Spring 2022/23 Paper (Short Questions)) Flashcards
How could you encode each of the following as linear constraints? Assume that x and y are specified as binary decision variables, where the value 0 means “not selected” and 1 means “selected”.
(i) Exactly one of x and y is selected.
(ii) At most one of them is selected.
(iii) If x is selected, then y is also selected.
(iv) If x is selected, then y is not selected.
(i) x + y = 1
(ii) x + y ≤ 1
(iii) x ≤ y
(iv) x + y ≤ 1
If x* is the optimal objective function value of P and y* is the optimal function value of P’, then x≥ y
True: Adding a constraint to maximization problem (from P to P’) either leaves the feasible region unchanged or reduces it. Thus, the maximum value in P’ cannot exceed the maximum value of P, hence x≥ y
If y is a feasible solution of P’, y will also be feasible for P
True: Since P’ includes all the constraints of P plus at least one additional constraint, any solution that satisfies all the constraints of P’ must also satisfy the constraints of P
If x is optimal solution of P and x is feasible for P’, then x will be optimal for P’
True: Since adding a constraint can only reduce the feasible region or keep it unchanged, x being feasible and optimal in P makes it optimal in P’ as well, provided it remains within the feasible region of P’
Given a LP with five variables, it is known that (0,3,0,1,4) is a feasible solution. Lets suppose that we solve the associated dual problem. Which of the following cases are possible ….
(i) The dual problem has optimal bounded solution
(ii) The dual problem is infeasible
(iii) The dual problem is unbounded
(iii) The dual problem is unbounded.
If the primal problem is feasible but optimal, the dual problem could potentially be unbounded. This occurs if there is no upper bound on the objective function value in the dual problem that aligns with a primal feasible region allowing indefinite improvement
If the right-hand side term of a constraint changes, but without leaving its sensitivity interval, which of the following will remain unchanged ?
(i) the composition of the basis
(ii) the value of the basic variables
(iii) the value of the objective function
(i) the composition of the basis.
When a right hand side of a constraint changes, without leaving its sensitivity interval, the composition of the basis does not change. While both the value for the basic variables and objective function change.
Intersection of two convex sets is convex (True/False)
True: The intersection of two convex sets is always convex
Union of two convex sets is convex (True/False)
False: The union of two convex sets is not necessarily convex.
When minimizing a convex function over a convex set, a local minimum is necessarily a global minimum (True/False)
True: One fundamental property of convex functions is that any local minimum is also a global minimum when the function is defined over a convex set.
Set of points contained in a high-dimensional rectangle is an example of a convex set (True/False)
True: A high-dimensional rectangle (hyperrectangle) is a product of intervals, and like lower-dimensional rectangles, it is a convex set.
Is the LP given by ….
maximize x1 + x2
subject to.. x1 - x3 ≤ 4
x1 + x2 ≥ 2
x1 + x3 ≤ -1
x1, x2, x3 ≥ 0
(i) infeasible, or
(ii) unbounded, or
(iii) has an optimal solution?
(i) Infeasible
Given that constraint 3 “x1 + x3 ≤ -1” is inherently unsatisfiable under the non-negativity restrictions, the entire set of constraints cannot be satisfied simultaneously, thus the LP is infeasible
Consider a maximisation integer-linear program and let w∗ be its optimal objective function value. Let the optimal objective function value of its linear programming relaxation be v∗ and let y∗ be the objective function value of a feasible solution of
the dual of its linear programming relaxation. Which of the following statements is true? Briefly explain your answer.
(i) w∗ ≤ v∗ ≤ y∗
(ii) w∗ ≤ v∗ ≥ y∗
(iii) w∗ ≥ v∗ ≤ y∗
(iv) w∗ ≥ v∗ ≥ y∗
(ii) w∗ ≤ v∗ ≥ y∗
w: the optimal objective function value of the maximization integer-linear program.
v: optimal objective function value of the linear programming relaxation of the ILP
y*: objective function value of the feasible solution of the dual LP relaxation.
Each derivative of the previous format of the ILP, cannot be bigger than what it was derived from.
Consider a primal problem P and its dual problem D. If D is infeasible, what can we say about P ?
(i) It is possible that P is infeasible
(ii) It is possible that P is unbounded
(iii) It is possible that P has an optimal solution
(iv) P can be either infeasible, unbounded or optimal; infeasible D doesn’t limit P in any way
(i) It is possible that P is infeasible: TRUE
(ii) It is possible that P is unbounded: TRUE
(iii) It is possible that P has an optimal solution: FALSE
(iv) P can be either infeasible, unbounded or optimal; infeasible D doesn’t limit P in any way: FALSE
An unbounded primal implies its dual is infeasible under certain conditions, but an infeasible dual does not necessarily mean the primal is unbounded or feasible.
When Newton’s Method is started from a point near the solution, it will converge very quickly (True/False)
TRUE: Newton’s Method is known for its rapid convergence properties, particularly when started close to the solution.
In descent methods, the particular choice of search direction does not matter so much (True/False)
FALSE: The choice of search direction is crucial in descent methods. The direction, typically chosen to be in the negative of the gradient, is fundamental to ensure that each step moves towards a local minimum.