The Replicon Flashcards

1
Q

synonymous mutation

A

A mutation in the genetic code that changes the DNA nucleotide sequence and RNA nucleotide sequence but does not ultimately change the encoded amino acid

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2
Q

nonsynonymous mutation

A

A mutation in the genetic code that changes the DNA and RNA nucleotide sequences as well as the encoded amino acid

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3
Q

the replicon

A

A region of a chromosome that replicates as a single unit starting at a specific origin of replication
- a unit of DNA in which individual acts of replication occur; contains an origin and may have a terminus
- can be linear or circular

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4
Q

origin of replication

A

The start point of DNA replication

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5
Q

unidirectional replication

A

Form of DNA replication in which the replication fork proceeds in one direction only
- replication fork created at the origin

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6
Q

bidirectional replication

A

Form of DNA replication in which the replication fork proceeds in both directions
- when origin creates two replication forks that move in opposite directions

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7
Q

plasmid

A

Small extrachromosomal circular DNA molecule that can replicate independently of the main cellular chromosome
- autonomous circular DNA genome that constitutes a separate replicon

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8
Q

extrachromosomal

A

Nucleic acids present in a cell, that are not a part of the main chromosome

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9
Q

in vivo

A

Preforming an experiment within a living organism

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10
Q

in vitro

A

Preforming an experiment under highly controlled conditions outside of a living organism.

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11
Q

how many replicons to bacteria have? how many do humans have?

A
  • bacteria usually only has one replicon
  • humans typically have thousands of replicons in each chromosome
  • ours typically has 10,000 replicons
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12
Q

what is the bacterial genome?

A
  • the bacterial genome is the replicon
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13
Q

what are some examples of replicons?

A
  • bacterial chromosome
  • eukaryotic chromosomes
  • plasmids
  • mitochondrial genome
  • phage
  • virus
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14
Q

how do bacterial chromosomes terminate?

A
  • they may or may not have a terminus
  • most common way is for DNA polymerases to crash into one another (humans do this)
  • E. coli have a different mechanism
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15
Q

what is the termination mechanism E. Coli have?

A
  • there are sequences that designate the termination point
  • in bacteria you do not want DNA replication to go in the opposite direction because the opposite is for transcription - especially for ribosomes
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16
Q

what organelles contain origins of replications?

A
  • nucleus
  • chloroplasts
  • mitochondria
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17
Q

what does the initiation of DNA replication commit the cell to?

A
  • commits the cell to division
  • division must not occur until after replication is completed
  • replication is controlled at the stage of initiation and is highly regulated
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18
Q

what are the ways you can map replication?

A
  • autoradiography
  • fluorescent labelling
  • electrophoresis
  • electron microscopy
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19
Q

what are the types of replication control?

A

single copy and multicopy

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20
Q

single copy

A
  • replicates once alongside bacterial chromosome
  • Usually when the bacterial chromosome itself replicates
  • Have a mechanism to make sure each copy is segregated to each daughter cell
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21
Q

multicopy

A
  • present in more copies than bacterial chromosome
  • small plasmids do this
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22
Q

unidirectional

A
  • replication in only one direction
  • mitochondria
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23
Q

bidirectional

A
  • replication is two directions
  • bacterial and eukaryotic chromosomes
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24
Q

replication fork

A
  • separation of the two strands of DNA
  • at each end of the replication eye
  • also called a theta structure
  • initiated at the origin
  • moves sequentially along DNA
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25
replication eye
opening of the two strands to enable the reading - also called a theta structure in circular DNA
26
prokaryotic replication
- single and circular - competitive inhibition between DNA A and seq A - at the origin seq A binds to the hemimethylated state on the new strand and blocks the binding of DNA A and slows the rate of DNA replication, causing a 13 minute delay - when Seq A binds to DNA is has an affinity for the membrane and pulls the origin to the membrane to hide it from DAM methylase - this also stops DAM methylase from binding as well - Seq A recognizes the origin because it has an affinity for DNA A sites called high affinity binding sites - DNA A binds to these sites but there are not enough for actually replication - bacterial oriC contains 11 GATC/CTAG repeats that are methylated on adenine on both strands - DAM methylates the A on each strand on each strand of the GATC sequence - the new strand contains a non methylated strand - once methylated by DAM methylase, DNA A is able to replicate - it takes 20-40 DNA A proteins to binds at the origin to pull the strands apart
27
what is the role of termination sites and Tus proteins in bacterial replication?
- bacterial chromosome is a single replicon that normally terminates when the replication forks meet - Ter sites serve as a backup to prevent replication from going too far - transcription of major genes is in the same direction as replication - ter sites are pointed in opposite directions - ter sites are pointed in opposite directions and binds to the Tus proteins that blocks helicase thus stopping DNA polymerase - Tus proteins are bounded asymmetrically - one side is bounded alot tighter than the other - if the helicase is going the right way it'll just bounce off but if it's going the wrong way the Tus protein stops
28
why do you need ter sites?
- one side of the DNA pol may be faster than another - this is to prevent replication from crossing into transcription
29
bacteria number of replicons, length, and movement
replicons: 1 length: 4,200 kb movement: 50,000 bp/min
30
yeast number of replicons, length, and movement
replicons: 500 length: 20 kb movement: 3,600 bp/min
31
fruit fly number of replicons, length, and movement
replicons: 3,500 length: 40 kb movement: 2,600 bp/min
32
toad number of replicons, length, and movement
replicons: 15,000 length: 200 kb movement: 500 bp/min
33
mouse number of replicons, length, and movement
replicons: 25,000 length: 150 kb movement: 2,200 bp/min
34
plant number of replicons, length, and movement
replicons: 35,000 length: 300 kb
35
what are the length of eukaryotic replicons?
- 40-200 kb in length - replicons only work once before cell division - a chromosome is divided into many replicons
36
what portion of DNA replication did eukaryotes inherit from archaea?
- Orc1 and Cdc6
37
what are the differences between replication termination for prokaryotes and eukaryotes?
- eukaryotes are terminated by the fusion of replication eyes - no ter sites or Tus proteins
38
what is the cell cycle?
- mother cells divides by mitosis - two daughter cells form and grow - interphase occurs - gap 1 in synthesis - synthesis - gap 2 in synthesis
39
foci
- active replicons are clustered (foci) - 300-500 active sites at any given time - eukaryotic nucleus contains 100-300 foci - one focus can contain more than 300 replicons
40
ORC
- origin recognition complex - a complex of sic proteins that binds to an ARS at the A and B1 sites - 6 protein - about 400 kD (roughly the size of DNA polymerase)
41
how does licensing factor components work?
- necessary for initiation at each origin - is present in the nucleus prior to replication but is activated or destroyed by replication - initiation of another replication cycle becomes possible only after licensing factor reenters the nucleus after mitosis - ORC is already there and bound there - ORC has to bind to ATP, then recruits cdc6 and cdc6 recruits cdt1 - in turn cdt1 recruits MCM 2-7 to the origin site - then DNA synthesis can initiated
42
cdc6
- part of the licensing factor that binds to the orc - recruits cdt1
43
cdt1
- cannot arrive until cdc6 arrives - recruits the helicase - irreversibly committed to replication
44
geminin
- orc normally gets too many helicases, so geminin is recruited and bind to cdt1 so it no longer recruits the helicases
45
MCM 2-7
- a helicase - minichromosome maintenance - 6 subunits - moves in opposite polarity from the direction of the bacterial helicase
46
what is the percentage of eukaryotic replicons active at any given time?
about 15% - if all replicons were acrive, replication could be completed in 1 hour, but the S phase lasts about 6 hours which explains that only 15% of replicons are active at any given time
47
what are the general rules for replication?
- initiation of DNA replication commits cells to division - division must not occur until after replication is completed
48
what does the bacterial origin support?
- initiation of replication - control frequency - segregates replicated chromosomes - not in eukarotes
49
what is controlling reinitiation?
- physical sequestration of oriC - delay in remethylation - inhibition of DNAA binding - repression of DNAA transcription
50
what can the beginning of eukaryotic DNA replication be traced back to?
- archaeal chromosomes - orc1/cdc6 are the same proteins found in archaea and eukaryotes
51
what is the system controlling reinitiation?
- physical sequestration of OriC - delay in remethylation - inhibition of DnaA binding - repression of DnaA transcription
52
oriC
- 245 bp fragment - smallest fragment that can support replication - very AT rich
53
how is eukaryotic replication terminated?
- fusion of replication etes - no ter sites
54
eukaryotic replication
- The A domain is where ORC attaches and is very AT rich - the B domain is where transcription factors attach - once ATP binds to ORC initiation can begin - at the B domain ABF1 stimulates initiation by opening the two strands - then cdc6 binds to ORC which in turn recruits cdt1 - cdt1 recruits MCM which is a helicase - when too many MCM binds, geminin binds to cdt1 to stop recruitment of MCM - now replication can begin
55
mitotic cell cycle
- G1 is the first growth stage - then synthesis occurs - then G2 in another growth phase - then mitosis can begin and the cell can divide - interphase is everything in the cycle except mitosis
56
explain the connection between eukaryotic replication and the cell cycle
- in early G1 ORC is bound - cdc6 and cdt1 are synthesized and binds - in late G1 the helicase and possibly geminin are recruited - then in synthesis, the DNA replication machinery is recruited and synthesizes the DNA to prepare for mitosis - cdc6 and cdt1 are degraded in S phase to prevent reinitiation - mcm is phosphorylated at the beginning of S phase and becomes active by leaving the origin - In the G2 phase all the proteins are degraded - finally mitosis occurs
57
where are MCM proteins in metazoans? in budding yeast?
- metazoans = MCM proteins are in the nucleus throughout the cycle - budding yeast = only after mitosis
58
what does MCM stand for?
minichromosomal maintenance
59
how can ORC, cdc6, cdt1, and mcm be downregulated?
by cdk activity - cell cycle dependent kinase - phosphorylates enzyme
60
when is geminin degraded?
during late mitosis and early G1 - this allows cdt1 to bind which results in the recruitment of the MCM helicase in early G1
61
which of the following proteins or complexes is not a component of licensing factor?
ORC
62
which of the following proteins blocks binding of mcm to the origin
geminin