Thermal Flashcards

1
Q

What affects the amount of energy needed to raise the temperature of a substance with a mass of 1 Kg by 1 K?

A

The amount of heat needed to raise the temperature of a substance (material) depends on:

1- mass:
more mass=more particles=more heat needed to move all particles.

2- Type of material:
heat capacity= how much heat a material absorbs and store.
Great capacity = they absorb a lot of energy (difficult to heat up)
less capacity=they don’t absorb lots of energy (easy to heat up)

3- How much the temperature is raised…obviously!!!

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2
Q

The SHC of water is 4200 J / kg oC

How much does the internal energy increase if 0.5 kg of water is heated by 10 oC?

A

E = m x c x delta t
= 0.5 x 4200 x 10
= 21000 J

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3
Q

The SHC of aluminium is 880 J / kg oC

How much does the internal energy increase if 1 kg of aluminium is heated by 10 oC?

A

E = m x c x delta t
= 1 x 880 x 10
= 8800 J

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4
Q

Water has a very high specific heat capacity (4200 J/kg°C). What does this mean?
What would happen if water had a low specific heat capacity?

A

Water takes a huge amount of energy to heat up, but take a long time to cool down too.

Life would have not evolved, water absorbs the right amount of energy for life to develop.

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5
Q

What is the first law of thermodynamics?

A

Energy is not lost or gained, just transferred or transformed.

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6
Q

What is the zeroth law?

A

The Zeroth Law states that if two bodies are in equilibrium with a third body, they are in thermal equilibrium with one another.

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7
Q

What is specific latent heat?

A

The amount of energy transfer necessary to change the state of 1Kg of a substance with no change in its temperature.

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8
Q

What is specific latent heat of fusion?

A

The amount of energy transfer necessary to melt 1Kg of a solid at its melting temperature.

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9
Q

What is the specific latent heat of vaporisation?

A

The amount of energy transfer necessary to change1Kg of a liquid into a gas at its boiling point.

Vaporisation is the process of turning a liquid into a gas (vapour)

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10
Q

Calculate the thermal energy, Q, absorbed when 1.5 kg of paraffin is raised from 15°C to 50°C.

A
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11
Q

What are the 3 modes of heat transfer?

A
  • Conduction
  • Convection
  • Radiation
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12
Q

If 48 000 J of heat energy are given off when a 2 kg block of metal cools by 12 oC, what is the specific heat capacity of the metal?

A

Q=mC∆T

C=Q/m∆T

C=(48 000)/(2 × 12)

C=2000J 〖kg〗^(-1) K^(-1)

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13
Q

How much energy is provided by a 500W (Power) heater in 2mins?

A

E=P × t

E=500W × 120s

E=60 000J or 60kJ

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14
Q

Calculate the equilibrium temperature when 50g of copper at 150oC is added to 100mL of water at 10oC
Cw=4200J Kg-1 K-1. CCu=385 J Kg-1 K-1.

A

m_w C_w ∆T_w=m_Cu C_Cu ∆T_Cu

0.1×4200×(T_f-10)=0.05×385×(150-T_f)

420T_f-4200=2887.5-19.25T_f

420T_f+19.25T_f=2887.5+4200

439.25T_f=7087.5

T_f=16.1℃

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15
Q

Calculate the amount of heat required to heat 250g of ice at -15oC to steam at 120oC.
Cice=2110 J Kg-1 K-1. Cw=4200 J Kg-1 K-1. Cst=1996 J Kg-1 K-1. Lf=334kJ kg-1. Lv = 2230kJ kg-1

A

Q=mC_i ∆T_i+mL_f+mC_w ∆T_w+mL_v+mC_s ∆T_s

Q=0.25×2110×15+0.25×334 000+0.25×4200×100+0.25×2230 000+0.25×1996×20

Q=7912.5+83 500+105 000+557 500+9980

Q=763 892.5J

Q≈770kJ

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16
Q

Convert the following:
a) 25°C to K;
b) -8°C to K;
c) 210 K to °C;
d) 480 K to °C.

A

a) TK = TC + 273 = 25 + 273 = 298 K c) TC = TK - 273 = 210 - 273 = -63°C
b) TK = TC + 273 = -8 + 273 = 265 K d) TC = TK - 273 = 480 - 273 = 207°C

17
Q

How much heat transfer is required to thaw a 0.450 kg package of frozen vegetables originally at 0°C if their heat of fusion is the same as that of water?

A

Q = mLf = (0.450 kg)(334 kJ kg-1) = 150 kJ

18
Q

How much heat transfer is necessary to raise the temperature of a 0.200 kg piece of ice from −20.0°C to 130°C, including the energy needed for phase changes?

A

Q = mciceΔT + mLf + mcwaterΔT + mLv + mcsteamΔT = (0.200 kg)(2090 J kg-1 °C-1)(20°C) + (0.200 kg)(3.34 x 105 J kg-1) + (0.200 kg)(4186 J kg-1 °C-1)(100°C) + (0.200 kg)(2.256 x 106 J kg-1) + (0.200 kg)(1520 J kg-1 °C-1)(30°C) = 6.19 x 105 J or 619 kJ