States of Matter - Week 18 Flashcards

1
Q

What are 2 features of gasses?

A
  • Expand to occupy the available volume
  • Exert pressure
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2
Q

What is the gas constant?

A

PV = nRT

R = gas constant

If R is expressed in J mol^-1 K^-1, V must be expressed in m^3

If R is expressed in L atm mol^-1 K^-1, V must be expressed in dm^3.

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3
Q

A fixed amount of a gas has a temperature of 45.0 °C and is at a pressure of 2.55 x 105 Pa. What is the pressure if the temperature falls to −3.68 °C and the gas volume doubles?

A

If amount of gas remains fixed:
PiVi / Ti = PfVf / Tf and Vf = 2 x Vi

Therefore, Pf = (Tf / Ti) x Pi x ½

= (269.47 K x 2.55 x 105 Pa) / (318.15 K x 2)

= 1.08 x 105 Pa (3 sf)

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4
Q

What mass of ethane is required to exert a pressure of 5.18 x 105 Pa in a 10.0 dm3 vessel at 360 K?

A

n = PV / RT

Therefore, n = 5.18 x 105 Pa x 10.0 dm3 / 8.314 J K-1 mol-1 x 360 K

If using R = 8.314 J K-1 mol-1 , volume units must be m3.

Therefore, n = 5.18 x 105 Pa x 10.0 dm3 x 0.001 m3 dm-3 / 8.314 J K-1 mol-1 x 360 K

                     =  1.73068 mol

MC2H6 = 30.08 g mol-1 and mC2H6 = n x MC2H6 = 1.73068 mol x 30.08 g mol-1

Therefore mC2H6 = 52.1 g

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5
Q

What is the root square mean equation of gasses where M = molar mass and u^2 = the average of (speed)^2.

A

U rms = square root of (3 RT/M)

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6
Q

What factors affect distribution of particle speed in gasses?

A

Particle speed is different for different particle masses and distribution changes with temperature.

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7
Q

What affects particle energy in gases?

A

Distribution of particle energy is the same for all particles and depends only on temperature.

  • Shown inn maxwell-Boltzmann distribution curve for different temperatures where T2>T1
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8
Q

How is partial pressure calculated?

A

when there is a mixture of gasses with amounts n1, n2 etc.
PV = (n1 + n2 + …) RT = n1RT + n2RT + ….
so P = (n1RT)/V + (n2 RT)/V + ….
= P1 + P2 + …….

P1 and P2 are the partial pressures of component gases.

P = p(n1/(n1 + n2 + ….) + p(n2/(n1 + n2 + ….))
= Px1 + Px2 + …. Where x = mole fraction

= P = Px

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9
Q

The total pressure of a mixture of 2.24 g of methane and 7.15 g of carbon dioxide is
2.85 x 105 Pa at 298 K. Calculate the partial pressure of each gas at this temperature.

A

pCH4 = P xCH4 ; pCO2 = P xCO2 and P = pCH4 + pCO2

MCH4 = 16.05 g mol-! and MCO2 = 44.01 g mol-1

nCH4 = 2.24 g / 16.05 g mol-! = 0.13956 mol; nCO2 = 7.15 g / 44.01 g mol-! = 0.16246 mol

ntotal = 0.30202 mol

xCH4 = 0.13956 mol / 0.30202 mol = 0.46209
xCO2 = 0.16246 mol / 0.30202 mol = 0.53791

Therefore, pCH4 = 2.85 x 105 Pa x 0.46209 = 1.32 x 105 Pa
and pCO2 = 2.85 x 105 Pa x 0.53791 = 1.53 x 105 Pa

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10
Q

What is 1 ppm? and what is 1 ppb?

A

1 ppm = 1 particle / 10^6 particles = 1 mol / 10^6 mol (1 out of 1 million)

1 ppb = a mole fraction of 1 x 10^-9 (1 out of 1 billion)

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11
Q

What properties do the intermolecular forces within liquids cause?

A
  • Surface tension
  • Capillary action
  • Viscosity
  • Boiling point
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12
Q

What is the structural features and bonding of molecular solids?

A

Discrete particles - relatively weak interparticle forces.
Usually form crystalline or partially crystalline arrangement.

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13
Q

What is the structural features and bonding of giant molecular (network) solids?

A

Include layered structures
Covalent bonding between constituent atoms, weaker intermolecular forces - between layers
Usually form crystalline structures.

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14
Q

What is the structural features and bonding of metalic solids?

A

Iron cores (atoms minus valence electrons) bound into giant crystalline structures by completely delocalised valence electrons

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15
Q

What is the structural features and bonding of ionic solids?

A

Crystalline structures - ions held by attractive forces between opposite charges and the repulsive forces between like charges.

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16
Q

What is a phase change?

A

A solid will undergo phase changes, first to a liquid then a gas.

17
Q

Which has a larger enthalpy change, solid/ liquid change or liquid/gas change?

A

Liquid/gas change is larger. As the change separates particles completely, enough energy is needed to completely overcome interparticle attractions rather than just loosening interparticle forces.

18
Q

What is shown in a phase diagram?

A

Phase diagrams show the ranges of values of variable for which different phases are stable and the values for which different phases can co-exist in equilibrium.
Shown as a pressure - temperature (Tp) diagram

19
Q

What does a Tp (triple point) indicate?

A

It marks the unique values of temperature and pressure for which all three phases can co-exist in equilibruim.

20
Q

What is the order of strength of intermolecular forces from weakest to strongest?

A

Weakest:
Instantaneous dipole - induced dipole (dispersion)
Dipole - induced dipole
Dipole - Dipole
Hydrogen bonds —> Strongest

21
Q

How are dispersion forces formed?

A

Due to instantaneous dipoles created by the electrons in one particle influencing those in neighbouring particles creating a net attractive effect.