The Contact Process Flashcards
What does the contact process make?
sulphuric acid (H₂SO₄)
What are the raw materials used in the contact process?
suplhur
air
water
Where is suplhur available?
in fossil fuels and suphide ores
What is a three step brief summary of the contact process?
make sulphur dioxide
convert the sulphur dioxide into sulphur trioxide (reversible reaction)
convert the sulphur trioxide into concentrated sulphuric acid
What is stage 1?
Making the sulphur dioxide
What are the two ways in which you can make sulphur dioxide? (Stage 1)
This can either be made by:
burning sulphur in an excess of air
by heating sulphide ores, like pyrite, in an excess of air
When making the sulphur dioxide, why is an excess of air is used? (stage 1)
so that the sulphur dioxide produced is already mixed with oxygen for the next stage
What is the equation for burning sulphur in an excess of air? (Stage 1)
S(s) + O2(g) → SO2(g)
What is the equation for heating sulphide ores in an excess of air? (Stage 1)
4FeS2(s) + 11O2(g) → 2Fe2O3(s) + 8SO2(g)
What is stage 2?
Converting the sulphur dioxide into sulphur trioxide:
sulfur dioxide reacts with more oxygen to make sulfur trioxide
What is the equation for making sulphur trioxide? What type of reaction is this? (Stage 2)
2SO2(g) + O2(g) ⇌ 2SO3(g)
This is a reversible reaction
In stage 2, which direction is exothermic?
2SO2(g) + O2(g) ⇌ 2SO3(g)
the formation of sulphur trioxide is exothermic (to the right)
What are the conditions of stage 2?
temperature: 450oC
pressure: 1 atmospheres - 2 atmospheres
catalyst: vanadium (V) oxide, V2O5
Explain the conditions of stage 2: temperature
The position of equilibrium needs to shift to the right in order to produce more sulphur trioxide
The forward reaction (the production of sulphur trioxide) is exothermic
If you lower the temperature, the p.o.e. will move to counteract this (move to the right) to produce more heat (Le Chatelier’s Principle)
However:
If the temperature is too low, the rate of reaction becomes too slow; it is not economical
A compromise is chosen:
450°C is a compromise temperature producing a fairly high proportion of sulphur trioxide (percentage yield), but in a very short time (rate of reaction)
Explain the conditions of stage 2: pressure
There are 3 molecules on the left-hand side of the equation, but only 2 on the right:
2SO2(g) + O2(g) ⇌ 2SO3(g)
If you increase the pressure, the p.o.e. will move to counteract this (move to the right) to lower the pressure (Le Chatelier’s Principle)
High pressure also speeds up the reactions as a higher pressure pushes the same amount of gas particles into a smaller volume ensuring that there are more frequent, successful collisions in the same amount of time
However: Economic Considerations
Even at these relatively low pressures, there is a 99.5% conversion of sulphur dioxide into sulphur trioxide. The very small improvement that you could achieve by increasing the pressure isn’t worth the expense of producing those high pressures