Structural and Compositional Characterisation of Materials Flashcards

1
Q

State the 3 kinds of microscopy.

A

Projection image
Optical image
Scanning image

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2
Q

How does projection image microscopy work?

A

An object is placed in from of a point source of illumination.

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3
Q

How does optical image microscopy work?

A

Object is magnified using conventional lenses

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4
Q

How does scanning image microscopy work?

A

Each point of an object is presented serially.

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5
Q

How does a field ion microscope work?

A

High potential is applied between a very fine tip of radius r and a scene at distance R (magnification R/r)
A low pressure inert gas is maintained. Gas atoms are ionised in the very high field near the surface of the specimen.
Each ion is accelerated towards the screen which contributes a speck if light to the image (phosphor screen)
Ionisation occurs preferentially above the atoms which protrude the specimen surface.

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6
Q

What are the limitations of field ion microscopes?

A

Only conducting samples can be studied (conductor or semi-conductor)
Only the surface can be studied which may not be representative of the bulk.

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7
Q

Explain how time-of-flight mass spectrometry works.

A

Aim to determine the elements by mass number and isotopes.
Vaporised sample injected at low pressure. Electron gun fires and kooks an outer electron out of orbit forming positive ions.
Positive ions accelerated by electric field to a constant KE.
Positive ions with smaller m/z will take longer to move through drift area.
Ions distinguished by different flight times by generating a small current when reaching a sensor.

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8
Q

Explain how positive sense atom probe works.

A

Aim to map the atom concentration within a given volume.
High potential or short laser pulse us applied to the tip, a layer of ionised atoms is stripped from the surface.
Ionised atoms will accelerate towards an imaging screen which is specifically orientated so that the ion falls over a hole in the fluorescent screen which leads to a TOF mass spectrometer.
The mass spectrometer can then identify the element within the sample.

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9
Q

What are the limitations of atom probe?

A

Only conducting samples can be studied.
Material needs to be needle shaped specimen
Only a volume of 20x20x50nm can be studied at a time.

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10
Q

Describe Abbe’s theory of image formation.

A

Interaction of illuminating beam and the sample leads to diffraction.
Objective lens corrects the diffraction and a pattern is formed at the back focal plane.
Waves propagate to the image plane and re-interfere to form a magnified image of the sample.
Finite size limits the maximum angle of diffraction collected which limits the smallest features to be seen.

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11
Q

Explain the Rayleigh criterion.

A

Rayleigh’s criterion specifies the minimum separation between two light sources that may be resolved into distinct objects.
This is when the maximum of one diffraction pattern caused by the circular aperture coincides with the minimum of the other diffraction pattern.
See notion answers

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12
Q

Explain numerical aperture.

A

In a microscope, NA is important as it relates to the resolving power if a lens.
A lens with a large NA will be able to resolve finer details.
Lenses with larger NA will also be able to collect more light and so give brighter images. Another way to describe this situation is that the larger the NA the larger the cone of light that can be brought into the lens and so the more diffraction modes will be collected.
Thus the microscope has more information to form a clear image, hence its resolving power will be brighter.

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13
Q

What is the role of a condenser lens?

A

It is the lens that focuses the illuminating beam into the specimen.

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14
Q

What is the role of the objective lens?

A

The lens that leads to the diffraction pattern in a real image.

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15
Q

What is the role of the projection lens?

A

The lens that is used to magnify the image to give a final upright (virtual) image.

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16
Q

Describe an optical lens.

A

Glad with spherical or near spherical polished surfaces, coated to minimise reflection so that light refracts from the surface.
Used in combinations to minimise spherical and chromatic aberrations.

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17
Q

Describe a magnetic lens.

A

A magnetic field (solenoid) is created in which electrons are focus by having a decreasing radius to spiral about the optical lens.
Lenses always convergent
Electron lenses have both spherical and chromatic aberrations
The aberrations of the lenses scale with focal length. Objective lens focal length is just a few mm are used and sample sits in the magnetic field of the lens

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18
Q

Describe how spherical aberration arises.

A

Lenses are made spherical and is not made in the ideal shape for focusing.
Arises because of different path lengths of different rays from an object point to the image point.
Rays furthest from optical axis brings rays to focus near the lens (marginal focus) than does the central portion of the lens (axial focus)
A disk of least confusion exists at the best compromise position of focus.
Check notion to see diagram.

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19
Q

Explain how chromatic aberration arises.

A

Arises due to different wavelengths in photons or the different energies of electrons.
The faster an electron travel, the less it is diffracted by a magnetic lens. The higher the wavelength, the less it is refracted by an optical lens, thus different focal lengths.
A disk of least confusion exists at the compromise position of focus.

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20
Q

How can chromatic aberration be removed?

A

By using monochromatic light (filters) or multiple lenses of different shapes.

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21
Q

Explain how astigmatism arises.

A

Arises because focus for rays travelling in the horizontal plane are at a different position from the focus for rays travelling in the vertical plane because of different path lengths.
A disk of least confusion exists at the compromise position of focus.

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22
Q

How can astigmatism be removed?

A

Using stigmators (correcting lenses) by imposing a weak electric or magnetic quadrupole field on the electron beam.

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23
Q

List the different ways that photons can be produced for microscopy.

A
Heated filaments (cheap, white light, low intensity)
Arc discharge (small, white light, high intensity)
Gas discharge (monochromatic)
Laser (monochromatic, intense)
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24
Q

Explain how an electron gun works.

A

Requires:
-Stable voltage supply
-Controllable filament heater
-controlled bias voltage
Steps:
-Cathode is heated which emits a stream of electrons.
-Electrons are accelerated using an electric field in a vacuum.

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25
Q

How can an electron gun be improved?

A

Pointed filaments to reduce are in which electrons are emitted.
Lanthanum Boron filaments which is a brighter source due to lower work function.
High electric field to increase intensity.

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26
Q

Explain how critical and Koehler illumination works in microscopy.

A

Light source is focused on specimens using condenser lens.
Critical Illumination:
-Light from the source is focused on the image plane.
Koehler Illumination:
-An extra field diagram (Koehler lens in diagram on notion) is placed between the source and the condenser lens.
-The rays of the source are then instead focus on the aperture planes (including the eyepiece) and defocus on the sample (illumination).

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27
Q

State the advantages of Koehler illumination over Critical illumination.

A

More illumination on the sample (no glare)

Removes the image of the light source on the final image.

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28
Q

How are virtual images detected?

A

With an eyepiece

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29
Q

How are real images detected?

A

Ground glass, fluorescent phosphor

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30
Q

How are photons and electrons detected?

A

Photographic film
CCD
TV cameras

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31
Q

State the properties of an aperture.

A
Opaque to radiation.
Thin in the axial direction
Zero reflectivity
Adjustable in size
Adjustable in position
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32
Q

Explain how phases contrast microscopy works.

A

A condenser annulus limits the number of rays entering the illuminated specimen.
Condenser focuses the illuminating light on the specimen
The specimens then scatters and refracted the light causing a phase shift.The thicker the sample, the large the phase contrast.
An objective lens focuses the scattered and illuminating light on to a detector.
A phase plate is placed between the detector and the objective lens. The plate is thicker in the region where background light hits it, thus creating a larger phase change.
The background light is dimmed by a grey filter ring.
The resultant waves interfere to give rise to contrast in the final intensity in regions of the field of view that contain the specimen.

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33
Q

Explain how polarising microscopy works.

A

The incident light becomes plan polarised using a polarising filter.
The light is shone on a specimen which causes the polarisation to change depending on the angle of incidence (normally causes elliptical polarisation)
The reflected light is then analyses by the polarising unit which is perpendicular to the polariser of the incident light.
The reliant intensities are dependent on the angles of polarisation.

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34
Q

Explain how interference microscopy works.

A

Light from the specimen only differs in phase and has the same amplitudes.
A reference wave is added to the system which superposes with the existing waves
A contrast is seen as the waves have different amplitudes.

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35
Q

Explain the difference between 2-beam and multiple beam TEM.

A

2-beam:
-Reciprocal lattice is rotated by double slit only (x-y coordinates)
-g(hkl) satisfying the Bragg condition will have a diffraction spot just as intense as the central (000) spot
-Only one reciprocal lattice vector (with small indices) is seen due to a decrease in intensity of higher integer vectors
Multiple beam:
-Many g(hkl) satisfies the Bragg condition and there are many diffraction spots but less intensity than the 000 spot.
Many reciprocal lattice vectors are seen.

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36
Q

Why do electron diffraction patterns of thin crystals have many spots?

A

Wavelength of electron is much less than the spacing between the planes. Bragg angle is very small thus the large Ewald sphere intersects many reciprocal lattice points.
Bragg condition in thin samples is less rigorous as there are less scattering centres which contribute to the diffraction beam (consider double slit vs multiple slits)

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37
Q

Explain what happens to the electron diffraction pattern when the sample thickness increases.

A

As sample thickness increases, the diffraction spots strait to blur out and disappear due to the stricter Bragg angle as many scattering centres contribute to the diffracted beam.

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38
Q

Explain how selective area diffraction (SAD) works in electron microscopy.

A

Objective lens forms a diffraction pattern at the back focal plane.
An intermediate lens is to focus on the back focal plane instead of the specimen.
An aperture is place where the intermediate image forms (selected area).
The diffraction pattern is projected by the projection lens.

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39
Q

Explain the usual imaging mode in electron diffraction.

A

An aperture is placed at the back focal plane

The intermediate lens focuses on the specimen

40
Q

What happens in convergent beam diffraction and what is the advantage of it in electron microscopy?

A

It is where an incident beam is condensed into a small spot thus the patter comes from the whole of the illumination area.
Advantages:
-patterns can be obtained from very small crystallites
-direct determination of space groups.

41
Q

Explain the differences in electron patterns from a single crystal, polycrystal and fine scale polycrystal.

A

Single crystal - regular array of spots.
Polycrystal - superimposed spots patterns.
Fine scale polycrystal - ring pattern
In a polycrystal, there are more diffraction spots as the grains are orientated in different directions.
In a fine scale polycrystal, there are grains orientated in almost all directions which gives many more reciprocal lattice points.

42
Q

State the structure factor for FCC, BCC and diamond structures.

A

FCC: h,k,l are either all odd or all even
BCC: h+k+l = even
Diamond: h,k,l are all odd or all even AND h+k+l=4n

43
Q

Explain how Kikuchi patterns arise.

A

Occurs in thicker foils
Inelastic scattering followed by subsequent elastic scattering
Inelastic scattering causes rays to be scattered diffusely
Some of these electrons travel at the Bragg angle and may undergo Bragg diffraction.
Inelastic scattering is strongly biased towards low angles, the ray that diffracted at Q, is more intense than the one diffracted at R. (Notion diagram)
There is an increase in intensity to the left and a decrease to the right on the distribution of energies.
Kikchi line intensity increases with sample thickness.

44
Q

What happens to Kikuchi lines and diffraction pattern if the sample is tilted?

A

Kikuchi lines move proportional to the tilt angle as inelastic scattering events still happens and the Bragg angle is satisfied.
Diffraction pattern remains fixed as the Bragg angle is still satisfied at low tilts but at lower intensity.

45
Q

What causes streaking in electron diffraction patterns?

A

Platelet and rod like precipitates
Planar defects
Strain
Compositional variations

46
Q

What causes extra spots in electron diffraction patterns?

A

Ordering of atoms

Precipitates or other phases with particular orientation relationship

47
Q

Explain how phases shifts occur in TEM as electrons go through a specimen.

A

Negligible amount of electrons are absorbed as they pass through a sample and the amplitude change is negligible.
Different refractive indexes and thicknesses lead too variations in phases of the electron wave as they exit.

48
Q

Explain how high resolution phases contrast imaging works.

A

Thin specimens are required as it is modelled using single scattering event
The phases shift is modelled by using the contrast transfer function in which the phase shift can be approximated as contributions from defocus and spherical aberration
These phase changed electrons then interfere with other electrons creating an interference pattern.

49
Q

Why are images from high resolution phase contrast microscopy hard to interpret?

A

Phases shifts are theoretically approximate to the structure and must be compared to simulations to find the right function. It is even harder for thicker specimens as multiple scattering can alter the phases.

50
Q

Explain how diffraction contrast TEM works.

A

Samples exhibit diffraction contrast, whereby the electron beam undergoes Bragg scattering which in the case of a crystalline sample, disperses electrons to discrete locations in the back focal plane by the objective lens.
A small objective aperture is put into the back focal plane of the objective lens, which limits the area of the transmitted beam or the diffracted beam.
The diffraction pattern is created by the focusing of the intermediate lens.

51
Q

Explain the difference between light and dark field imaging.

A

Bright field - the sample is at the optical axis and the transmitted beam is therefore bright. Beams that diffract therefore do not go through the aperture.
Dark field - the sample is at an angle (tilted beam) and the diffracted beam is therefore bright. Only the beam that diffracted goes through the aperture.

52
Q

Explain the condition when diffractions caused by dislocations can be seen using bright and dark field imaging.

A
  • Diffraction condition is determined by Braggs law.
  • At a dislocation atomic planes are either closer/further apart and will therefore either dsatisfy (dislocation causes diffraction) or not satisfy Bragg’s law.
  • For an edge dislocation, the burgers vector is perpendicular to the atomic planes. Therefore if the diffraction vector g is perpendicular to b, the dislocation cannot be seen (parallel to the planes)
53
Q

Explain how bend contours can be seen by TEM.

A

Bend contours change the orientation wrt the beam causing diffraction (or no diffraction).

54
Q

Explain how coherent ppts can be seen by TEM.

A

Lattice planes on either side of the ppt distorted due to difference in lattice parameters.
Planes passing through the centre of the precipitates are undistorted.
A line of no contrast is seen as the planes are normal to the diffraction vector g in the middle of the ppt (obeying Bragg’s law) while the lattice planes on either side of the ppt does not.
A dark field image shows a bright line of no contrast.

55
Q

Explain how a stacking fault can be seen in TEM.

A

The region of crystal above the fault is out of register with the crystal below fault (disregistry R)
For a fault not to be seen R.g = n as the disregistry. The vector R moves the reflecting planes normal to themselves by a distance equal to an integer number of spacing between planes.

56
Q

Explain how thickness contrast imaging works in TEM.

A

The objective aperture is placed around the forward scattered beam (excluding many scattered electrons).
Scattering increases with mass and thickness, reducing the intensity of the image.

57
Q

What is the principle behind structure factor contrast imaging in TEM.

A

Strength of diffracted beam controlled by the structure factor which produces contrast.

58
Q

What are the uses of structure factor contrast imaging in TEM?

A

Amorphous damaging regions in irradiated samples

59
Q

Explain how diffraction conditions are set up.

A

Set up by titling specimen with reference to Kikuchi lines.
In 2 beam conditions, g is strongly excited by tilting to the Bragg angle. The reciprocal lattice is rotated by appropriate double tilt (x and y) so that a particular g(hkl) satisfying the Weiss zone law is brought exactly on the Ewald sphere.
In bright field conditions, sample is just tilted away from the 2 beam condition giving brighter field images.
In weak beam conditions, image is formed in dark field. The optical axis goes through g, but the sample is titled so that it satisfies 3g. Intensity and then increase only from regions close to core of dislocations and high strain fields to tilt to Bragg condition giving high resolution of highly strained regions.

60
Q

Explain how an SEM works.

A

Electron gun accelerates electrons using energy between 2-40keV
Condenser lenses focus the beam until it has a diameter of only 2-10nm.
Fine electron beam scanned across specimens using deflector coils.
Detector collects signal and intensity os plotted against scan position to create an image.

61
Q

What are secondary electrons.

A

Electrons in the sample that are ejected by ionisation that arises from impact of the primary beam in SEM. (Low energy, many electrons)

62
Q

What are backscattered electrons.

A

Primary electron. that have been multiply scattered in the sample so they are scattered back up towards the lenses in SEM. (High energy, little electrons).

63
Q

Sketch a diagram of the SEM signals generated and their sampling volumes.

A

Check notion.

64
Q

Explain how secondary electron images are detected and why tilting the sample gives larger contrast.

A

Detected by a scintillator of photomultiplier system (not ether energy of the secondary electrons are too low so the detector is coated in thin Al foil).
The secondary electrons are attracted to the detector by a bias voltage on the grid (10keV) and accelerated towards a phosphor screen which emits light.
Light is transmitted through a light pipe and into a photomultiplier which converts photons into pulses of electrons. Amplified and used to modulate the intensity on a Cathode ray tube.
Tilting gives a larger interaction volume that is close to the surface so more secondary electrons so more contrast.

65
Q

Explain the information that secondary electron image yield.

A

Tilted surfaces result in string topographical contrast. Improves yield of secondary electrons recorded on detector if surface faces the detector.
Potential biases prevent secondary electrons to escape the detector. Voltage contrast as there is a work function associated with secondary electron production.

66
Q

Explain how backscattered electrons are detected.

A

Using a solid state detector
“Doughnut” type arrangement, concentric with the electron beam, maximising the solid angle of collection
BSE detectors are usually either of scintillator or semiconductor types
Fraction of incident electrons that are backscattered increases with atomic number (strong composition contrast).

67
Q

Estimate the ultimate resolution of SEM.

A

Limited by spherical aberration and Rayleigh’s criterion

Approx 2nm.

68
Q

Explain why working resolution is not na high as ultimate resolution.

A

Working resolution (pixel size)
-The pixel size is determined by the minimum size that may be obtained on the cathode ray tube monitors (typically 100nm). This limits the specimens pixel size by considering the magnification:
P(spec) = P(image)/M

Ultimate resolution (sampling volume)
-depends on probe size.
The sampling volume determines the volume in which the electrons interact with the sample and can escape the surface.
-if electron probe is larger than the specimen pixel then signals from adjacent pixels are merged.
-if the electron probe is smaller than the specimen pixel then the signal will be weak (small beam current) with a lot of noise.
-For secondary electrons this is about the same as the pixel size (good resolution)
-for backscattered electrons and x-rays this is bigger than the pixel size so poor resolution.

69
Q

Define depth of field.

A

The range of positions for the object for which our eye can detect no change in sharpness of the image.
Small convergence angle increases depth of field considerably

70
Q

Show that the typical depth of field for an SEM image is larger than that for an optical microscope.

A

Check notion

Depth of focus h = s/α

71
Q

How does STEM incorporate the advantages of SEM and TEM?

A

TEM quality lenses and forcing electron beam down to 0.1nm gets atomic resolution scaled image
This sample required
X-rays and scattered electrons can also be detected.

72
Q

Sketch a typical X-ray spectrum and explain its key features.

A

Check notion

73
Q

How are characteristic X-rays produced in EDX?

A

Produced by electrons knocking the inner electron and causing an electron at a higher energy orbital to fall to the lower one emitting an electron.

74
Q

How does Brehmstrahlung arise in EDX?

A

It arises as electrons get close to the nucleus and change direction producing a photon.

75
Q

How are the highest energy X-rays formed in EDX?

A

When the nucleus completely stops the electron all the kinetic energy is released as an x-ray,

76
Q

Explain the mechanism of Auger emission and why it tends to dominate.

A

Auger emission is where an inner electron is knocked out
An electron is emitted from the outer shell
An electron at a lower energy level lowers its energy to an inner shell

77
Q

Sketch a diagram showing the sampling volume of x-ray microanalysis.

A

Check notion.

78
Q

Explain the advantages and disadvantages of thick samples in x-ray microanalysis.

A

Ads:
Sampling volume diameter of x-rays a lot larger than the resolution for secondary and backscattered electrons.
Disads:
Bad resolution as this is a lot larger than pixel size and distinct images in specimen cannot be resolved.

79
Q

Explain the advantages and disadvantages of thin samples in x-ray microanalysis.

A

Ads:
Sampling volume diameter of c-rays is a lot less due to the decreasing depth of penetration into the sample. This causes less lateral spread of the electron beam.
Disads:
The number of x-rays emitted is smaller than for a bulk specimen. Noise may be a problem.

80
Q

Explain how EDX works.

A

Detector is collimated so backscattered or secondary electrons cannot reach the detector.
Electrons focus on sample and characteristic x-rays produced. Thin beryllium window to separate the two vacuum systems (microscope and detector)
The x-rays cannot be deflected. The detector is placed near the sample in the line of sight of the sample.
The incoming x-ray excites a number of electrons in the condition band of silicon reverse biased diode, leaving holes in the valence band. Lithium is included to compensate for native impurities present that cause extra holes.
As the creation of electron hole pairs is typically 3.8eV, there are several electron hole pairs generated which is proportional tot he energy of the x-rat. This leads to increased conductivity.
EDX is operated at low T to reduce residual conductivity from thermal excitation.
A current is then produced as the electrons are now free to move in the conduction band when a potential bias is applied. It is also amplified by a pre-amp.
Electron trap to prevent backscattered and secondary electrons from entering the detector.
Dead zone where holes are present and recombination can occur.

81
Q

Explain how special artefacts of EDX arise.

A
  • Microscope may have electromagnetic coils that change the energy of the X-ray created. This is why the detector is placed as close to the sample as possible.
  • Escape peaks that occur when the Si x-ray escapes the detector leading to artefact peak equal to the energy of the parent ming the energy off the Si x-ray that is generated.
  • Some peaks occur when two x-rays arrive at the detector nearly simultaneously so that they are not discriminated by the pulse pileup rejection electronic giving a false peak as the sum of two x-rays.
82
Q

Explain the problems in the use of EDX.

A
Peak broadening (typically 150eV) and many elements overlap.
Difficult or impossible to analyse light elements due to the beryllium window. Light elements get filtered.
83
Q

State ways that light elements can be detected in EDX.

A

Use a windowless or ultra thin window detector which is good for elements heavier than C.
Use electron energy loss spectroscopy in which inelastic scattering causes ionisation and the characteristic excitation energy if the shell. The energy loss can be measured using a magnetic spectrometer.

84
Q

Explain how WDX works.

A

X-rays from specimen are filtered so only a chosen wavelength is detected.
X-rays are collimated by two sets of slits so that the x-rays are focused onto the crystal.
X-rays leaving the specimen are at a certain angle to the crystal which satisfies Braggs law and thus reach the detector.
A further slit is used to focus x-rays on detector.
The detector then counts x-ray photons arriving of the specific wavelength.
The sample, crystal and detector must lie on the Rowland circle so that the x-rays can be focused

85
Q

Compare the advantages and disadvantages of WDX to EDX.

A

Ads:
-Resolving power is excellent. peaks of less than 5eV in width.
-Gas proportional counters are capable of very high count rates, possible to collect data from single element in short time.
-Better for light element analysis.
-WDX more sensitive and can detect low concs.
Disads:
-EDX is cheaper and simpler to operate.
-Whole spectrum is acquired simultaneously using EDX whereas WDX is one wavelength at a time.
-EDX better for thin foil analysis and are good at detecting relatively small quantities of material present at relatively high conc in a local area.

86
Q

State the Cliff-Lorimer equation and explain its use.

A

C1/C2 = k12 l1/l2
A first approximation of relative weight fractions of the two elements. The Cliff-Lorimer factor is dependent on two elements, operating conditions and detector response.

87
Q

Explain how a scanning probe microscope works.

A

A probe is put very close to a surface and moved by using a piezoelectric crystal that contracts and expands by a small voltage.
A voltage is applied between the specimens and the probe top. This causes electron distribution to overlap between a protuberant atom and the probe.
As tunnelling only occurs at short distances, the magnitude of the tunnelling current depends on the spacing of atoms in which the probe current is the strongest on top of atoms.
The surface can then map to a resolution of about 0.1nm
Individual atoms can also be identified according to the current generated at each point.

88
Q

Explain how AFM works.

A

A fine tip is mounted on a cantilever beam
The tip is moved and scans the sample using a piezoelectric crystal.
The cantilever beam (deflection remains constant) will rise and fall depending on the surface topography.
A laser is shone onto the cantilever and collected by a photodiode, The angle at which the laser is reflected depends on the vertical displacement of the tip as it moves along the surface.

89
Q

Compare the use of scanning probe microscopy and AFM.

A

AFM can be conducted in most environments while STM can only be conducted in a vacuum.
The resolution of AFM is worse than STM as the force between sample and the tip is determined by several neighbouring atoms as well in AFM.
AFM requires computer processing and interpretation of images while STMs can directly image specimens.
STMs can only work for metals (conductors) as tunnelling is harder due to electrons being less “free”, while AFMs can be used for both conductors and insulators as it depends on the forces between tip and atoms.

90
Q

State an equation for contrast.

A

Check page 5

91
Q

Give the expression for Rayleigh resolution limit.

A

Check page 10

92
Q

Give the expression for size of spherical aberration.

A

Check page 15

93
Q

Give an expression for size of chromatic aberration

A

Check page 16

94
Q

Derive an expression for minimum resolution in the presence of diffraction and spherical aberrations.

A

Check page 16

95
Q

Give expressions for depth of focus, h.

A

Check notion.

96
Q

State an expression for pixel size.

A

Check notion.

97
Q

State the condition for diffraction and no diffraction for dislocation.

A

If g.b = 0 then no (or weak) contrast will be seen