Test 2 Flashcards

1
Q

(Ch 6)
a. Define: Alkyl halide
b. Vinyl halide
c. Aryl halide

A

a. Halogen directly bonded to sp3 carbon
b.halogen bonded to sp2 carbon of alkene
c.halogen bonded to sp2 carbon on benzyne ring

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1
Q

(Ch 6)
a. what group are halogens in?
b. describe a c-halogen bond
c. what happens to C and Halogen when they react?

A

a.7A
b. polar; Halogens more electronegative than C, C has partial + charge
c. C can be attacked by nucleophile(New C-nuc bond formed) and halogen can leave with e pair(existing C-X bond broken)

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2
Q

(Ch 6) Alkyl Halide classification:
a. Methyl Halide
b. Primary Halide
c. Secondary Halide
d. Tertiary Halide

A

a. Halide attaches to methyl group
(CH3-X)
b. C bonded to halide attaches to one other carbon
(R-CH3-X)
c. C bonded to halide attaches to two other carbons.
( R )
(R-CH3-X)
d. C bonded to halide attaches to three other carbons
( R )
(R-CH3-X)
( R )

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3
Q

(Ch 6)
a. IUPAC Nomenclature
b. Reaction of Alkyl Halides:
-nucleophilic substitution:
-elimination:

A

a. name as haloalkane, choose longest c chain, use lowest # for position
b.
-C-Nu bond formed and C-X bond broken
-Major product formed + halogen

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4
Q

(Ch 6)
a.Sn2 Mechanism:
b. What type of reaction?
c. what does concerted mean?

A

a. Bimolecular nucleophilic substitution
b. One-step concerted reaction
c. Bond breaking and making occur in the same step “in concert”

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5
Q

(Ch 6) Sn2 cont:
a. Substitution: Reactants and products?
b. define
c. Rxn rate and overall order?

A

a. nucleophile + substrate(electrophile) –> transition state (substrate connected to nuc) –> Nuc-substrate + halogen (leaving group)
b. Halogen atom on alkyl halide replaced(substituted) w/ nucleophile(HO-)
c. Kr[alkyl halide][nucleophile], 2nd

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6
Q

(Ch 6) Sn2 cont:
a. draw and label energy diagram
b. Mechanistic considerations (Walden Inversion):
c. Under what circumstances will this process not occur?

A

a. reactants, transition state (highest energy), products (lowest energy).
b.because it is concerted, Sn2 substitution occurs with the inversion of stereochemistry at the electrophilic center. (like wind inverting umbrella, turns (S) to (R) and vice versa.
c. If the process breaks Cahn Ingold Prelogs by changing the priorities.

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7
Q

(Ch 6) Sn2 cont:
a.Substrate Structure (steric effects and where nuc attacks):
b.Relative rxn rates for sn2 order:

A

a. Nucleophile “attacks” from back side of atom: must overlap back lobe of C-X sp3 orbital.
b. CH3X>1>2>3(3 doesn’t react due to steric hindrance aka too crowded)
c.

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8
Q

(Ch 6)
a.Nucleophilic strength:
b.Trends in Nucleophilicity
c. Polarizability effect of Nucleophilic strength:

A

a. Nucleophiles react faster; strong bases are nucleophiles, but not all strong nucleophiles are basic.
b. -negatively charged nucleophile stronger than its neutral counterpart
-nucleophilicity decreases from left to right on periodic table
-increases down periodic table as size and polarizability increase
c. Bigger atoms have “softer/squishier” shell that can start to overlap the carbon atom from further distance.

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9
Q

(Ch 6)
a.Sn1 mechanism:
b. Rate:
c. What is created and what occurs?
d. Define racemization?

A

a. Unimolecular nucleophilic substitution (only halogen involved in rate determining step)
b. kr[alkyl halide]
c. carbocation intermediate; Nucleophilic attack occurs, giving a mix of inversion and retention, leading to racemization
d. equal mixture of enantiomers. Carbon rehybridizes sp3 C (chiral, optically active) and becomes sp2 C (achiral, optically inactive).

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10
Q

(Ch 6) Sn1 cont.
a. Sn1 steps:
1.Formation of carbocation (what occurs and what is involved)
2.Attack of the nucleophile
3.possible proton inventory

A
  1. rate-determining step, only substrate involved. RACEMIZATION OCCURS HERE: all stereochemical info at electrophile carbon is lost.
  2. Nucleophile attacks carbocation forming product, nucleophile can be very weak bc C+ is a strong electrophile.
  3. If nucleophile is neutral, this step is necessary; If uncharged molecule (alcohol/h2o), the positively charged product must lose proton.
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11
Q

(Ch 6) Sn1 cont.
a. Define energy diagram
b.Stereochemical consequences
-structure:
-nucleophilic attack:
c. what is produced after nucleophilic attack?
d. substituent effects (carbocation stability):

A

a. peak 1 transition state 1, slowest step is rate-determining step (valley), peak 2, low energy products
b. -carbocations sp2 hybridized and trigonal planar
-nucleophilic attack occurs on empty p orbitals, so in Sn1, can occur on top or bottom lobes.
c. mixtures of retention and inversion of configuration at the electrophilic center (if chiral, gets racemized).
d. inductive effect and hypercojugation

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12
Q

(Ch 6) Sn1 cont.
a.order of reactivity:
b. Better leaving group:
c.Inversion and what happens:
1.hydride shift
2.methyl shift
3.why does this occur?
d. retention

A

a. 3>2> (follows carbocation stability)
b. Increases rate of rxn
c. carbocations can rearrange to form more stable carbocation; move the smallest group on adjacent carbon (creates hydride and methyl shift)
1. H- on adjacent carbon moves
2. CH3- on adjacent carbon moves
3. poor nucleophile in sn1 causes it.
d. “retains” bond w/ nucleophile.

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13
Q

(Ch 6)
a. Why are the best leaving groups stable after they leave?
b. which Sn has rearrangements?

A

a.e withdrawing to polarize c atom, stable(not strong base) after leaving, and polarizable to stabilize transition state.
b. Sn1

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14
Q

(Ch 6) Solvent effects Sn2:
a.define its protic state:
b. define its aprotic state:
*(which one does it use?)
c. Sn2 crown ethers

A

a. Solvates nucleophiles, reducing nucleophilicity because of acidic hydrogens (O-H, N-H). BAD for Sn2 nucleophiles (ex, alcohols C6H10).
b. Do not H-bond b/c they dont have acidic protons, so doesnt solvate and allows nucleophile to be more free. SUITABLE for sn2
*uses aprotic solvent
c. All C and O’s are sp3, so structure looks like crown. solvate cation so nucleophilic strength of anion increases.

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15
Q

(Ch 6) Solvent effects of Sn1:
a.define protic state:
Preparation of Alkyl Halides:
b. free radical allylic halogenation
c. allylic radicals
d. resonance delocalization

A

a. BEST bc it can solvate both ions strongly through
H-bonding. The solvent in Sn1 stabilizing high energy intermediate.
b. Halogen placed on carbon directly attached to the double bond (allylic)
c. can be stabilized by resonance (like carbocations).
d.overlap with p orbitals of pi bonds allows an odd electron to be delocalized over two carbon atoms (bond is spread across two c atoms). effective in stabilizing radical.

16
Q

(Ch 6)
a. allylic bromanization:
-where does it occur?
b. allylic positions:
c. Mechanism of propagation steps:

A

a. allylic radicals are resonance stabilized.
-Bromination occurs w/ good yield at allylic positions (sp3 C next to c=c)
b. top and bottom peaks of hexagon.
c. Extraction of allylic H+ allylic radical –> allylic bromide

17
Q

(Ch 6) Allylic halogenation:
a. difficult or easy to occur and why?
b. resonance forms
c. where does Br attach?

A

a.easy bc of extra stability associated w/ allylic radicals bc of resonance.
b. both resonance forms can react, so bromination will occur from both resonance forms to give mix of products
c. where the e “.” is located .

18
Q

(Ch 5) Define
a. superimposible:
b. non-superimposible:
c. Chirality: (superimposible or not?)
d. Achiral:(superimposible or not?)

A

a.mirror image and object are same
b.object and mirror image are different and you can tell them apart.
c.”handedness” (left glove doesn’t fit right) mirror image is different from original object; non-superimposable
d. don’t have handedness; superimposable mirror image and object same

19
Q

(Ch 5) Define
a. Enantiomers (superimposible or not?)
-how do enantiomers relate to each other?
b. Chiral center: (hybridization)
-what about its mirror image?
-what if it has two identical substituents?

A

a. pair of molecules that are non-superimposible (chiral) mirror images.
-similar to each other, but you can tell them apart (same bp, refractive index,etc).
b. tetrahedral sp3, aka asymmetric stereocenter.
-mirror image will have different configuration
- two identical substituents=achiral

20
Q

(Ch 5)
a.Stereocenter/stereogenetic atom:
b.Stereoisomer:

A

a.interchange of two groups gives a stereoisomer (double bonded C atoms & cis-trans isomers)
b.molecules that differ only in arrangement of bonds in 3d space

21
Q

(Ch 5)
a.Cahn-Ingold Prelog Designations:
b.Steps:
1.Breaking ties:
2.Multiple bonds:
c. (R)=
d. (S)=

A

a. Atoms w/ higher atomic # receives higher priority, assign priority to groups
b. 1. Use next atoms along chain of each group as tie-breakers
2. treat double/triple bonds as if they were a separate atoms. (ex C=C, 4 C’s total)
c. (R)= clockwise
d. (S)= counterclockwise

22
Q

(Ch 5) Properties of Enantiomers:
a. Optical Activity:
1. D or +
2. L or -
b. specific rotation equation:

A

a. measured by polarimeter; cant be created from scratch
1. Clockwise
2. Counterclockwise
b. a= a(observed)/c(L)

23
Q

(Ch 5)
a. Define Racemic mixture:
b. Optical purity (enantiomeric excess) formula:
c. When is D/L assigned?
d. when is R/S assigned?

A

a. contains equal amounts of D and L enantiomers. No optical activity. optically inactive reagents combine to form chiral molecules.
b. observed rotation/rotation of pure enantiomer x100
c.assigned to molecule based on experimental observations;enantiomers rotate light in opposite directions same magnitude
d. assigned to ATOM within a molecule based on known structure.

24
Q

(Ch 5)
a.Diastereomers:
b. what is a relation between diastereomers?
c. meso compounds

A

a.Stereomers that are not enantiomers; some matching and some opposite configurations; non-superimposable (chiral) (cis/trans, double bonds)
b. different properties, bp, refractive index, density, so easily separated
c. have an internal plane of symmetry so achiral. if rotated 180 degrees, can be superimposable. achiral with chiral center.

25
Q

(Ch 5)
Nonmobile conformers
a.Allenes:
-hybridization?
-chiral/achiral?
B. biphenyl derivatives:
-which confirmation cant they move to?
-chirality and is it superimposible?

A

a. compounds w/ c=c nonds that share central c atom (sp hybridized)
-chiral w/o chiral compound.
b. conformationally locked in staggered confirmation. cant eclipse
-chiral,nonsuperimposible

26
Q

(Ch 5)
a.Fischer projections:
-horizontal:
-vertical:
b. rules:
b. 2n rule
c. constitutional isomers:

A

a.
-bow tie, outward bonds
-behind plane bonds
b.highest oxidized(w/ most O) at top
can rotate 180, not 90
c chain on vertical line
b. max # of stereoisomers. compounds w/ plane of symmetry may have less.
c. same formula different connectivity.

27
Q

(Ch 4)
a.Chlorination of methane:
b.example of free radical chain rxn:
c. steps of general free radical chain rxn:
1.Initiation:
2.Propagation:
3.Termination:
d.homolytic definition:

A

a.one photon of light=many molecules formed
b.single e- moving on its own through rxn
1. generates radical intermediates
2. intermediates react with stable molecule. produce another reactive intermediate and a product molecule.
3. Side rxns that destroy reactive intermediates, when 2 free radicals join.
d.decomposing into 2 uncharged atoms

28
Q

(Ch 4)
Chain rxn chlorination of methane:
1.Initiation (Formation of Cl atom):
2a. Propagation (Formation of carbon radical) step 1:
2b. step 2
3. Termination

A
  1. Cl molecule splits homolytically into Cl atoms= free radicals (reactive)
    2a.Cl atom collides w/ methane and removes H atom. Then forms free radical + HCl
    2b. methyl free radical=reactive. Collides w/ another Cl molecule; produces methyl chloride and regenerates Cl radical
  2. when any two free radicals join together to produce a non-radical compound. (CH3Cl)
29
Q

(Ch 4)
a.Thermodynamics:
b.Kinetics:
c. Keq of chlorination of methane:

A

a.rxn at eq; Keq= [products]/[reactants]
b. rate of chemical rxns.
c. [CH3Cl][HCl]/[CH4][Cl2]

29
Q

(Ch 4)
a.Thermodynamics:
b.Kinetics:
c. Keq of chlorination of methane:

A

a.rxn at eq; Keq= [products]/[reactants]
b. rate of chemical rxns. kr[A]a[B]b
c. [CH3Cl][HCl]/[CH4][Cl2]

30
Q

(Ch 4)
a. Gibbs free energy:
b.-G:
c.+G:

A

a.amount of energy available to do work; G= energy of products-reactants.
b. Exergonic; Keq>1; favorable and spontaneous and goes to completion
c.Endergonic;Keq<1

31
Q

(Ch 4)
a. enthalpy equation:
b. -H:
c: +H:

A

a.enth. products - enth. reactants; heat released/absorbed during chemical rxns
b. heat released; exothermic
c. heat absorbed; endothermic

32
Q

(Ch 4)
Bond dissociation energies (BDE):
a.exothermic:
b.endothermic:
c. Hrxn equation:

A

a. bond formation releases energy (-BDE)
b. bond formation requires energy (+BDE)
c. [BDE bonds broken]-[BDE bonds formed]

33
Q

(Ch 4)
a. homolytic cleavage
b. higher Ea=
c. lower Ea=

A

a. when bonds break, each atom gets one e-
b. slowest step and will determine rate at which rxn proceeds (rate-limiting step)
c. faster rate, more thermodynamically favorable

34
Q

(Ch 4)
a.primary hydrogen
b.secondary hydrogen
c.tertiary hydrogen
*which has highest H?

A

a. H b. R c. R
R-C-H R-C-H R-C-H
H H R
primary has highest H

35
Q

(Ch 4)
a.Chlorination energy diagram: 1 vs 2 reactivity:
1:
2:
*which is more favored?
b.Stability of radicals:

A
  1. primary
  2. secondary, so H is more negative and has lower Ea, meaning it is more favored.
    b. Me<1<2<3
36
Q

(Ch 4)
a.reactive intermediates:
1.carbocations
-stability order most to least:
-what stabilizes carbocations?
c. 1. inductive effect
2.hyperconjugation:

A

a. short-lived species
1. sp2 hybridized with vacant p orbital
-3>2>1>Methyl
-alkyl substituents
c. 1. e- density donation along sigma bond
2.overlap of sigma bond orbitals with empty p orbital

37
Q

(Ch 4)
reactive intermediates cont:
2.Radical
-order of stability
a. Hammond postulate:
-endothermic:
-exothermic:

A
  1. sp2 hybridized w/ one e- in p orbital
    -3>2>1>methyl
    a.
    -transition sate resembles product (high product on graph)
    -transition state resembles reactant (high reactant on graph)