T03/024 : ATOMIC PROPERTIES & CHEMICAL BONDING Flashcards

1
Q

Draw resonance structures of carbonate and determine the most stable one

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2
Q

Define resonance

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3
Q

Give 4 characterisitics of resonance structures

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4
Q

What is an isoelectronic molecule?

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5
Q

What are the defining qualities of isoelectronic molecules?

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  • same number of valence electrons
  • same geometry
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6
Q

Define Lewis structures

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7
Q

Identify the steps in writing Lewis structures

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8
Q

What are the guidelines for Lewis structures

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9
Q

Draw Lewis structure of PCl5

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10
Q

Draw Lewis structure of SF6

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11
Q

Define Formal Charge

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12
Q
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13
Q
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14
Q
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15
Q

Define a chemical bond

A

chemical bond is the force of attraction between 2 or more atoms, ions or molecules that enable formation of compounds or molecules.

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16
Q

Give 6 types of chemical bonds

A

1.Ionic or electrovalent bond
2.Covalent bond
3.Co-ordinate covalent bond
4.Metallic
5.Van der Waals
6.Hydrogen bonds

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17
Q

What causes bonds to form?

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18
Q

Define :
1. Valence
2. Valence electrons
3. Bonding Electrons
4. Non-bonding electrons
5. Electronic theory/Valence Theory/Octet theory of valence

A
  • valence is the number of bonds formed by atom in a molecule
  • valence electrons are the electrons in the outer energy level of an atom that can take part in chemical bonding
  • Bonding electrons are electrons that are actively taking part in bond formation.
  • non-bonding are still available for bond formation.
  • Electronic theory or valence also called the Octet theory of Valence, states
    ‘Atoms interact by electron-transfer or electron-sharing, so as to achieve the
    stable outer shell of eight electrons.’
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19
Q

State the octet theory of valence

A

Atoms interact by electron-transfer or electron-sharing so as to achieve the stable outer shell of 8 electrons.

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20
Q

Differentiate the rule of 2 and the rule of 8

A
  • the tendecy of atoms to have 8 e in their outer shell
  • Since helium has two electrons in the outer shell, for hydrogen and lithium, having one and three (2, 1) electrons respectively, it is the Rule of two which will apply.
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21
Q

Why do atoms form chemical bonds?

A
  • this is to ensure the system achieves the lowest possible potential energy.
  • Bond formation involves attraction forces overcoming repulsive forces between atoms and results in a net lowering of energy.
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22
Q

Define an ionic bond

A
  • electrostatic force of attraction between a cation and anion produced by electron transfer.
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23
Q

State Coulomb’s Law and explain its relation to ionic bond

A

Coulomb’s Law and its relation to ionic bonding:

Coulomb’s Law states that:
F=k(Q1 x Q2)/r^2
k = (2.31 x 10^-19 J nm)

Where:
- F = force of attraction/repulsion between charges
- k = Coulomb’s constant
- q₁, q₂ = charges of the ions
- r = distance between the charges

Relation to Ionic Bonding:

  1. Charge Effect:
    - Larger charges result in stronger ionic bonds
    - Example: Mg²⁺ forms stronger ionic bonds than Na⁺
    - This is why compounds like MgO have higher lattice energies than NaCl
  2. Distance Effect:
    - Smaller distance between ions results in stronger bonds
    - Force of attraction increases as ions get closer
    - This is why smaller ions form stronger ionic bonds
  3. Lattice Energy:
    - Directly related to Coulomb’s law
    - Higher charges and smaller ionic radii lead to greater lattice energy
    - The greater the lattice energy, the stronger the ionic bond

Think of it like magnets - the closer they are and the stronger their charges, the greater their attraction, just as ionic bonds become stronger with higher charges and smaller distances between ions.

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24
Q

What can help you predict the stability of an ionic compund?

A
  • charge of anion and cation
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25
Q

What are the conditions necessary for formation of ionic bond?

A

**1) Number of valence electrons
*** Electropositive atom should have 1, 2 or 3
valence electrons while the electronegative
atom should have 5, 6 or 7 valence
electrons.
* Group 1, 2 and 3 satisfy condition for
electropositive atom, while group 5, 6 and
7 satisfy condition for electronegative
atom.

**2) Net lowering of energy
*** To form a stable ionic compound, there
must be a net lowering of energy.
* This means that energy must be released as
a result of electron transfer and final
formation of the ionic compound.

i) Low ionization energy of electropositive
element.

* The removal of electron from the
electropositive atom must requires energy
which should be low.
ii) High electron affinity for electronegative
atom.

* Addition of the electron to electronegative
must release high energy which is electron
affinity.
iii) High lattice energy.
* The electrostatic attraction between the
cation and anion in the solid compound
release energy which is electrical energy or
lattice energy.

N/B :- net energy should be negative

3.Electronegativity difference between metal and non-metal
- a large difference in electronegativity is needed for formation of ionic bond.
- Preferably a difference of 2 or more
is necessary for formation of ionic
bond between the two atoms.

26
Q

How can net lowering of energy be achieved during formation of ionic compunds?

A
  1. The electropositive element should have a low ionization energy
  2. The electronegative element should have high electron affinity
  3. High lattice energy (large electrostatic attraction between cation and anion)
27
Q

What forces are at play in electron affinity? What leads to a positive electron affinity or negative electron affinity?

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28
Q

What is lattice energy?Differentiate lattice energy formation and

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29
Q

What are the factors governing the formaton of ionic bonds?

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30
Q

Explain the factors that affect lattice energy

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31
Q

look at charges

Between MgCl2 and CaO, which is the most stable ionic compound?What about between Al203 and CaO?Why?

A

The stability of ionic compounds depends on the lattice energy, which is influenced by the charge and size of the ions involved.

Comparison 1: MgCl₂ vs. CaO
- MgCl₂:
- Magnesium has a +2 charge, and chlorine has a -1 charge.
- The lattice energy depends on the attraction between Mg2+ and Cl- but Cl- relatively large ionic radius, reducing lattice energy.

  • CaO:
    • Calcium has a +2 charge, and oxygen has a -2 charge.
    • The charges are higher compared to MgCl₂ O2- vs Cl-
    • Both ions in CaO are smaller than in MgCl₂, which increases the lattice energy due to stronger electrostatic attractions.

Conclusion: CaO is more stable than MgCl₂ due to its higher lattice energy, resulting from the higher charge and smaller ionic radii of Ca2+ and O2-

Comparison 2: Al₂O₃ vs. CaO
- Al₂O₃:
- Aluminum has a +3 charge, and oxygen has a -2 charge.
- The charges are higher, which significantly increases lattice energy.
- Both Al3+, O2- and Ca2+ and O2- further strengthening the electrostatic attraction.

Conclusion: Al₂O₃ is more stable than CaO because of the higher charge of Al3+, leading to much stronger lattice energy.

Summary:
1. CaO is more stable than MgCl₂.
2. Al₂O₃ is more stable than CaO.

This is due to the lattice energy being proportional to the product of the charges and inversely proportional to the sum of the ionic radii.

32
Q

Explain 4 charateristics of ionic compunds

A
  • solid at room temperature
  • High melting points
  • Hard and brittle
  • Soluble in water
  • Good conuctors of electricity in..
  • Do not exhibit isomerism
  • ## Ionic reactions are fast
33
Q

What is the formula for the Born-lande equation?

A
                 N_A * M * z⁺ * z⁻ * e²
U = - --------------------------------------- * (1 - 1/n)
         4 * π * ε₀ * r₀

NA = Avogadro constant = 6.022x1023 atom-1
M = Madelung constant, relating to the geometry of the crystal;
Z+ = Charge on cation
Z- = charge on anion
e- = Electronic charge
ro = Sum of radii of cation and anion
n = Born exponent, typically a number between 5 and 12,
determined experimentally by measuring the compressibility of
the solid, or derived theoretically.
εo = 8.854 x10-12 J-1C2m-1

34
Q

What is the significance of Born-Lande equation?

A

Therefore, two key conclusions about factors that influence lattice
energy of ionic compounds:
1)From U α Z+Z-
The higher the charge on cation and anion, the greater the
magnitude of lattice energy
e.g. U (LiF) < U(CaF2) < U(MgS)

2) U α 1/ro
 The smaller the size of ions, the higher the lattice energy e.g.
U (NaF) > U(NaCl) > U(NaBr) > U(NaI)

35
Q
A
36
Q

What is the Born-Haber cycle?

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37
Q

State Hess’ law

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The total amount of heat evolved or absorbed in a chemical reaction is constant whether the reaction is carried out in a single step or multiple steps.

38
Q

Calculate:
(I)lattice energy using Born-Haber cycle
(ii)Madelung constant using Borne- Lande equation

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39
Q

ionic lattice, exothermix, endothermic, isolated gaseous ions

Define
(i)Lattice Dissociation Enthalpy
(ii)Lattice Formation Enthalpy

A

(i)Lattice Dissociation Enthalpy
(ii)Lattice Formation Enthalpy - the enthalpy change…

40
Q

How does charge density influence lattice enthalpy and melting points?

A
41
Q

Which substance in the the following pairs has the larger lattice
enthalpy?
a) NaCl or KCl b) NaF or NaCl
c) MgCl2 or NaCl d) MgO or MgCl2

A

(a) KCl
(b)NaF
(c)MgCl2
(d) MgO

42
Q

charge, lattice enthalpy

Magnesium oxide is used to line furnaces. Why?

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43
Q

Explain trends of thermal stability and decomposition down Group 2

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44
Q

Define and state whether they are exothermic and endothermic :
1.Standard Enthalpy change of formation
2.Standard Enthalpy Change of Atomisation
- enthalpy of sublimation
-
3.First Ionisation energy
4.Second ionisation energy
5.Electron affinity

(if you’re using 1 atom of a molecule divide the energy of atomisation by no. of atoms in that molecule)

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45
Q

Why are lattice compunds formed at a lower energy state than the reactants

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46
Q

Calculate the ionisation energies of Mg^2+
(Calculate the change in energy in formation of Mg^2+ and Al^3+)

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47
Q

Differentiate hydration and lattice enthalpy

A

for ionic compund to dissolve, hydrattion > lattice

48
Q

Define enthalpy of solution

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49
Q

Define enthalpy of hydration

A
  • multiply by no of ions formed
50
Q

Define solvent-solvent intermolecular attractions

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51
Q

Describe the relationship btn The enthalpy of solution, ΔHsolution, enthalpy of hydration,
ΔHhydration, lattice energy and solvent-solvent intermolecular
attractions, ΔHosolvent-solvent

A
ΔH°sol = ΔH°LE + (ΔH°hyd(anion) + ΔH°hyd(cation)) + ΔH°solvent-solvent
52
Q

Explain how these factors affect solubility :
1. Solvent
2. Lattice energy
3. Enthalpy of hydration
4. Enthalpy of solution
5.

A
53
Q

what is the Effect of the Size and charge of ions on LE and ΔHhydration:

A
  • compounds with smaller size have higher hydration enthalpy …
54
Q

Explain the trends in Lattice energy and melting points in : MgCl2, CaCl2, Mg0 and NaF, NaCl, NaBr

A
55
Q

What is the lattice energy for CaCl2 given the following thermodynamic
data.
a) Ca2+(g) + 2Cl-(g) →CaCl2(s)
b) sublimation energy of calcium = +178 kJ/mol
c) first ionization of calcium = +590 kJ/mol
d) second ionization of calcium = +1,150 kJ/mol
e) bond dissociation of Cl2(g) = +244 kJ/mol
f) electron affinity of Cl- = -349 kJ/mol
g) enthalpy of reaction or formation = -326 kJ

A
56
Q

If the lattice energy increases with charge and the association of
oppositely charged ions is a stabilizing force, can NaF form, with Na+2 and
F-2?

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57
Q

Use the thermodynamic data of CuF given below and
other information from inorganic chemistry to
determine the value of Madelung of CuF. Energy is in
kJ/mol and eV.
Cu(s)→Cu (g) = 339.
Cu(g)→Cu+
(g) + e− = 745.
F2(g)→2F(g) = 243.4.
F(g) + e−→F−
(g) = -349.
Cu+
(g)→Cu2+
(g) + e =1960.
Cu(s) +½ F2 (g) →CuF (s) = -140.
Give your final answer to 2 decimal places.

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58
Q

Describe the valence bond theory

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59
Q

What are the main features of the valence bond theory?

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60
Q

What are the different bond types?

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61
Q
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