Topic 2 - Life Assurance and Annuity Functions Flashcards
Topic 2 –Life and Annuity Functions
Topic overview
- Define simple assurance and annuity functions
- Determine mean and variance functions
• For assurance functions
• For annuity functions - Derive relationship between assurance and
annuity functions
Topic overview
What is a life insurance contract?
- Agreement between Life co and policyholder
- Policyholder agrees to make payment(s)
- Life co agrees to pay lump sum or series of
payments on occurrence of insured event
(Insured event normally on survival or on
death)
What are the different types of life assurance contract?
Whole life (WL)
Term assurance (TA)
Pure endowment (PE)
Endowment assurance (EA)
What is a whole life contract?
Payout on death
What is a term assurance contract?
Payout on death during specific term
What is a pure endowment contract?
Payout on survival beyond a specific term
What is an endowment assurance contract?
• Payout on survival beyond a term or death if earlier
• So combination of a TA and PE
In most contracts, what is the payout referred to as?
Sum Assured
Determine mean & variance functions
What does the standard notation Tx refer to?
- Complete future lifetime of a life aged x
- How much longer we expect a life aged x to live
State the formula for calculating the complete expectation of life for an individual aged x
E[Tx] = ∫0,∞ 𝑡𝑝𝑥 dt = 𝑜ex
Note: in all cases where 𝑜ex is stated, the 𝑜 symbol should be placed above the e
Determine mean & variance functions
What does the standard notation Kx refer to?
- Curtate random future lifetime of a life aged x
- Integer of Tx
State the formula for calculating the curtate expectation of life
E[Kx] = Σ𝑘=1,∞ 𝑘𝑝𝑥 = ex
ex ≈ 𝑜ex - 0.5
- Assume that benefits are paid at the END of year of death
Give the present value of a £1 sum assured payout on a policyholder’s death from a whole life assurance contract. Assume benefits are paid at the end of year of death
Whole Life Assurance
- Pays sum assured on policyholder’s death
PV of a sum assured of £1 payable at end of YOD
PV = 𝑣^(𝐾𝑥 + 1)
Determine mean & variance functions
State the standard notation for the complete future lifetime of a life aged x (ie how much longer we expect a life aged x to live)
Tx
What does the standard notation E[Tx] refer to?
The complete expectation of life for an individual aged x
Determine mean & variance functions
Give the standard notation for the curtate random future lifetime of a life aged x (integer of Tx)
Kx
Give the expected present value of a £1 sum assured payout on a policyholder’s death from a whole life assurance contract. Assume benefits are paid at the end of year of death
Whole Life Assurance
- Pays sum assured on policyholder’s death
EPV of a sum assured of £1 payable at end of YOD
EPV = E[𝑣^(𝐾𝑥 + 1)] = Σ𝑘=0,∞ 𝑣^(𝐾𝑥 + 1) 𝑘𝑝𝑥 𝑞,𝑥+𝑘
EPV = A,x
Give the expected present value of a £1 sum assured payout on a policyholder’s death from a whole life assurance contract. Assume benefits are paid at the end of year of death
Whole Life Assurance
- Pays sum assured on policyholder’s death
EPV of a sum assured of £1 payable at end of YOD
EPV = E[𝑣^(𝐾𝑥 + 1)] = Σ𝑘=1,∞ 𝑣^(𝐾𝑥 + 1) 𝑘𝑝𝑥 𝑞,𝑥+𝑘
EPV = A,x
Find A35 – basis AM92 Ultimate@ 4% pa
A35 = 0.19219 (pg 96)
Give the variance of the present value of a £1 sum assured payout on a policyholder’s death from a whole life assurance contract. Assume benefits are paid at the end of year of death
- Whole Life Assurance
- Variance
- Use Var[X] = E[X^2] – [E(X)]^2
var[𝑣^(𝐾𝑥 + 1)] = E[𝑣^(𝐾𝑥 + 1)(2)] - E[𝑣^(𝐾𝑥 + 1)]^2
= Σ𝑘=0,∞ [𝑣^(𝐾𝑥 + 1)]^2 𝑘𝑝𝑥 𝑞,𝑥+𝑘 - (Ax)^2
= Σ𝑘=0,∞ [𝑣^2]^(𝐾𝑥 + 1) 𝑘𝑝𝑥 𝑞,𝑥+𝑘 - (Ax)^2
= 2^Ax - (Ax)^2
2^Ax based on v^2 i.e. (1/1+i)^2 and is tabulated
Determine mean & variance functions
Whole Life Assurance
So far our expectations and variances of sum assured are only based on sum assured (S) of £1, what if S>1?
- E(S𝑣^[𝐾𝑥+1]) = SE(𝑣^[𝐾𝑥+1])
- Var[S𝑣^(𝐾𝑥+1)] = S^(2)Var[𝑣^(𝐾𝑥+1)]
Determine mean & variance functions
Example
• Calculate the EPV and Variance of a whole life assurance with a sum assured of £100,000 for a life currently aged 40. Payable at the EOYD.
• Basis AM92 Ultimate @ 6% pa
• 100000A40@6% = 100000x0.12313 = £12,313
• Var = 1000002[(2^A40) – (A40)^2]
• 100000^(2)[0.02707 – 0.12313^(2)] = £119,090,031