Starshine Flashcards

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1
Q

what is the definition of luminosity

A

the rate at which energy of all types is radiated by an object in all directions

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2
Q

therefore what is the luminosity of a star

A

the power emitted from the star

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3
Q

what two factors impact luminosity

A
  • size of the object

- its temperature

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4
Q

what is a black body radiator

A
  • a theoretical perfect emitter

- that gives off energy across the entire electromagnetic spectrum

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5
Q

what does the stefan-boltzmann law state

A
  • the output power from a black body is proportional to its surface area
  • and the fourth power of its temperature in K
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6
Q

what are the axes for the distribution graph given by the law

A
  • the y axis is the energy output (increasing upwards)
  • the x axis is the wavelength
  • with the start being the shorter wavelengths (blue)
  • and the end being the longer wavelengths (red)
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7
Q

what does the distribution graph show

A
  • there is a distribution for 6000, 4500 and 3000K, coloured red, blue and green
  • the 6000K has the highest peak which is closest to the blue end, finishing off by tapering off into the red end
  • the 4500K has the second highest peak which is second closest to the blue end, tapering off
  • the 3000K has the lowest peak which is closest to the red end, tapering off
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8
Q

what is the equation for stefan-boltzmann’s law

A
  • L = oAT^4
  • L = luminosity
  • o (sigma) = stefan-boltzmann constant (5.67x10-8 Wm-2K-4)
  • A = surface area (m^2)
  • T = temperature (K)
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9
Q

what would be the modified equation for a sphere like a star

A

L = o(4 pi r^2)T^4

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10
Q

what does stefan-boltzmanns distribution show about the relationships between the energy output and wavelengths of light emitted from a black body

A
  • at higher energy outputs (temperatures) the peak is more pronounced and reached sooner
  • so the wavelength of the peak output gets shorter as the temperature rises
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11
Q

what is the law that describes this relationship between the output wavelength and temperature

A

weins law

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12
Q

what is the formula for weins law

A
  • Y(max) * T = 2.898x10-3 mK
  • Y(max) = max wavelength (Y = lambda)
  • T = temperature (K)
  • 2.898x10-3 = weins constant
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13
Q

what are the average temperatures for a red giant, white dwarf and blue supergiant

A
  • red giant = 3,000K
  • white dwarf = 10,000K
  • blue supergiant = 25,000K
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