network of capillaries →
maintains concentration gradient

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17
Q

Describe how gas exchange occurs in the lungs

A

● Oxygen diffuses from alveolar air space into blood down its concentration gradient
● Across alveolar epithelium then across capillary endothelium

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18
Q

Explain the importance of ventilation

A

● Brings in air containing higher conc. of oxygen & removes air with lower conc. of oxygen
● Maintaining concentration gradients

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19
Q

Explain how humans breathe in and out (Inspiration)

A
  1. Diaphragm muscles contract → flattens
  2. External intercostal muscles contract, internal
    intercostal muscles relax (antagonistic) →
    ribcage pulled up / out
  3. Increasing volume and decreasing pressure
    (below atmospheric) in thoracic cavity
  4. Air moves into lungs down pressure gradient
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20
Q

Explain how humans breathe in and out
(expiration)

A
  1. Diaphragm relaxes → moves upwards
  2. External intercostal muscles relax, internal
    intercostal muscles may contract → ribcage
    moves down / in
  3. Decreasing volume and increasing pressure
    (above atmospheric) in thoracic cavity
  4. Air moves out of lungs down pressure gradient
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21
Q

Suggest why expiration is normally passive at rest

A

● Internal intercostal muscles do not normally need to contract
● Expiration aided by elastic recoil in alveoli

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22
Q

Suggest how different lung diseases reduce the rate of gas exchange

A

● Thickened alveolar tissue (eg. fibrosis) → increases diffusion distance
● Alveolar wall breakdown → reduces surface area
● Reduce lung elasticity → lungs expand / recoil less → reduces concentration gradients of O2 / CO2

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23
Q

Suggest how different lung diseases affect ventilation

A

● Reduce lung elasticity (eg. fibrosis - build-up of scar tissue) → lungs expand / recoil less
○ Reducing volume of air in each breath (tidal volume)
○ Reducing maximum volume of air breathed out in one breath (forced vital capacity)
● Narrow airways / reduce airflow in & out of lungs (eg. asthma - inflamed bronchi)
○ Reducing maximum volume of air breathed out in 1 second (forced expiratory volume)
● Reduced rate of gas exchange → increased ventilation rate to compensate for reduced oxygen in blood

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24
Q

Suggest why people with lung disease experience fatigue

A

Cells receive less oxygen → rate of aerobic respiration reduced → less ATP made

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25
Q

Suggest how you can analyse and interpret data to the effects of pollution,
smoking and other risk factors on the incidence of lung disease

A

● Describe overall trend → eg. positive / negative correlation between risk factor and incidence of disease
● Manipulate data → eg. calculate percentage change
● Interpret standard deviations → overlap suggests differences in means are likely to be due to chance
● Use statistical tests → identify whether difference / correlation is significant or due to chance
○ Correlation coefficient → examining an association between 2 sets of data
○ Student’s t test → comparing means of 2 sets of data
○ Chi-squared test → for categorical data

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26
Q

Suggest how you can evaluate the way in which experimental data led to
statutory restrictions on the sources of risk factors

A

● Analyse and interpret data as above and identify what does and doesn’t support statement
● Evaluate method of collecting data
○ Sample size → large enough to be representative of population?
○ Participant diversity eg. age, sex, ethnicity and health status → representative of population?
○ Control groups → used to enable comparison?
○ Control variables eg. health, previous medications → valid?
○ Duration of study → long enough to show long-term effects?
● Evaluate context → has a broad generalisation been made from a specific set of data?
● Other risk factors that could have affected results?

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27
Q

Explain the difference between correlations and causal relationships

A

● Correlation = change in one variable reflected by a change in another - identified on a scatter diagram
● Causation = change in one variable causes a change in another variable
● Correlation does not mean causation → may be other factors involved

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28
Q

Explain what happens in digestion

A

● Large (insoluble) biological molecules hydrolysed to smaller (soluble) molecules
● That are small enough be absorbed across cell membranes into blood

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29
Q

Describe the digestion of starch in mammals

A

● Amylase (produced by salivary glands / pancreas) hydrolyses starch to maltose
● Membrane-bound maltase (attached to cells lining ileum) hydrolyses maltose to glucose
● Hydrolysis of glycosidic bond

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30
Q

Describe the digestion of disaccharides in mammals

A

● Membrane-bound disaccharidases hydrolyse disaccharides to 2 monosaccharides:
○ Maltase - maltose → glucose + glucose
○ Sucrase - sucrose → fructose + glucose
○ Lactase - lactose → galactose + glucose
● Hydrolysis of glycosidic bond

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31
Q

Describe the digestion of lipids in mammals, including action of bile salts

A

● Bile salts (produced by liver) emulsify lipids causing them to form smaller lipid droplets
● This increases surface area of lipids for increased / faster lipase activity
● Lipase (made in pancreas) hydrolyses lipids (eg. triglycerides) → monoglycerides + fatty acids
● Hydrolysis of ester bond

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32
Q

Describe the digestion of proteins by a mammal

A

● Endopeptidases - hydrolyse internal (peptide) bonds
within a polypeptide → smaller peptides
○ So more ends / surface area for exopeptidases
● Exopeptidases - hydrolyse terminal (peptide) bonds at
ends of polypeptide → single amino acids
● Membrane-bound dipeptidases - hydrolyse (peptide)
bond between a dipeptide → 2 amino acids
● Hydrolysis of peptide bond

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33
Q

Suggest why membrane-bound enzymes are important in digestion

A

● Membrane-bound enzymes are located on cell membranes of epithelial cells lining ileum
● (By hydrolysing molecules at the site of absorption they) maintain concentration gradients for absorption

34
Q

Describe the pathway for absorption of products of digestion in mammals

A

Lumen (inside) of ileum → cells lining ileum (part of small intestine) → blood

35
Q

Describe the absorption of amino acids and monosaccharides in mammals

A

1 ● Na
+ actively transported from
epithelial cells lining ileum to
blood (by Na
+
/K
+ pump)
● Establishing a conc. gradient
of Na
+
(higher in lumen than
epithelial cell)
2 ● Na
+ enters epithelial cell down
its concentration gradient with
glucose against its
concentration gradient
● Via a co-transporter protein
3 ● Glucose moves down a conc.
gradient into blood via
facilitated diffusion

36
Q

Describe the absorption of lipids by a mammal, including the role of micelles

A

● Micelles contain bile salts, monoglycerides and fatty acids
○ Make monoglycerides and fatty acids (more) soluble in water
○ Carry / release fatty acids and monoglycerides to cell / lining of ileum
○ Maintain high concentration of fatty acids to cell / lining
● Monoglycerides / fatty acids absorbed (into epithelial cell) by diffusion (lipid soluble)
● Triglycerides reformed in (epithelial) cells and aggregate into globules
● Globules coated with proteins forming chylomicrons which are then packaged into vesicles
● Vesicles move to cell membrane and leave via exocytosis
○ Enter lymphatic vessels and eventually return to blood circulation

37
Q

Describe the role of red blood cells and haemoglobin in oxygen transport

A

● Red blood cells contain lots of haemoglobin (Hb) - no nucleus, biconcave, high SA:V, short diffusion path
● Hb associates with / binds / loads O2at gas exchange surfaces where partial pressure of O2 (pO2) is high
● This forms oxyhaemoglobin which transports O2 (each can carry 4O2 - one at each Haem group)
● Hb dissociates from / unloads O2 near cells / tissues where pO2
is low

38
Q

Describe the structure of haemoglobin

A

● Protein with a quaternary structure
● Made of 4 polypeptide chains
● Each chain contains a Haem group containing an iron ion (Fe 2+)

39
Q

Describe the loading, transport and unloading of oxygen in relation to the
oxyhaemoglobin dissociation curve

A

Areas with low pO2 (respiring tissues):
● Hb has a low affinity for O2
● So O2 readily unloads / dissociates with Hb
● So % saturation is low

Areas with high pO2 (gas exchange surfaces):
● Hb has a high affinity for O2
● So O2 readily loads / associates with Hb
● So % saturation is high

40
Q

Explain how the cooperative nature of oxygen binding results in an
S-shaped (sigmoid) oxyhaemoglobin dissociation curve

A
  1. Binding of first oxygen changes tertiary / quaternary structure of haemoglobin
  2. This uncovers Haem group binding sites, making further binding of oxygens easier
41
Q

Describe evidence for the cooperative nature of oxygen binding

A

● A low pO2 as oxygen increases there is little / slow increase in % saturation of Hb with oxygen
○ When first oxygen is binding

● At higher pO2
, as oxygen increases there is a big / rapid increase in % saturation of Hb with oxygen
○ Showing it has got easier for oxygens to bind

42
Q

What is the Bohr effect?

A

Effect of CO2 concentration on dissociation of oxyhaemoglobin → curve shifts to right

43
Q

Explain effect of CO2 concentration on the dissociation of oxyhaemoglobin

A
  1. Increasing blood CO2 eg. due to
    increased rate of respiration
  2. Lowers blood pH (more acidic)
  3. Reducing Hb’s affinity for oxygen as
    shape / tertiary / quaternary
    structure changes slightly
  4. So more / faster unloading of oxygen
    to respiring cells at a given pO2
44
Q

Explain the advantage of the Bohr effect (eg. during exercise)

A

More dissociation of oxygen → faster aerobic respiration / less anaerobic respiration → more ATP produced

45
Q

Explain why different types of haemoglobin can have different oxygen
transport properties

A

● Different types of Hb are made of polypeptide chains with slightly different amino acid sequences
● Resulting in different tertiary / quaternary structures / shape → different affinities for oxygen

46
Q

Explain how organisms can be adapted to their environment by having
different types of haemoglobin with different oxygen transport properties

A

Curve shift left → Hb has higher affinity for O2
● More O2 associates with Hb more readily
● At gas exchange surfaces where pO2
is lower
● Eg. organisms in low O2 environments - high
altitudes, underground, or foetuses

Curve shift right → Hb has lower affinity for O2
● More O2 dissociates from Hb more readily
● At respiring tissues where more O2
is needed
● Eg. organisms with high rates of respiration /
metabolic rate (may be small or active)

47
Q

Describe the general pattern of blood circulation in a mammal

A

Closed double circulatory system - blood passes through heart twice for every circuit around body:

  1. Deoxygenated blood in right side of heart pumped to lungs; oxygenated returns to left side
  2. Oxygenated blood in left side of heart pumped to rest of body; deoxygenated returns to right
48
Q

Suggest the importance of a double circulatory system

A

● Prevents mixing of oxygenated / deoxygenated blood
○ So blood pumped to body is fully saturated with oxygen for aerobic respiration

● Blood can be pumped to body at a higher pressure (after being lower from lungs)
○ Substances taken to / removed from body cells quicker / more efficiently

49
Q

Name the blood vessels entering and leaving the heart and lungs

A

● Vena cava – transports deoxygenated
blood from respiring body tissues → heart
● Pulmonary artery – transports
deoxygenated blood from heart → lungs

● Pulmonary vein – transports oxygenated
blood from lungs → heart
● Aorta – transports oxygenated blood
from heart → respiring body tissues

50
Q

Name the blood vessels entering and leaving the kidneys

A

● Renal arteries – oxygenated blood → kidneys

● Renal veins – deoxygenated blood to vena cava from kidneys

51
Q

Name the the blood vessels that carry oxygenated blood to the heart muscle

A

Coronary arteries - located on surface of the heart, branching from aorta

52
Q

Suggest why the wall of the left ventricle is thicker than that of the right

A

● Thicker muscle to contract with greater force
● To generate higher pressure to pump blood around entire body

53
Q

Explain how graphs showing pressure or volume changes during the cardiac
cycle can be interpreted, eg. to identify when valves are open / closed

A

SL valves closed
● Pressure in [named] artery higher than
in ventricle
● To prevent backflow of blood from
artery to ventricles

SL valves open
● When pressure in ventricle is higher
than in [named] artery
● So blood flows from ventricle to artery

AV valves closed
● Pressure in ventricle higher than atrium
● To prevent backflow of blood from
ventricles to atrium

AV valves open
● When pressure in atrium is higher than
in ventricle
● So blood flows from atrium to ventricle

54
Q

Describe the equation for cardiac output

A

Cardiac output (volume of blood pumped out of heart per min) = stroke volume (volume of blood pumped in
each heart beat) x heart rate (number of beats per min)

55
Q

How can heart rate be calculated from cardiac cycle data?

A

Heart rate (beats per minute) = 60 (seconds) / length of one cardiac cycle (seconds)

56
Q

Explain how the structure of arteries relates to their function

A

function – carry blood away from heart at high pressure

● Thick smooth muscle tissue → can contract and control / maintain blood flow / pressure
● Thick elastic tissue → can stretch as ventricles contract and recoil as ventricles relax, to
reduce pressure surges / even out blood pressure / maintain high pressure
● Thick wall → withstand high pressure / stop bursting
● Smooth / folded endothelium → reduces friction / can stretch
● Narrow lumen → increases / maintains high pressure

57
Q

Explain how the structure of arterioles relates to their function

A

Explain how the structure of arterioles relates to their function
Function – (division of arteries to smaller vessels which can) direct blood to different capillaries / tissues
● Thicker smooth muscle layer than arteries
○ Contracts → narrows lumen (vasoconstriction) → reduces blood flow to capillaries
○ Relaxes → widens lumen (vasodilation) → increases blood flow to capillaries
● Thinner elastic layer → pressure surges are lower (as further from heart / ventricles)

58
Q

Explain how the structure of veins relates to their function

A

Function – carry blood back to heart at lower pressure
● Wider lumen than arteries → less resistance to blood flow
● Very little elastic and muscle tissue → blood pressure lower
● Valves → prevent backflow of blood

59
Q

Explain how the structure of capillaries relates to their function

A

Function - allow efficient exchange of substances between blood and tissue fluid (exchange surface)
● Wall is a thin (one cell) layer of endothelial cells → reduces diffusion distance
● Capillary bed is a large network of branched capillaries → increases surface area for diffusion
● Small diameter / narrow lumen → reduces blood flow rate so more time for diffusion
● Pores in walls between cells → allow larger substances through

60
Q

Explain the formation of tissue fluid

A

At the arteriole end of capillaries:
1. Higher blood / hydrostatic pressure inside
capillaries (due to contraction of ventricles)
than tissue fluid (so net outward force)
2. Forcing water (and dissolved substances)
out of capillaries
3. Large plasma proteins remain in capillary

61
Q

Explain the return of tissue fluid to the circulatory system

A

At the venule end of capillaries:
1. Hydrostatic pressure reduces as fluid leaves capillary (also due to friction)
2. (Due to water loss) an increasing concentration of plasma proteins lowers water potential in
capillary below that of tissue fluid
3. Water enters capillaries from tissue fluid by osmosis down a water potential gradient
4. Excess water taken up by lymph capillaries and returned to circulatory system through veins

62
Q

Suggest and explain causes of excess tissue fluid accumulation

A

● Low concentration of protein in blood plasma OR high salt concentration
○ Water potential in capillary not as low → water potential gradient is reduced
○ So more tissue fluid formed at arteriole end / less water absorbed at venule end by osmosis
● High blood pressure → high hydrostatic pressure
○ Increases outward pressure from arterial end AND reduces inward pressure at venule end
○ So more tissue fluid formed at arteriole end / less water absorbed at venule end by osmosis
○ Lymph system may not be able to drain excess fast enough

63
Q

What is a risk factor? Give examples for cardiovascular disease

A

● An aspect of a person’s lifestyle or substances in a person’s body / environment
● That have been shown to be linked to an increased rate of disease
● Examples - age, diet high in salt or saturated fat, smoking, lack of exercise, genes

64
Q

Describe the function of xylem tissue

A

Transports water (and mineral ions) through the stem, up the plant to leaves of plants

65
Q

Suggest how xylem tissue is adapted for its function

A

● Cells joined with no end walls forming a long continuous tube → water flows as a continuous column
● Cells contain no cytoplasm / nucleus → easier water flow / no obstructions
● Thick cell walls with lignin → provides support / withstand tension / prevents water loss
● Pits in side walls → allow lateral water movements

66
Q

Explain the cohesion-tension theory of water transport in the xylem

A

Leaf
1. Water lost from leaf by transpiration - water evaporates from mesophyll
cells into air spaces and water vapour diffuses through (open) stomata
2. Reducing water potential of mesophyll cells
3. So water drawn out of xylem down a water potential gradient

Xylem
4. Creating tension (‘negative pressure’ or ‘pull’) in xylem
5. Hydrogen bonds result in cohesion between water molecules (stick
together) so water is pulled up as a continuous column
6. Water also adheres (sticks to) to walls of xylem

Root
7. Water enters roots via osmosis

67
Q

Describe how to set up a potometer

A
  1. Cut a shoot underwater at a slant →
    prevent air entering xylem
  2. Assemble potometer with capillary tube
    end submerged in a beaker of water
  3. Insert shoot underwater
  4. Ensure apparatus is watertight / airtight
  5. Dry leaves and allow time for shoot to
    acclimatise
  6. Shut tap to reservoir
  7. Form an air bubble - quickly remove end
    of capillary tube from water
68
Q

Describe how a potometer can be used to measure the rate of transpiration

A

Potometer estimates transpiration rate by measuring water uptake:

  1. Record position of air bubble
  2. Record distance moved in a certain amount of time (eg. 1 minute)
  3. Calculate volume of water uptake in a given time:
    ● Use radius of capillary tube to calculate cross-sectional area of water (πr2)
    ● Multiply this by distance moved by bubble
  4. Calculate rate of water uptake - divide volume by time taken
69
Q

Describe how a potometer can be used to investigate the effect of a named
environmental variable on the rate of transpiration

A

● Carry out the above, change one variable at a time (wind, humidity, light or temperature)
○ Eg. set up a fan OR spray water in a plastic bag and wrap around the plant OR change
distance of a light source OR change temperature of room

● Keep all other variables constant

70
Q

Suggest limitations in using a potometer to measure rate of transpiration

A

● Rate of water uptake might not be same as rate of transpiration
○ Water used for support / turgidity
○ Water used in photosynthesis and produced during respiration

● Rate of movement through shoot in potometer may not be same as
rate of movement through shoot of whole plant
○ Shoot in potometer has no roots whereas a plant does
○ Xylem cells very narrow

71
Q

Suggest how different environmental variables affect transpiration rate
(light intensity)

A

Increases rate of
transpiration

● Stomata open in light to let in CO2
for photosynthesis

● Allowing more water to evaporate faster

● Stomata close when it’s dark so there is a low transpiration rate

72
Q

Suggest how temperature affects transpiration rate

A

Increases rate of
transpiration

● Water molecules gain kinetic energy as temperature increases

● So water evaporates faster

73
Q

Suggest how wind intensity affects transpiration rate

A

Increases rate of
transpiration

● Wind blows away water molecules from around stomata

● Decreasing water potential of air around stomata

● Increasing water potential gradient so water evaporates faster

74
Q

Suggest how humidity affects transpiration rate

A

Decreases rate of
transpiration

● More water in air so it has a higher water potential

● Decreasing water potential gradient from leaf to air

● Water evaporates slower

75
Q

Describe the function of phloem tissue

A

Transports organic substances eg. sucrose in plants

76
Q

Suggest how phloem tissue is adapted for its function

A
  1. Sieve tube elements
    ● No nucleus / few organelles → maximise space for / easier flow of organic substances
    ● End walls between cells perforated (sieve plate)
  2. Companion cells
    ● Many mitochondria → high rate of respiration to make ATP for active transport of solutes
77
Q

What is translocation?

A

● Movement of assimilates / solutes such as sucrose
● From source cells (where made, eg. leaves) to sink cells (where used / stored, eg. roots) by mass flow

78
Q

Explain the mass flow hypothesis for translocation in plants

A
  1. At source, sucrose is actively transported into phloem sieve tubes / cells
  2. By companion cells
  3. This lowers water potential in sieve tubes so water enters (from xylem) by osmosis
  4. This increases hydrostatic pressure in sieve tubes (at source) / creates a hydrostatic pressure gradient
  5. So mass flow occurs - movement from source to sink
  6. At sink, sucrose is removed by active transport to be used by respiring cells or stored in storage organs
79
Q

Describe the use of tracer experiments to investigate transport in plants

A
  1. Leaf supplied with a radioactive tracer eg. CO2 containing radioactive isotope
    14C
  2. Radioactive carbon incorporated into organic substances during photosynthesis
  3. These move around plant by translocation
  4. Movement tracked using autoradiography or a Geiger counter
80
Q

Describe the use of ringing experiments to investigate transport in plants

A
  1. Remove / kill phloem eg. remove a ring of bark
  2. Bulge forms on source side of ring
  3. Fluid from bulge has higher conc. of sugars than below - shows sugar is transported in phloem
  4. Tissues below ring die as cannot get organic substances
81
Q

Suggest some points to consider when interpreting evidence from tracer &
ringing experiments and evaluating evidence for / against the mass flow
hypothesis

A

● Is there evidence to suggest the phloem (as opposed to the xylem) is involved ?
● Is there evidence to suggest respiration / active transport is involved?
● Is there evidence to show movement is from source to sink? What are these in the experiment?
● Is there evidence to suggest movement is from high to low hydrostatic pressure?
● Could movement be due to another factor eg. gravity?

82
Q
A