Study Questions #4 - 50-85

Question 1

Show the output produced by the following program fragment.
int i = 1;
int j = 2;
i = + - + - + - j;
printf("%d %d\n", i, j);

Answer 1

-2 2

Question 2

Show the output produced by the following program fragment.
int i = 1;
int j = 2;
i = - + - + - ++ j;
printf("%d %d\n", i, j);

Answer 2

-3 3

Question 3

Show the output produced by the following program fragment.
int i = 1;
int j = 2;
i = + - + - + -- j;
printf("%d %d\n", i, j);

Answer 3

1 1

Question 4

Show the output produced by the following program fragment.
int i = 1, j = 2;
int k = 3, m = 4;
i += j - (k *= m++);
printf(“%d %d %d %d\n”, i++, ++j, k–, –m);

Answer 4

-9 3 12 4

Question 5

Show the output produced by the following program fragment.
int i = 1, j = 2, k = 3, m = 4;
i *= –j * (k *= –m);
printf(“%d %d %d %d\n”, i++, ++j, k–, –m);

Answer 5

9 2 9 2

Question 6

Show the output produced by the following program fragment.
int i = 1, j = 2;
int k = 3, m = 4;
i %= j++ % (k += –m);
printf(“%d %d %d %d\n”, i++, ++j, k–, –m);

Answer 6

1 4 6 2

Question 7

Show the output produced by the following program fragment.
int i = 1, j = 2;
int k = 3, m = 4;
i *= j / - (k -= ++m);
printf(“%d %d %d %d\n”, i++, ++j, k–, –m);

Answer 7

1 3 -2 4

Question 8

If the value of n is 4 and m is 5, will the value of ++(n * m) be 21? Explain your answer.

Answer 8

++(n * m) = 21. The 4x5 will be evaluated first and then the ++ will be added after (the brackets has precedence).

Question 9

In which order the following operators will be executed:

1. i j k

Answer 9

Will be executed from left to right*.

1. The less than will be evaluated before the two logical or’s.
2. The less than will be evaluated before the two logical and’s.
3. Less than, and, or
4. Less than, left to right.
5. Left to right.
6. less than, equal, and
7. less than, not equal, or

Question 10

Show the output produced by the following program fragment.
int i = 2, j = 3, k = i * j == 6;
printf(“%d\n”, k);

Answer 10

1

Question 11

Show the output produced by the following program fragment.
int i = 5, j = 10, k = 1;
printf(“%d\n”, k > i < j);

Answer 11

1

Question 12

Show the output produced by the following program fragment.
int i = 3, j = 2, k = 1;
printf(“%d\n”, i < j == j < k);

Answer 12

1

Question 13

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, i % j + i < k);

Answer 13

0

Question 14

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, i % j + i < k );

Answer 14

0

Question 15

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, k = i * j == 6 );

Answer 15

0

Question 16

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, i < j == k < i );

Answer 16

0

Question 17

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, k > i < j );

Answer 17

1

Question 18

Show the output produced by the following program fragment.
int i = 3, j = 4, k = 5;
printf(“%d\n”, i < j || ++ j < k );
printf(“%d %d %d\n”, i, j, k );

Answer 18

1

3 4 5

Question 19

Show the output produced by the following program fragment.
int i = 7, j = 8, k = 9;
printf(“%d\n”, i – 7 && j ++ < k );
printf(“%d %d %d\n”, i, j, k );

Answer 19

Error. The i-7 is not legal. It is undefined.

Question 20

Show the output produced by the following program fragment.
int i = 7, j = 8, k = 9;
printf(“%d\n”, ( i = j ) || ( j = k ));
printf(“%d %d %d\n”, i, j, k );

Answer 20

1

8 8 9

Question 21

Show the output produced by the following program fragment.
int i = 1, j = 1, k = 1;
printf(“%d\n”, ++i || ++ j && ++ k );
printf(“%d %d %d\n”, i, j, k );

Answer 21

1

2 1 1

Question 22

Show the output produced by the following program fragment. Assume that i, j, and k are int variables and you
compile the segment using C99. What will be the produced output if i, j, and k are bool?
i = 0; j = 1; k = 2;
printf(“%d %d %d\n”, i, j, k);
printf(“%d %d %d\n”, i–, j–, k–);
printf(“%d %d %d\n”, i, j, k);

Answer 22

int 0 1 2
0 1 2
-1 0 1
Bool i – not allowed for bool.

Question 23

Show the output produced by the following program fragment. Assume that i, j, and k are int variables and you
compile the segment using C99. What will be the produced output if i, j, and k are bool?
i = 0; j = 1; k = 2;
printf(“%d %d %d\n”, i, j, k);
printf(“%d %d %d\n”, i++, j++, k++);
printf(“%d %d %d\n”, i, j, k);

Answer 23

int 0 1 2 bool 0 1 1
0 1 2 0 1 1
1 2 3 1 1 1

Question 24

Show the output produced by the following program fragment. Assume that i, j, and k are int variables and you
compile the segment using C99. What will be the produced output if i, j, and k are bool?
i = 0; j = 1; k = 2;
printf(“%d %d %d\n”, i, j, k);
printf(“%d %d %d\n”, –i, –j, –k);
printf(“%d %d %d\n”, i, j, k);

Answer 24

int 0 1 2
-1 0 1
-1 0 1
Bool –i not allowed for bool.

Question 25

Show the output produced by the following program fragment. Assume that i, j, and k are int variables and you compile the segment using C99. What will be the produced output if i, j, and k are bool? i = 0; j = 1; k = 2; printf("%d %d %d\n", i, j, k); printf("%d %d %d\n", ++i, ++j, ++k); printf("%d %d %d\n", i, j, k);

Answer 25

int 0 1 2 bool 0 1 1 1 2 3 1 1 1 1 2 3 1 1 1

Question 26

Is the following if statement legal? if (n >= 1 ); If so, what does it do when n is equal to 5 and when n is equal 15?

Answer 26

There is no syntax error but there is a logical error. When n=5 it prints “n is between 1 and 10”. When n=15 it also prints “n is between 1 and 10”. As there is no && between the two evaluations and the second expression doesn’t have the n before the evaluation.

Question 27

What does the following statement print if i has the value of 17? What does it print if i has the value 31? printf("%d\n", ++i >= 0 ? ++i : --i);

Answer 27

17 = 19. 31 = 32

Question 28

What does the following statement print if i has the value of 17? What does it print if i has the value 31? printf("%d\n", ++i >= 0 ? ++i : (i-=10));

Answer 28

When 17, it prints 19. When 31, it prints 33.

Question 29

The following if statement is unnecessarily complicated. Simplify it as much as possible. (Hint: the entire statement can be replaced by a single assignment.) if( age >= 13) if( age

Answer 29

if ( age

Question 30

Convert the following conditional expression to traditional if statement i = j < k ? l > m ? 1 : 2 : n == p ? 3 : 4;

Answer 30

Convert i = j < k ? l > m ? 1 : 2 : n == p ? 3 : 4;

Question 31

``` What value is assigned to fee by the if statement when speed is 75? if(speed > 35) fee = 20.0; else if(speed > 50) fee = 40.00; else if(speed > 75) fee = 60.00; ```

Answer 31

40

Question 32

``` What value is assigned to fee by the if statement when speed is 75? if(speed > 75) fee = 60.0; else if(speed > 50) fee = 40.00; else if(speed > 35) fee = 20.00; ```

Answer 32

40

Question 33

Which if statement in the above two questions seems reasonable?

Answer 33

I am unsure what this question is looking for

Question 34

``` What output does the following program fragment produce? (Assume that i is an integer variable) i = 1; switch (i % 3) { case 0: printf("zero"); case 1: printf("one"); case 2: printf("two"); } ```

Answer 34

onetwo

Question 35

``` What will be printed by this switch statement if the value of color is 'R'? switch(color) { case 'R': printf("red\n"); case 'B': printf("blue\n"); case 'G': printf("green\n"); } ```

Answer 35

red Blue Green ( no break statement)

Question 36

``` What output line(s) are displayed by the statements that follow when grade is 'I'? When grade is 'B'? and When grade is 'b'? switch(grade) { case 'A': points = 4; break; case 'B': points = 3; break; case 'C': points = 2; break; case 'D': points = 1; break; case 'E': case 'I': case 'W': points = 0; } if(points > 0) printf("Passed, points earned = %d\n", points); else printf("Failed, no points earned\n"); ```

Answer 36

“Failed, no points earned”