Topic 1 Flashcards
Compare monohybrid and dihybrid crosses.
Monohybrid crosses look at a single trait/gene and dihybrid crosses look at 2 traits/genes
What is a test cross?
Determining unknown genotypes by crossing with homozygous recessive
Compare parental cross, first generation, and second generation offspring.
Parental cross: homozygotic true breeding; one recessive one dominant
F1: heterozygous and only shows dominant phenotype with hidden genotypes
F2: shows all possible phenotypes and all genotypes can be inferred
Why was Mendel successful in his discovery?
Not only are peas easy to grow, have a short life cycle, controlled mating, and have two easily distinguishable states (short and tall);
There is no gene linkage, meaning the traits are controlled by a single gene.
As well as, Mendel kept detailed record of the crosses that were used to find statistical evidence and used true breeding lineages (good controls)
What is the first Mendelian law?
Alleles of a gene separate independently (randomly) from each other during transmission from parent to offspring (meiosis)
The dominant phenotype appears at _____% in the F1 generation and _______% in the F2 generation
100%; 75%
Define locus.
a specific region on a chromosome, usually a gene
(plural loci)
How do you predict the results of a dihybrid cross in a punnet square?
You put all the possible allele combinations for each parent.
Ex) a parent that is YyRr has all the possible combinations for their gametes:
YR Yr yR yr
What is the second Mendelian law?
Law of Independent Assortment
Alleles of two (or more) genes (loci) segregate independently during transmission from parent to offspring
9 AA: 3 Aa: 3aA: 1aa
Derivations of the Second Law?
(3/4D+1/4r)^n
where n is the number of genes involved in the cross
How do you find the probability of an organism having multiple, independent genotypes? Phenotypes?
Multiply them.
If inheritance is independent, the expected frequencies are of the genotypes are their products:
Ex) P(dd)=1/2; p(tt)=1/4; and p(gg)=1/8
P=1/21/41/8= 1/64
P(AA)=0.25
P(Aa)=0.5
P(aa)=0.25
So, the probability of getting a dominant phenotype is 75% and the probability of getting a recessive phenotype is 25%. To find the probability of these phenotypes in combination use the multiplication rule.
Ex) P(round, yellow, and tall)=(0.75)^3
or P(round, green, and short)=(0.75)(0.25)(0.25)
How do we calculate the frequency of genotypes in crosses?
AKA the total possible allele combinations
We can use probability to determine the expected frequencies of genotypes in a progeny based on the assumption of equal segregation of alleles (First Mendelian Law) and independent assortment of alleles (Second Mendelian Law).
(1) Apply the Second Law to predict frequencies:
(2) Consider every locus separately
(3) How many gamete genotypes can from from each parental genotype
(a) if the alleles at the locus are the same (homozygotic) then there is effectively only one allele
(4)
How do we calculate the frequency of genotypes in crosses?
We can use probability to determine the expected frequencies of genotypes in a progeny based on the assumption of equal segregation of alleles (First Mendelian Law) and independent assortment of alleles (Second Mendelian Law).
(1) Apply the Second Law to predict frequencies:
(2) Consider every locus separately
(3) How many gamete genotypes can from from each parental genotype
(a) if the alleles at the locus are the same (homozygotic) then there is effectively only one allele
(4) Multiply all the possible outcomes
(5) then raise the product to the power of the number of segregating loci
True or false? Not all sets of genes are ‘Mendelian’ or follow Mendel’s laws.
True
How do you statistically test if genes are Mendelian?
preform a Chi-squared test
How do you preform a Chi-Squared test?
Step 1: Predict expected numbers based on hypothesis
Ex) 9:3:3:1 for a dihybrid cross
Step 2: Calculate how well the data fits hypothesis use the chi-squared formula (with observed and expected frequencies)
Step 3: Determine the degrees of freedom
- you can then use a table (df vertical, 0.05 horizontal) to find the CV
Note: df= n-1
where n is the number of categories (amount of phenotypes)
Step 4: Accept or reject the hypothesis by comparing the chi-squared statistic to the critical value
Ex) H0: there is no difference between the observed phenotypic ratio and the expected ratio
Either determine if the chi-squared is larger than the CV OR calculate the p-value on the computer
If the p-value is less than 0.05 it may be significantly different (reject null hypothesis)