tests for convergence Flashcards
geometric series
if abs. value of r is ⟨ 1, converges
Sum of convergent series is (1st term)/1-r
telescoping series
always converges, decompose series via partial fractions, and then cancel out terms until only the sum remains
nth term test
if the limit as n approaches infinity does not equal 0, it will converge
*even if it does equal 0, does not mean it automatically converges
integral test
- f(x) is positive, continuous, decreasing
- if the integral from k to infinity of f(x) converges, then sum of a sub n will converge
- same if integral diverges, sum will diverge
*to see if you should use this, see if you see a derivative for u-sub.
p-series
∑from n=1 to infinity of 1/n ^p
if p ⟩ 1 –> converges
if p ≤1 –> diverges
simple harmonic series
∑1/n –> always diverges
alternating simple harmonic series
converges conditionally (needs the alternator)
direct comparison test
- 0 < a subn < b subn for all n
- if ∑b subn converges, ∑a subn converges
- if ∑a subn diverges, ∑b subn diverges
limit comparison test
a subn > 0, b subn > 0
lim n goes to infinity of a/b = L
1. L is finite and positive
2. then ∑b subn + ∑a subn either both converge or both diverge
alternating series test
- needs an alternator
- lim as n goes to infinity a subn has to go to 0
- an+1 is always ≤ a of n (terms get smaller as series goes on)
if all true, will converge!
alternating series remainder
- an+1 is always ≤ a of n
[S-Sn]=[Rn] ≤ a of n+1
maximum error in approximation is the last term you didn’t use
absolute convergence
- converges w/ or w/o the alternator
- if ∑An abs. converges, ∑[An] converges
- if absolute value converges, the series converges
conditional convergence
- converges only w/ alternator
- ∑An condit. converges, ∑[An] diverges
- the absolute value diverges, but the original converges
Ratio Test
lim n goes to infinity of [(An+1)/An]
1. if limit is less than 1, series converges absolutely
2. if limit is greater than to 1, or goes to infinity, series diverges
3. inconclusive test if series = 1
Root Test
n√[An]
1. if less than 1, converges
2. if greater than 1 or = to infinity, diverges
3. inconclusive if = 0
*same rules as ratio test