TASK 1 Flashcards
How would you define a random phenomenon?
We call phenomenon random if individual outcomes are uncertain but there in nonetheless a regular distribution of outcomes in a large number of repetitions. “Random” in statistics is not a synonym for “haphazard” but a description of a kind of order that emerges only in the long run.
What is a probabilistic experiment? Offer examples.
A probabilistic experiment is an occurrence such as the tossing of a coin, rolling of a die, etc. in which the complexity of the underlying system leads to an outcome that cannot be known ahead of time.
How would you define the sample space in a probabilistic experiment? Offer examples.
_sum of all possible outcomes in a probability experiment (S) _ Because some outcome must occur on every trial, the sum of the probabilities for all possible outcomes must be exactly 1 _EXAMPLE: Experiment Rolling a die once: Sample space S = {1, 2, 3, 4, 5, 6} OR Experiment Tossing a coin: Sample space S = {Heads, Tails}
What are elementary outcomes? Offer examples.
Each single element (outcome) (EO) ,a possible combination NB. Every elementary outcome is an event but NOT VICE VERSA
What is an event? Is there a difference between events and elementary outcomes?
Event = set of one or more EO’s for a random experiment = subset of sample space NB. Every elementary outcome is an event but NOT VICE VERSA
What are disjoint events? Offer examples of disjoint and non-disjoint events.
Two events (A and B) are disjoint If they have no EO’S in common (A and B) = 0 EXAMPLES _Tossing a coin and getting a heads and a tails at the same time is impossible. _You can’t take the bus and the car to work at the same time. _You can’t get a pay raise and a pay decrease at the same time
What is a probability model?
A mathematical description of a random phenomenon consisting of two parts: a sample space (S) and a way of assigning probabilities to events.
What is a probability, and which values can probabilities have?
The probability of any outcome of a random phenomenon is the proportion of times the outcome would occur in a very long series of repetitions. That is, probability is a long-term relative frequency. P = number of outcomes event A / total number of outcomes VALUES = 0 to 1
What is the complement rule?
The complement of any event A is the event that A does not occur, written as a^c . Complements are “opposites” (ex. “rain” or “not rain”) P (A^c) = 1 - P(A)
What is a uniform probability model?
a model in which every outcome has equal probability. P (A) = number of eo’s in A / number of eo’s in Event
How do you determine the probability of an event using a uniform probability model?
P (A) = number of eo’s in A / number of eo’s in Event It is a model in which every outcome has equal probability.
How are uniform probability models related to simple random sampling, or SRS?
ex. SRS of size n=3 students , (3 randomly chosen kids) each sample of size n=3 is EO and each EO has the same probability of occurring
What is the addition rule and when should it be applied?
General Addition Rule for UNIONS of two events For any two events A and B, P(A or B) = P(A) + P(B) – P(A and B) … for disjoint events is =P (A) + P (B)
What is the multiplication rule and when should it be applied?
The multiplication rule for independent events says that if A and B are independent, then P(A and B) = P(A) × P(B). Two events A and B are independent if P(B|A) = P(B) . Two events A and B are independent if knowing that one occurs does not change the probability that the other occurs. If A and B are independent, then P(A and B) = P(A) × P(B) No, disjoint events cannot be independent. If A and B are disjoint, then the fact that A occurs tells us that B cannot occur. If we know they are disjoint, then if event A happened, we know that event B did not happen, therefore, knowledge of event A affected our knowledge of event B, making them dependent events.
What form does the addition rule take on in the case of disjoint events?
If events A, B, and C are disjoint in the sense that no two have any outcomes in common, then P(one or more of A, B, C) = P(A) + P(B) + P(C).