Study Flashcards
How is this implicit equation differentiated?
x^2 +y^2 = 25
2x + 2y(dy/dx) = 0 since differentiating with respect to x so (dy/dx) is written
How is the tangent line to a point on a function?
By first differentiating to find the derivative, and then plugging in the x and y values at the point to find slope and using point slope formula to complete
Differentiating to find the derivative, and then plugging in the x and y values at the point to find slope and using point slope formula to complete
Finding the tangent line to a point on a function
Derivative of arcsin
1 / √1-x^2
1 / √1-x^2
Derivative of arcsin
Derivative of arccos
-1 / √1-x^2
-1 / √1-x^2
Derivative of arccos
Derivative of arctan
1 / 1+x^2
1 / 1+x^2
Derivative of arctan
Derivative of arccot
-1 / 1+x^2
-1 / 1+x^2
Derivative of arccot
Derivative of arcsec
1 / |x|√x^2 - 1
1 / |x|√x^2 - 1
Derivative of arcsec
Derivative of arccsc
-1 / |x|√x^2 - 1
-1 / |x|√x^2 - 1
Derivative of arccsc