thermo Flashcards

1
Q

what is the rankine cycle?

A

its a reversible steam power plant cycle (no losses due to irreversibility)

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2
Q

how do you work out specific volume?

A

v=1/p

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3
Q

what is internal energy?

A

internal energy gives the amount of energy bound up within a substance due to its temperature and pressure

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4
Q

what is enthalpy?

A

its similar to internal energy which represents energy bound up within the system due to its temperature and pressure and capacity for doing work

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5
Q

adiabatic meaning?

A

there is no heat transfer

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6
Q

isentropic requirements?

A

it needs the process to be adiabatic and reversible (as perefect as possible) (Δs = 0)
∆𝑠=𝑠2−𝑠1=0

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7
Q

what are the propertis of extesive systems?

A

its total valuie depends upon the extent of the system (how many kilograms) i.e volume, internal energy, enthalpy and entropy

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8
Q

what are the properties of intensive systems?

A

its value is independent of the extent of the system, i.e pressure and volume

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9
Q

what is the first law of thermodynamics?

A

the law describes what must apply to a cyclic process = a process that returns exactly to start point. Q = ΔU + W

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10
Q

displacement equations?

A

constant volume dv=0 W12 1 => pdv=-px

2
constant pressure dp=0 W12 1 => pdv=-p(v2-v1)

2

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11
Q

what is reversibility?

A

W=∫pdV
for it to be reversible the system must be in a state of equilibrum (pressure constant throughout the system)
change of state is called (state of quasiequilibrium)
for many processes Teq < < Tprocess

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12
Q

what is irreversibility?

A

most procces are not perfect and are said to be irreversible. W=∫pdV

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13
Q

what is work transfer in a cyclic process?

A

check phone for answer

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14
Q

steady flow energy equation?

A

h1+ (v1^2/2)+gz1+(Q/m)-(W/m) = h2+(v2^2/2)+gz2
(h=enthalpy in this case)

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15
Q

turbine and compresser equation?

A

in this case heat transfer (Q)=0 and difference in potential (gz)=0 z1=z2
W/m=(h1-h2)+(v1^2-v2^2)/2

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16
Q

boiler and heater equation?

A

in this case work (W)=0 and difference in potential (gz)=0
z1=z2
Q/m=(h2-h1)+(v2^2-v1^2)/2

17
Q

nozzle equation?

A

in this case work (W), heat transfer (Q) and difference in potential (gz) are normally negligible (=0)
(h1-h2)=(v1^2-v2^2)/2 (frequently v1 < < v2)
v2^2=2(h1-h2)

18
Q

1st law but open system equation?

A

h=u+pv

19
Q

pure substance properties?

A

pure substance is matter of a single chemical composition, e.g water. if the whole system contains only water then it is not important if it is in the ice, water or steam phase, its still considered pure

20
Q

what is the rankine cycle efficiency?

A

it should be <40% (if its above that its probaly wrong)
n=net work out/heat in => Wt-Wp/Qb
but Wp < < < Wt so Wt/Qb

21
Q

calculations for rankine cycle?

A

W/m is negligible, so Δh is negligible > > Hin = Hout
n=Wt/Qb=> −ΔhT/ΔhB=> h3-h4/h3-h2

22
Q

turbine (adiabatic) equations?

A

n=work out for actual turbine/work out for perfect turbine=>
ΔHactual/ΔHperfect = h1-h2/h1-h2s (see phone for diagram)

23
Q

compressors (adiabatic) equations?

A

n=work out for actual compressor/work out for perfect compressor
ΔHactual/ΔHperfect = h2-h1/hs2-h1

24
Q

ideal gas equations?

A

pv=Rt and (p1 v1)/T1 = (p2 v2)/T2

25
Q

univerval gas constant?

A

pV = mRT
(Po Vo)/To=MR=> R=8.3143 kj/kgmol.K

26
Q

definitions of specific heat?

A

@constant pressure
Cp=(dh/dT)p The relationship between enthalpy and temperature for a process occurring at constant pressure. Cp may not be constant

@constant volume
Cv=(du/dT)v The relationship between internal energy and temperature for a process occurring at constant volume, Cv may not be constant

27
Q

definitions of specific heat for a prefect gas?

A

for perfect gas vlaues Cp abd Cv are constant
h2-h1=Cp(T2-T1) u2-u1=Cv(T2-T1) 𝛾=Cp/Cv

28
Q

useful equations for Cp and Cv?

A

h = u + pv (for any pure substance)
h = u + RT (for an ideal gas)
dh = du + RdT (differentiate)

29
Q

for a semi perfect gas or perfect gas?

A

dh = CpdT and du = CvdT
CpdT = CvdT + RdT
Cp = Cv + R
R = Cp - Cv

30
Q

Constant volume process

A

using 1st law Q = Δu + W
V is constant, so dV = 0, pdV = 0, W=0
and Q = Δu = CvΔT
for process 1-2: Q = Cv(T2-T1)
since V is constant, p1/T1=p2/T2
Q=CvT1(T2-1)/T1 = CvT1 (p2-1)/p1

31
Q

constant pressure process

A

using 1st law Q = Δu + W
for a reversible process 1-2
Q = h2-h1 = Cp(T2-T1)

32
Q

constant temperature process

A

using 1st law Q = Δu + W
W = p1v1 ln(v2/v1)
since T1 = T2 = T and p2v2 + p1v1 =RT
W = p1v1 ln(v2/v1) = RT ln (v2/v1) = RT ln(p1/p2)
since ΔT = 0, Δu = 0 and 1st law gives Q=W

33
Q

What is the 2nd law of thermodynamics?

A

Delta S= 0 =>100%