Thermodynamics Flashcards
Define standard enthalpy of formation:
The enthalpy change when one mole of a substance is formed from its elements, under standard conditions, with all substances in their standard state.
Define standard enthalpy of combustion:
The enthalpy change when one mole of a substance is burnt completely in oxygen, under standard conditions, with all substances in their standard state.
State Hess’s Law:
The enthalpy change (at constant pressure) in a reaction is independent of the route taken (and depends only on the initial and final states).
Define enthalpy of atomisation:
The enthalpy change when 1 mole of gaseous atoms are formed from its element in its standard state.
Define enthalpy of bond disassociation:
The standard enthalpy change to break 1 mol of covalent bonds in a gaseous molecule to form gaseous atoms.
Define electron affinity:
The first electron affinity is the enthalpy change when 1 mole of gaseous atoms gain one mole of electrons to form one mole of gaseous atoms with a -1 charge.
Define second electron affinity:
The enthalpy change when one mole of gaseous 1- ions gains one electron per ion to produce gaseous 2- ions.
Why is the first electron affinity exothermic and the second endothermic?
The first is exothermic because there is an attraction between the nucleus and the electrons (making bonds). That nuclear attraction was stronger than the repulsion felt by the electron.
The second is endothermic because it takes energy to overcome the repulson between the negative ion and the electron.
Define enthalpy of lattice formation:
The standard enthalpy change when 1 mole of a solid ionic lattice is formed from its constituent ions in gaseous form.
Why is the enthalpy of formation always exothermic?
When a lattice forms, many electrostatic attractions between oppositely charged ions are made. Making bonds is exothermic.
Define enthalpy of lattice disassociation:
The standard enthalpy change when 1 mole of a solid ionic lattice is disassociated into its constituent ions in gaseous form.
Why is the enthalpy of lattice disassociation always endothermic?
This reaction is overcoming many electrostatic attractions between oppositely charged ions. Breaking bonds is endothermic.
The strength of a lattice enthalpy of formation depends on the following factors:
- The charge on the ion
The greater the charge on the ion, the greater the attraction between the ions so the stronger the lattice enthalpy - The size of the ion
The larger the ions, the weaker the lattice. As ions increase in size, their charge density decreases so the ions have a weaker attractive force between them.
Which one has a higher lattice enthalpy of formation and why?
Out of NaF and LiF?
LiF
Na+ is bigger than Li+ so Na+ has a smaller charge density than Li+.
So when the Na+ forms a bond with F-, less energy is released compared with when Li+ joins with F-.
NaF forms a weaker ionic bond, so a smaller lattice enthalpy of formation.
Why is the lattice enthalpy of formation for Na2O more exothermic than NaF
The oxide ion has a higher charge than the fluoride ion therefore the oxide ion has a higher charge density. Thus, more energy is released when a sodium ion bonds to an oxide ion, compared to when it bonds to fluoride.