T1: 4. Covariant Derivative Flashcards

1
Q

In what case is the coordinate derivative of a vector, a tensor?

A

Under linear coordinate transformations; the non-linear term in the product rule disappears.

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2
Q

Define the covariant derivative ∇ (or connection)

A

A linear operator which takes a vector to a rank [1,1] tensors and acts like a derivative.

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3
Q

What does it mean for a covariant derivative to ‘act like a derivative’

A

Obeys the Leibniz (product) rule for derivatives, with some scalar function f:

∇(fV) = (df)V+f∇V

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4
Q

What define a connection to be ‘torision-free’?

A

The connection coefficients are symmetric in the lower indices.

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5
Q

What property does a ‘torsion-free’ connection have?

A

Its action on a scalar (function) is commutative.
[∇_µ, ∇_ν]f = 0

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6
Q

What two properties does the Levi-Civita connection have?

A
  1. It is torsion-free (symmetry in lower indices of connection coeffs/Christoffels)
  2. It is ‘metric compatible’.
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7
Q

What does it mean for a connection to be ‘metric compatible’?

A

Its action on the metric vanishes:

∇_λ g_µν = 0

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8
Q

For a torsion-free metric, how many equations does the cov deriv of the metric give?

A

The number of components of the connection coeffs/Christoffels.

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9
Q

Does the covariant derivative commute with raising/lowering indices

A

Yes!

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10
Q

State the covariant derivative ∇_µ V^ν (on a vector)

A

∇_µ V^ν = ∂µV^ν + Γ^ν(µλ) V^λ

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11
Q

State the covariant derivative ∇_µ ω_ν (on a covector)

A

∇_ν ω_µ = ∂v ω_µ - Γ^λ(vµ) ω_λ

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12
Q

Generally, how many connection coefficients does an n dimensional space have?

A

n^3

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13
Q

Give an expression for the Christoffel

A

Γ_μν^σ = 1/2 g^σλ(∂μ g_λν + ∂ν g_μλ - ∂λ g_μν)

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14
Q

How do we find an expression for the Christoffels?

A

Give cov derivative of metric and find difference.

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