Theory Important Flashcards

1
Q

Define Fossil Fuels?

A

A fuel that has been produced over a long period of time by the breakdown of organic material, such as decaying remains of plants and tiny marine animals. Fossil fuels are non-renewable because they are used faster than they can be replenished

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2
Q

Define difference between Renewable and Non-Renewable Fuel?

A

Renewable fuel is made from decomposition of biomass can be replenished as fast as it is consumed whereas non-renewable fuel is made from fossil fuels and cannot be replenished as fast as it consumed

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3
Q

Explain the carbon neutrality of Biofuels?

A

Biofuels are more carbon neutral than Fossil fuels, as during their combustion, plants remove CO2 released by biofuels for the purpose of photosynthesis

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4
Q

Define Activation Energy?

A

Activation energy is the minimum energy required to break the bonds between atoms of reactants and initiate the reaction

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5
Q

What is the purpose of salt bridge?

A

The salt bridge contains ions that free to move so they can balance the charges formed. Cations to move to the cathode and anions move to the anode, creating the internal circuit

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6
Q

What is the purpose of half cell?

A

To keep the reactants separate the prevent a spontaneous redox reactions. Thus, enable the flow of electrons to transfer via the external circuit

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7
Q

Why are Electrolytes usually in the form of a paste or gel, not a dilute solution?

A

Increases concentration of electrolyte, increasing the rate of reaction. Therefore, battery last longer, takes longer to reach equilibrium/polarisation

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8
Q

Why is a separator is used instead of a salt bridge. Why can it be a gelled electrolyte, a microporous plastic film or a porous inert material filled with electrolyte?

A

Separates the reactants but allows the ions in electrolyte to migrate to the electrodes. Cations join the cathode and the anions join the anode.

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9
Q

Why the anode and cathode are separated by an insulator?

A

Heat is also a product. Thus, insulator minimises the heat loss and reduces the efficiency and extends battery life

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10
Q

Why possible products of electrode reactions are removed from the electrode surfaces?

A

By removing products from electrode, thus products no longer build up. Therefore, it takes longer to reach equilibrium polarisation and equilibrium last longer

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11
Q

Describe two important functions of electrodes in this cell?

A

Porous electrodes allow reactants gases to diffuse slowly through, thus they can catalyse the reaction. Thus, it is the site of oxidation and reduction. They also keep reactants separate and thus, ensuring spontaneous redox reaction does not occur

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12
Q

Explain why the energy released when food is heated is greater than the energy available to the body?

A

This is due to incomplete absorption of nutrients by the body after digestion of food and incomplete oxidation of nutrients

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13
Q

A known mass of food is dried thoroughly and then burnt in the bomb calorimeter. Why must the food be dried?

A

To ensure excess water is removed before heating (otherwise heat will be wasted evaporating water rather than combusting food)

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14
Q

Explain why lipids are insoluble in water?

A
  • Lipids are a large, non-polar molecule with long hydrocarbon tail
  • Even though they have an ester functional group which can form a hydrogen bond with water it is predominantly a large non-polar molecule and so insoluble in water as it can only form dispersion forces
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15
Q

Explain how the strength of the forces between molecules is different between fat molecules and oil molecules?

A
  • Saturated fats - solids - due to the ability of the trigs to pack closely together thus they have greater dispersion forces -> higher melting point -> solids at room temp
  • Unsaturated fats (oils) - due to the presence of the C=C bonds this causes the fatty acid chains to kink -> thus the molecules are unable to pack as closely together -> decreases strength of the dispersion forces ->low melting point
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16
Q

Monosaccharides contain -OH functional groups and so can form hydrogen bonds with water. Why is the solubility of glucose in water important to biological processes?

A
  • Due to many -OH functional groups, they can form hydrogen bonds with water
  • Thus they are also very insoluble in water
  • Therefore digest easily
  • As a result, can be easily metabolised
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17
Q

Explain why polysaccharides are significantly less soluble than disaccharides or monosaccharides?

A

Polysaccharides are made up of long chains of monosaccharide linked -C-O-C bonds. Cross links form between chains too. Therefore, there are no available OH groups to forms H-bonds with water.

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18
Q

Why is amylose, slower to digest?

A

Due to the many exposed polar -OH functional groups - many hydrogen bonds can be formed between the monomers. Thus the straight chain tightly coils - causing many of the -OH functional sites to be internally facing thus decrease in solubility in water. Therefore, fewer Hydrogen bonds can be formed and as a result is slower to digest due to inability to break down monomers.

19
Q

Why is amylopectin, easier to digest?

A

Amylopectin is a branched polymer- thus there are many the -OH functional sites exposed as it
doesn’t coil. Thus it can easily form H bonds with water, very soluble and thus, easy to digest.

20
Q

How would a decrease from optimum temperature influence enzyme activity?

A

decrease in temp will decrease the rate of successful collisions thus decrease ROR but has no effect on the IMF within the enzyme thus no effect on the 3D structure thus no effect on the active site - enzyme does not denature - inactive.

21
Q

How would a increase from optimum temperature influence enzyme activity?

A

Increase in temperature above optimal, will disrupt the hydrogen bonds between the amide links in the secondary structure and between the R groups in the tertiary structure thus the protein will unravel, new bonds form, 3D will change, there will be a change in the shape of active site and the substrate will no longer be able to bind to the active site and enzyme cannot catalyse reaction / denatured

22
Q

How would a change from pH impact enzyme activity?

A

any change in pH from optimal pH range - can cause the acidic or alkaline R groups in the tertiary structure to ionise, as a consequence the ionic, Hydrogen and ion-dipole bonds can break, the enzyme will unravel, new bonds between R groups will form and 3D will change, there will be a change in the shape of active site and the substrate will no longer be able to bind to the active site and enzyme cannot catalyse reaction / denatured

23
Q

Explain why denaturation has no effect on the primary structure of a protein?

A
  • Because the change in pH or temperature is not significant enough to break the covalent amide link between the amino acids that form the primary structure
24
Q

Amylopectin is digested more rapidly than amylose. With reference to their structures, and hence their solubilities in water, explain this property?

A
  • Amylose -> straight chain polysaccharide-> forms a tight coil due to strong hydrogen bonds between the -OH functional groups -> thus - OH groups are internally facing -> decreases the solubility of amylose in water -> harder to hydrolyse -> slower to digest - > harder for the enzyme catalyse the reaction
  • Amylopectin -> branched polysaccharide -> -OH groups are exposed-> can form hydrogen bonds with water -> increases solubility in water -> easier to hydrolyse -> digest faster-> easier for the enzyme to catalyse the hydrolysis
25
Q

Are triglycerides soluble or insoluble in water

A

Triglycerides are insoluble in water - even though there are 3 ester functional groups the molecule is overall non polar thus cannot form hydrogen bonds with water thus insoluble in water

26
Q

Explain hydrolysis of triglycerides

A

Triglycerides are hydrolysed - after they are emulsified with bile - increase the surface are of fats by breaking down into water soluble droplets -> thus enabling the water and enzyme to act on them and catalyse the hydrolysis of triglycerides

27
Q

Explain why the energy released when food is heated is greater than the energy available to the body?

A
  • Energy oxidation in a lab in excess - 100% combustion. In humans - not have 100% digestion & absorption of all nutrients, not have 100% oxidation of the nutrients in the human body, thus we do not get all the KJ available
28
Q

Describe the bonding that is found in the primary and secondary structures of the glucagon molecule?

A
  • Primary structure (covalent bonds between C and N in the peptide links between amino acids
  • Secondary structure – hydrogen bonds between O (-C=O) AND H (-N-H) on different peptide groups in the a-helix (B-sheet)
29
Q

Explain enzyme lock and key model?

A

The reactant molecules manoeuvre into the active site and once bound here, the reaction can occur, and new product/s are released. Once in the active site, the substrate is held by a variety of bonds. These bonds can include:

• Hydrogen bonding
• Dipole-dipole
• Dispersion forces
• Electrostatic attraction between groups of atoms of opposite charge
• Ion-dipole interactions
2. The substrate bound to the enzyme is called the enzyme-substrate complex. The existing bonds within the substrate are weakened due to the new bonds formed between the substrate and the enzyme’s active site. This lowers the activation energy for the reaction.

  1. The enzyme-substrate complex then breaks down to release the products of the reaction. The enzyme, like all catalysts, remains unchanged by the reaction and is able to catalyse the same reaction with new substrate particles.
30
Q

Why can’t humans digest cellulose?

A

Cellulose is condensation polymer of beta glucose. Humans cannot digest cellulose because we lack the enzyme cellulase - thus cannot metabolise cellulose thus NO beta glucose

31
Q

Why is fat the main method of storing energy in the body?

A

Fat has a much greater energy content than carbohydrates or proteins so is a more efficient storage of energy

32
Q

Describe briefly 3 steps in the process of digestion and adsorption of triglycerides in the small intestine?

A
  1. Bile emulsifies fats and oils which increases reactive area
  2. Lipase hydrolyses the three ester bonds of a triglyceride into 3 fatty acids and a glycerol molecule
  3. Fatty acids and glycerol pass into the bloodstream
33
Q

Describe briefly where triglycerides are stored in the body, and how they can be used for energy production?

A

Initially triglycerides are re-formed in the liver from fatty acids and glycerol through condensation reactions.

  • Excess triglycerides are stored in adipose tissue.
  • Energy production is by oxidizing the fatty acids
34
Q

How increase in concentration impacts rate of reaction?

A

increase in concentration will increase the number of particles per unit of volume. This will increase the frequency of collisions. Therefore, this increases the frequency of successful collisions which lead to an increase in rate of reaction

35
Q

How increase in surface area impacts rate of reaction?

A

– an increase in surface area per volume results in an increase in the number of particles available to react. This will increase the frequency of collisions. Therefore, the increase in the frequency of successful collisions which leads to an increase in rate of reaction

36
Q

How increase in temperature impacts rate of reaction?

A

increases in temperature will increase the average kinetic energy of the particles. Therefore, the increase in proportion of particles will have the minimum required activation energy. This will increase the frequency of successful collisions which increase the rate

37
Q

How increase in catalysts?

A

Catalyst will provide an alternate pathway with a lower activation energy. Therefore the increase in proportion of particles will have the required activation energy

38
Q

Describe Homogenous vs Heterogeneous Equilibria?

A
  • A homogeneous equilibrium has everything present in the same phase. The usual examples include reactions where everything is a gas, or everything is present in the same solution
  • A heterogeneous equilibrium has things present in more than one phase. The usual examples include reactions involving solids and gases, or solids and liquids
39
Q

Define a standard solution?

A

A solution with an accurately known concentration

40
Q

Why is the Rf values always less than 1?

A

The distance of the samples cannot surpass the distance of the solvent front

41
Q

Distinguish between the terms Separation and Resolution in a chromatographic analysis?

A

Separation represents separated peaks in a chromatogram whereas resolution represents the difference between retention times of the substances

42
Q

What is the relationship between the length of the carbon chain and boiling point? Explain?

A

The longer the carbon chain, the higher the boiling point, as the more carbon and hydrogen atoms there are, the greater the dispersion forces

  1. As hydrocarbons are non-polar they have only intermolecular dispersion forces
  2. The longer the carbon chain, the more C-H atoms there are resulting is greater dispersion forces
  3. Stronger dispersion forces, the higher boiling point
43
Q

Why can’t tertiary alcohols be oxidised?

A

Tertiary alcohols are resistant to reaction with strong oxidising agent. In tertiary alcohols, the carbons attached to the -OH group does not have a C-H bond to break so oxidation cannot occur at the carbon atom