Study Test Questions D1 Flashcards
If the peak to peak voltage is 588.4 and the heating load is 2000watts of heat what is the resistance of this heat?
Peak to peak voltage / 2 =
peak voltage x 0.707 = E (RMS)
R= E*2/P
588.4/2= 294.2Em x 0.707= 208E
208*2\2000=21.632 ohms
If a source has an instantaneous voltage of 50 at 18• degrees, what would the instantaneous voltage be at 80degrees?
Instant to peak voltage
50E x sine 18• = 161.8Em
First angles max voltage to another angle at max voltage.
161.8Em x 80• = 159.34Em
State three reasons why alternating current is used more than direct current?
Cheaper, smaller, simpler, the step up or step down fiction of a transformer
List five applications where direct current is preferred or required instead of alternating current.
Mining, high intensity light sources that use carbon arcs, electro-plating, battery charging, precise speed, synchronized motors and alternators
What does Epp stand for?
Peak to peak value
2 X the peak
What is another name for RMS OR ROOT MEAN SQUARE?
Effective Value
At what angle in a sine wave does peak value occur?
90° and -270°
With respects to the peak value, what is the average value of an AC sine wave?
0°
With respects to the peak value, what is the average value of one alternation of an AC Sine wave?
.637
What two meters must be use to determine the effective resistance of an AC circuit?
Watt meter and amp meter
Ohm and volt meters might explode
What term is used to refer to the circulating currents in a magnetic core?
Eddy currents
As the frequency of the AC Increases, the effective resistance_____________.
Increases
What are the three formulas for finding Frequency, voltage and number of field poles?
F= PxN/120
N= 120xF/P
P= 120xF/N
P= poles N= speed in rpm F= Frequency
The peak power in an AC lighting circuit is 1200w. What is the effective power in that circuit?
P= 0.5 x Pm
= 0.5x1200w
=600w
What is the instantaneous voltage at 30° into the AC cycle on a sine wave with an effective value of 480E?
E= 0.707x Em
Em= E/0.707
= 480/0.707x VOLTAGE
=679 Em
e = sine 30°x 679V
=0.5x 679v
= 339.5e
If an AC source with a peak voltage of 339.4 Em is placed across a load with a resistance of 288ohms, what power will the resistance dissipate?
E= 0.707 x Em
P= E*2/R
200w
What is the frequency of an alternating voltage produced by a 10-pole alternator turning at a speed of 600rpm?
F= PxN/120
50hz
An turns at a speed of 450 rpm and produces an alternating current of 60 Hz. How many poles does this alternator contain?
P= fx120/ N
16 poles
At what rpm must a prime mover turn a six pole alternator to produce an alternating voltage with a frequency of 50Hz?
N= 120xF/P
1000rpm
What is the effective voltage of a sine wave with a peak value of 679 volts?
E = Em x 0.707
480.053 E