Stereoelectronics Flashcards

1
Q

why can’t C=C rotate?

A

p-orbitals are parallel

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2
Q

orbital distortion in C=O bond

A

O = more electronegative than C

π orbital = distorted to O
π* orbital = distorted to C (opposite)

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3
Q

interaction of adjacent orbitals

A

adjacent orbitals are able to interact

lowers overall energy (i.e. it’s beneficial)

filled orbital able to donate into unfilled orbital

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4
Q

adjacent orbitals in amide

A

nitrogen = sp2 hybridised

remaining p orbital is well positioned to overlap with unfilled π* orbital of C=O

Nn (donator) -> π* C=O

*n = non-bonding

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5
Q

x-ray evidence for orbital interaction

A

C=O bond in amide is longer than in ketone (weaker due to partial filling of π*)

C-N bond in amide is shorter than normal C-N (stronger as it has some double bond character)

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6
Q

orbital interaction in ester

A

No -> π* C=O

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7
Q

why is the s-trans conformation in esters more stable?

A

an additional orbital interaction is possible

= 2nd oxygen lone pair in sp2 with σ* of C=O

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8
Q

why are lactones more reactive than esters?

A

ring locks conformation as s-cis, making it less stable

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9
Q

in sub. cyclohexanes, when is the conformer most stable?

A

when sub. is placed equatorially

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10
Q

6-membered rings containing oxygen

A

if carbon adjacent to oxygen has electronegative sub. AXIAL = preferred

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11
Q

epimer

A

carbohydrates that differ in the location of the -OH group in one location

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12
Q

anomeric effect

A

tendency of heteroatomic sub. adjacent to a heteroatom in cyclohexane ring to prefer the axial position instead of the less-hindered equatorial

due to No -> σ* C-O (more of these interactions = more stable)

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13
Q

orbital effects in Sn1

A

[via carbocation]

more stabilising orbital effects = faster reaction

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14
Q

hyperconjugation

A

donation from σC-C / C-H to empty p-orbital on carbon

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15
Q

conjugation

A

pi systems linking

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16
Q

why is conjugation > hyperconjugation ?

A

orbitals are parallel = better overlap

17
Q

2 cases for intramolecular sub. reactions

A
  1. Nu tethered to R group
  2. Nu tethered to LG
18
Q

are long tethers favourable or unfavourable?

A

[unfavourable]

too many conformations/degrees of freedom

19
Q

Baldwin’s rules

A

[classification of cyclic compounds]

  1. n (ring size)
  2. exo or endo
  3. hybridisation at ring closure point (dig, trig, tet)
20
Q

what is the angle of attack for trig additions?

A

Burgi-Dunitz (105-109) on sp2 carbon