structures Flashcards

1
Q

dead load and live load

A

dead load and live load
dead loads
are permanent static loads on a structure that remain relatively constant overtime.
example: weight of the structure itself, beams, walls.

love loads are produced by the occuoancy

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2
Q

cold form sections

A

sreel sheets.
They are of extremely thin profiles.
Probles
1.2mm, 2mm, 3mm.
-
example
:
angle iron
c section
“Built up sections” are made up from two or more or hot rolled sections exclusively.
cold formed
They are made by means of connecting them.

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3
Q

lateral torsional buckling

A

lateral torsional buckling
This occurs when the load applied on the flexural member causes it to displace laterally and twist.
The displacement occurs due to the magnitude of the applied load and the twisting occurs if the
torsional Stiffness of the member section is insufficient applied. If the member u
In comparison to the load
Us more prone to lateral torsional buckling, it has a
smaller flexural capacity: the member will fail eavily. The member is prevented from developing is full
flexural strength.

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4
Q

cavity walls

A

A Two single leat walls built with a gap
in-between.
I act as one wall
m
There are Steel ties built into them, tying them together - Cavity ties.
-
3. Cavity ties should be provided at Spacing go 900mm horizontally & 28450mm vertically

4* Each single leat wall can be of a different thickness

These walls have better thermal and acoustic insulation

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5
Q

faced walls

A

Faced wall
a faced wall is a wall built of two different material
It is structurally treated as abre same thickness wall
built with weaker material.

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6
Q

factors affecting the strength of a slender wall

A

All Factors pertaining to short walls (In the Same way)
2) Number and Sizes of Caps at the edges off Mostar joints. ↑ ↓
I
3) Lateral Load on wall (wind etc.) ↑ ↓

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7
Q

strength properties of timber

A

Tension Parallel to grain.
Bending Parallel to grain.
Compn // grain
Compn perpendicular grain
Shear // Grain
Modulus of Elasticity.
Perpendicular

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8
Q

factors affecting the strength properties of timber

A

Moisture in Timber
2) Growth characteristics.
3) Duration of Load
4) Size & Shape of Member

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9
Q

models of failure of solid timber flexural members

A

Splitting of Bottom Fibre
2) Lateral Torsional Buckling.
3) Shearing along Grain.
Members
4)Bearing at supports at concentrated loads
5)deflection

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10
Q

fiber saturation point

A

When Timber starts drying first the free moisture is evaporated Ones the total amounts of free moisture is evaporated, the timber has reached the Fiber Saturation Point

When timber dries further than “Fibre Sat point”,”
*Strength proporties will increase Incect or fungal attacks will decrease

at this point the moisture Content is about 25% - 30%
Only the bound moisture is present
timber will not have any reduction in vol

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11
Q

cellular walls

A

The stiffness of a cellular wall is greater since the overall thickness is more and slenderness is less

It has more strength for a Smaller amount of material

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12
Q

factors of affecting the load transfer capacity

A

nail joints

diameter of nail Penetration of head point
Penetration of point side
Strength class of timber
Number of nails.
*hammered into Joints
*Clean Shaft and point

screw joints
Should be inserted perpendicular
to grain
Point Side penetration -2x
Number of screw.
Strength Class of timber.
*transfer Shear load as well
as withdrawal loads.
* driven into joints.

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13
Q

Why is timber Considered as an hygroscopic and an isotropic material.
2020/

A

hygroscopic material - Possesing the ability to absorb and Shred water from a Environment

isotropic-

Proportis of timber material does depend on direction. Unlike steel which ever the direction you take strength properties remain the same

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14
Q

timber seasoning

A



Timber Seasoning
I brought downto equilibrium moisture contenter this process. is called timber seasoning.
Go air dried.
kiln.
* timber treatment is to make sure that it’ll not decay, not attacked by insects, fungi.
local timber -graded into a grades

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15
Q

method of treating timber

A

method of treatment.
1 Brush application / Sprayru 2) Open tank method
3) Hot & Cold Tank method. 9) Pressure Treatment

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16
Q

Wood Based Products.

A

Wood Based Products.
1 Particle Board -chip bearch.
a) Fibre Board (you can’t see particles in this
high
MDF, HDF.
(medium
-3) Ply wood
density fibre
t
Built-up Sections
3) Laminated Timber-

17
Q

advantage of plywood

A

advantage of plywood
* you have grains running in both directions, good strength in both directions.
* Cost effective.

18
Q

why masonary walls should not be subjected to bending moments, unless accomplained with a sufficient Compressive load.

A

Masonary is generally very good in resisting compression has good Compressive strength…

However it is weak
when subjecte to tensile strength.

If a masonary wall is axially loaded and there is a chance of it built buckling and falling, as it will be in both tension and compression

Since masonary is poor in bending and tension, the wall will crack (assuming that self weight is 2000)
axial Toad
If theres the wall was an elastic material & the Stress
distribution will be (draw)
له
any element subjected to compression can buckle and it is one mode of faliure

Tension develops and then the wall.
fails

Tention develops on the inner curve of the “Column and Cashing develops so the wall fails due to buckling & Crushing.

19
Q

effective thickness

A

its not the actual thickness of the wall its effective thickenss depebds on varius factors such as

Factors affecting effective thickness.
Coefficient of stiffness (K)
thickness of wall (t).
gap between Piers from center to center (SP)
(4 breadth of pier (bp).
Thickness of wall with Pier (tp)

How effective thickness varies with thos factors
(K) increases (+) EFincreases ↑
(SP) increases. EF (bp) increases t
(TP) increases

BASICALY WHEN ALL THIESE INCREASE ET INCRESE

20
Q

Why 2 different PFOS is applied for love load and dead load

A

Pfos dead load= 1.4
PFOS live load= 1.6
Live loads create uncertainty due to its variance therefor it requires higher PFOS comp dead load which certain and can be calculated accurately

21
Q

Slenderness ratio

A

When slenderness ratio increases the tendency to buckleup increases

22
Q

Factors effecting the strength of slenderwalls

A

1.Slenderness ratio of the walls
2.Gaps in the edges of the wall
Due to shrinkage and workmanship motabed dsnt continue right throughout the bed
Lateral loads (wind load) acting on the load increases the weaker the wall

23
Q

Glu laminated timber

A

Glu large number of thin planks which is horizontal or vertical laminated, glu planks in the grain directing the longitudinal direction

24
Q

Adv laminated timber

A

Larger cross sections are possible by stacking on top of each other

Larger longer members by gluing and by vertical joints shouldn’t coincide

Better quality timber
By removing deflect and gluing the planks again

Efficient sections

By the top and bottom most plank has a strong variety of timber middle weaker timber where the stresses are low. Aka selective layering

Weaved members are possible
Grains to the longitude axis there for stronger

Easy cheap to treat

25
Q

Why masonry walls should not be subjected to bending moments unless accompanied by sufficient compressive loads

A

Masonry good atresistong compression not at tension/tensile strength

If axialy loaded it may buckleup and fail in both tension and compression

Since it’s poor at bending and tension it will Crack

Under compression ot will buckleup

Tension develops on the inner curve the column crushing develop and the walls fail.

26
Q

Modes of failure of solid timber flexual members

A

Splitting of bottom fibers
Tensile strength affected over the allowable stress the bottom fibers splits

Lateral torsional buckling
Bottom fibers stays straight while the top fibers buckle causing the timber to twist
Sjear along the grain
Timber is weak in the horizontal shear.
Timber is strong g on the horntal shear

Deflection (draw)

Bearing at supports at co centrated loads

27
Q

Moisture content

A

%of water contained in timber

Moisture cont= weight if water in timber sample/ weight of water in dry timber sample × 100

moisture will! The strength of the timber and will decay
As it’s subjected to seasoning

28
Q

Fiber saturation point

A

When timber starts drying first free moisture evaporated (water inbetween the cells draw)

When evaporated ot reaches its first evaporated point. The moisture content is 25-30%

Only bind moisture remains( moisture inside the cell)

Timber will not have any reduction in volume, strength proposes increases. Insect and fungi attacks will decrease.

29
Q

Equilibrium moisture content

A

When u further dry timber than bond moisture will start to evaporate then timber cell tubes will contract and the volume of the timber will reduce.

Below fiber saturation point it will reach the moisture content. This os where we use are timber structuraly

Moisture content is 8-20%

30
Q

Factor effecting the strength properties of timber

A

Moisture in timer
Growth characteristics of timber- slope of grains , knots and waves

Duration of loads

Size and shape of timber

31
Q

Hudroscopic

A

Possessing the ability to absorb and shed water from env to the env

32
Q

Composite slabs

A

Precast + insitu cast
AdV

Insitu conc= pured to obtain the thickness to woth hold the load

Lighter oannels easy to transport and cheaper
Form work not needed pre cast pannel act as a deck

Series of simply supported pannels

33
Q

Pre stressed concrete advantage

A

Small ant of construction material

Longer soan and length can be achieved

Few joints needed than traditional RC there low maintenance

Reduce the formwork as multiple uses of formwork is possible

Rapid construction with better quality

Requires small amt of construction materials

34
Q

DISADVANTAGES OF PRE STRESSED CONCETE

A

REQUIRE HIGHER strength concrete amd higher Tensile strength

Requires additional special equipment like Jackson and Anchorage
Concrete pretending requires skilled technology and high skill workers

Higher construction cost than RCC

35
Q

Role of reinforcement on a concrete beam

A

Reinforcement are designed to carry transverse external loads,

Loads cause bending shear and tortion across their lenth

Concrete stronger in compression not jn tension

Steel reinforcement is to take Tensile stress of the reinforce concrete

36
Q

Safe bearing capacity of soil

A

Dense soil has high bearing capacity
Loose clay has low bearing capacity
Peat has no bearing capacity
Normal soil has a about 100m

Geotypicak surveys are dine to find the soil properties msucj a s the bearing capacity.
Most typical foundation is pad footing provided separately for each column

And the column are categorized into shallow and deep foundation