The Tetrels and Pnictogens Flashcards

1
Q

What is an allotrope?

A

Allotropy or allotropsim is the property of some chemical element to exist in two or more different forms, with distinct structure
e.g. dimond, graphite, C60 buckminsterfullerence etc

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2
Q

How happens to the most common oxidation state going down group 14?

A
  • For the top of the group +4 is the most common: carbon, silicon and germanium
  • +2 becomes more favoured down the group
  • with lead stable in +2
  • This is due to the inert pair effect (the tendency of electrons in the outermost atomic s orbital to remain unionised or unshared in compounds of group 13-16 elements) + **relativistic effects
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3
Q

What happens to atomic radius going down group 14?

A
  • Atomic radius gets bigger going down the group
  • This effect results from the fact that electrons are being places in orbitals with increasing principal quantum number and therefore lie further from the nucleus
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4
Q

What happens to ionisation energy going down group 14 (kJ/mol)

A
  • Ionisation energy decreases for the first few elements then stabilises off
  • Decrease is due to the increase in principal quantum number associated with the outermost electrons, resulting in an increased distance from the nucleus (off sets increase in nuclear charge)
  • Ge, Sn and Pb as all proceeded by d-block and f-block electrons which have poor abilities of shielding the outer electrons (d- and f-block contraction) + relativistic effects for Pb
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5
Q

What happens to electron affinity going down group 14 (kJ/mol)

A
  • The electron affinities for C is lower than Si due to the small size of C, leading to increased repulsion when removing an electron
  • Ge and Sn are proceeded by d-block electrons hence experience increased nuclear charge despite being further away
  • Pb is anomalously low due to the inert pair effect + relativistic effects
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6
Q

Methane (CH₄), Silane (SiH₄), Germane (GeH₄), and Stannane (SnH₄), are all group 14 hydrides
What happens to the stability of hydrides going down group 14?

A
  • The stability of hydrides decreases down group 14 (PbH₄ is extremely unstable and has not been isolated)
  • This is due to the M-H getting longer and weaker going down the group due to larger, more diffuse orbitals, more polar bonds, metal not shielded and low-lying LUMOs
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7
Q

Carbon halides are hydraulically stable meaning?

A

It does not react with water/undergo hydrolysis readily

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8
Q

Group 14 halides (Si-Pb) are hydrolytically unstable
Why?

A
  • Although the further down the group the M-Cl bond gets stronger due to increased differences in electronegativitiy, hence greater electrostatic attraction
  • It also means the bond is more polar and more electrophilic metal(loid)
  • And also due to their larger size, they are more easily attacked by nucleophiles
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9
Q

For Ge, Sn, and Pb we can also form MX₂, which are more metallic (bigger difference in electronegativity, why?)
Why are the MX₂ compounds more likely to form?

A
  • Bigger difference in electronegativity (higher ΔΧ) are tetrel is become less electronegative
  • Left and down on the Arkel Ketelaar triangle
  • More likely to form due to the inert pair effect
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10
Q

Halides can also react with alcohols to form

A

M(OR)₄ from the halide
(with the strength of the S-O bond being the driver)

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11
Q

Silcones are?

A

Siloxane polymers

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12
Q

How can we form silicones

A

Through the hydroloysis of silylhalides
Then a condensation reaction
(way to form simple siloxanes)

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13
Q

Polymeric siloxane require three types of monomeric units to be formed
What are they

A

(the cross links are to typically add strength)

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14
Q

Where does the thermal and chemical stability of silicones comes from

A

The thermal and chemical stability of silicones comes from the strength of the Si-C bonds and of the Si-O-Si bridges

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15
Q

Silicones are remarkably inert
What however will they react with?

A

Will react with fluorinating agenets (due to the strength of Si-F bonds is very high, 582 kJ mol⁻¹

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16
Q

Why is the Si-O bond so strong?

A
  • Due to pπ-dπ bonding
  • The filled 2p orbtial of the oxygen donated electron density into the empty 3d of the si
  • (the strength of the silicon-oxygen bonds mean that the chemistry of silicon is dominated by these compounds
17
Q

Tetrahmethylsilane (TMS) is sued as a references for ¹H, ¹³C and ²⁹Si NMR
Why would you use TMS over Silicon tetrachloride for NMR

A
  • Because the central silicon is sterically hindered by the methyl group making it more stable
  • Si-Cl bonds are more polar - more likely to undergo attack (nucleophilic)
  • AND Cl⁻- is a much better LG than CH₃⁻
18
Q

Why are double and triplet bond favoured for first row elements but not for lower down the periodic table?

A
  • Easy to make double and triple bonds with first row elements because the orbital overlap is good
  • e.g. E=O bond (C=O yea, Si=O no)
  • Orbital overlap to make π-bonds with heavier group 14 elements is possible, but σ-bonds will always be preferred
19
Q

If double bonds are not preferred for silicon, how can the geometry of a compound encorage them to form?

A
  • Sterically hindering group can block oligomerisation (bonding with another group)
  • This stops the metal centres polymerising via σ-bonds and forces them to π-bond
  • This can also lead to the molecule no longer being planar
20
Q

What is a ‘paw-paw’ donor-acceptor bonding?

A

Where the same molecule will act as both as lewis acid and a lewis based all at the same time
(much weaker than covalent overlap of two triplet fragments)
e.g. these two Sn are sp² hybridised with a triplet arrangement (like carbenes)

21
Q

What are Zintl ions?

A
  • Clusters from group 14 elements which use cryptand-222 ligands to enable the crystallisation of these compounds
  • In general, a Zintl phases contain a group 1 or group 2 metal, along with post-transition metals (group 12) or the metalloids from group 13, 14, 15, or 16
22
Q

What happens to the Electron Affinity (kJ mol⁻¹) going down group 15

A
  • Nitrogens electron affinity is significantly lower due to the small size of the atom, where adding an electron would lead to increased repulsion
  • P and As have similar electron affinities (rather than a suspected increase for As) due to d-block contraction
  • Sb and Bi have similar electron affinities (rather than a suspected increase for Bi) due to f-block contraction
23
Q

What are the common oxidation states for group 15 elements?

A
  • General trend of s² p³
  • symmetrically half filled p orbital
  • Fewer oxidiation states further down the group due to the inert pair and relativistic effects
24
Q

What forms of nitrogen can be found?

A
  • Predominatly N₂ due to the strong nature of the N-N triple bond (ΔH = 945 kJmol⁻¹)
  • N³⁻ ion does exist, formed when Li metal reacts with nitrogen (of which the lattice energy is high)
25
Q

What forms can phosphorus be found in?

A
  • Because phosphorus is a larger atom allotropes are very common
  • This is because P=P bond are less favourable
  • (The P-P bond is still pretty weak however)
  • Can form a tetrahedron
  • Or black phosphorus which is rippled layers of 6 membered rings
  • Diphosphorus P₂ does exist, but only under extreme conditions
26
Q

White phosphorus (P₄) is pyrophoric
Meaning it is very reactive towards oxygen and ignites in contact with air (reaction shown below)
What is the driving force for this reaction?

A
  • The strong P=O bond
  • This bond is so strong due to pπ-dπ interaction of the oxygen donating e- density from its filled p-orbital into the empty, low-lying d-orbital of phosphorus
27
Q

What forms do As, Sb, and Bi comes in?

A
  • They form layered structures similar to phosphorus
  • Elements become more metallic as the group descends
28
Q

Phosphorus forms two oxides
What are they?

A
  • Phosphorus (V): tetrahedral structure
  • Phosphorus (iii): one LP on each phosphorus
29
Q

Nitrogen forms 7 molecular oxides
What are the stability of them like compared to N₂ and O₂

A

Nitrogen molecular oxides are all thermodynamically less stable than N₂ and O₂

30
Q

Why does nitrogen not form negative oxidation states for N oxides?

A

Because oxygen is more electronegative so always presents as O²⁻

31
Q

The following compounds are group 15 hydrides NH₃, PH₃, AsH₃, SbH₃, (BiH₃ = unstable above -60°C)
What happens to the bond energy and angles going down the group?

A
  • Bond energy decreases down the group, due to decreased stability from larger, more diffuse orbital and hence worse orbital overlap
  • Bond angle also gets smaller going down the group due to bonding going from between hydrides to just between orbtials
32
Q

What happens when you heat phosphorous acis up to 200°C

A

A disproportionation reaction
A way of forming PH₃

33
Q

NH₃ is well known to be basic
Why is PH₃ not basic

A
  • The P-H sigma bonds are mainly between the p-orbitals on the phosphorus and s-orbitals on the hydrogen
  • The 3s orbitals contribute little to the bonding which is where the LP for basicity would come from
  • (Drago’s rules)
34
Q

Phosphines (PR₃) is a good ligand for transition metals
(R = Me, Ph, ₛBu etc)
Why?

A

π-bonding involved overlap between a σ’ orbital on phosphorus and a filled metal d-orbtial

35
Q

MX₃ is formed for all group 15 halide but for MX₅ not all halides are formed
Explain the trend show

A
  • No MI₅ compounds are formed for group 15 because the bonding would involve large valance orbitals on both elements - poor overlap and very weak bonds
  • The larger the group 13 metal and the larger the halide, the larger the orbitals are resulting in worse overlap and weaker bonds
36
Q

How is NF₃ different to NH₃

A
  • Boiling point for NF₃ is much lower due to having no hydrogen bonding
  • They bond have the same trigonal pyrmidal structure with a LP on the Nitrogen
  • NF₃ has a slightly smaller bond angle due to the high electronegativity of fluorine
  • Where the fluorine pulls electron density away from the nitrogen, which results in less electrostastic repulsion between bond pairs
37
Q

This is what PCl₅ appears like in gas phase
How does PCl₅ as a solid

A
  • In the solid state PCl₅ exists as a tetrahedral [PCl₄]⁺ cation and ocetahedral [PCl₆]⁻ anion