TENTAPLUGG Flashcards
What are properties of good estimators?
- It is unbiased/validity. The expected value of the sample parameter is equal to the population parameter.
- It is reliable/efficient. The estimator has an as small variance as possible. Generally decreases when sample size increases
Which starting points for CI and hypothesis testing are approximate because of CLT (single population)?
Case 3 and Case 4
What are the assumptions for Case 1 (single pop.)?
- Xi follows a normal distribution
- Sigma2 (pop. variance) is known.
What are the assumptions for Case 2 (single pop.)?
- Xi follows a normal distribution
- Sigma2 (pop. variance) is UNknown
What are the assumptions for Case 3 (single pop.)?
- Xi follows an unknown distribution
- Sigma2 is unknown
- n >= 30
What are the assumptions for Case 4 (single pop.)?
- n >= 40
What are the assumptions for Case 5 (single pop.)?
- Xi follows a normal distribution
- mew and Sigma2 are unknown
Which starting points for CI and hypotheses testing are approximate (double populations)?
- Case 2 (round down v)
- Case 3 and Case 5, from CLT
What are the assumptions for Case 1 (double pop.)?
- Independent samples
- Xi, Yj follows normal distributions
- mewX, mewY, Sigma2X, Sigma2Y are unknown, but Sigma2X=Sigma2Y–> pooled variance S2p
What are the assumptions for Case 2 (double pop.)?
- Independent samples
- Xi, Yj follow normal distributions
- mewX, mewY, Sigma2X, Sigma2Y are unknown, Sigma2X & Sigma2Y are UNEQUAL
What are the assumptions for Case 3 (double pop.)?
- Independent samples
- Xi, Yj follow unknown distributions
- mews and sigma2s are unknown (may or may not be equal)
- nx, ny >= 30
What are the assumptions for Case 4 (double pop.)?
- DEPENDENT samples (matched pair)
- Xi, Yi follows normal distributions, –> Di follows normal distribution
- mews and sigma2s are unknown
What are the assumptions for Case 5 (double pop.)?
- Independent samples
- nx, ny >=40
What are the assumptions for Case 6 (double pop.)?
- Independent samples
- Xi, Yj follows normal distributions
- mews and sigma2s are unknown
What is special about the CI for sigma2x/sigma2y (Case 6)?
The CI in the formula sheet is for sigma2Y/sigma2X, so switch order of x- and y-terms.
Fa;b;0,95 = 1 / Fb;a;0,05