Solubility Flashcards

1
Q

compare the dissociation between strong, weak, and nonelectrolytes

A

strong electrolytes completely dissociate (and therefore dissolve) in H2O weak electrolytes partially dissociate and fully dissolve in H2O i.e. weak acids and weak bases non electrolytes: don’t dissociate at all in H20, but do dissolve in H2O

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2
Q

what is van’t Hoff factor?

A

refers to the # particles produced in solution per sole of substance

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3
Q

What is the van’t Hoff factor of 1 mole of glucose?

A

1

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4
Q

What is the van’t Hoff factor of 1 mole of NaCl

A

2: 1 NaCl = 1 Na+ and 1 Cl-

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5
Q

What is the van’t Hoff factor of Ca(NO3)2?

A

3: Ca(NO3)2 = Ca++ and 2 NO3

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6
Q

What is the van’t Hoff factor of HF?

A

between 1 and 2 This is because HF is a weak acid, it does not fully dissociate, and only partially dissociate.

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7
Q

What is the process of dissolution of electrolytes in H2O (3 steps)

A

agitation: i.e. stirring; an endothermic process because you’re adding energy to the system dissociation: the ions are pulled away from one another; an endothermic process because you’re breaking bonds, which requires energy solvation: the ions form bonds with water; an exothermic process d/t bond formation expels energy

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8
Q

How is the process of solvation of electrolytes differ between polar-nonelectrolytes and nonpolar-nonelectrolytes?

A

electrolytes undergo agitation, dissociation, and solvation polar-nonelectrolytes only undergo agitation and solvation. They do not undergo dissolution because the molecule doesn’t separate nonpolar-nonelectrolytes can only undergo agitation, but cannot undergo dissolution or solvation, as they cannot dissolve in H2O

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9
Q

Distinguish between an unsaturated, saturated, and supersaturated solution

A

unsaturated: the concentration of solute is less than the solubility factor and thus if more solute can be added and dissolved into the solution saturation: concentration of solute - colubility factor. no additional solute will dissolve if added. supersaturated solution: concentration of solute is greater than the solubility factor. If more solute is added, it will cause precipitation

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10
Q

How is solubility affected by Temp and P?

A

-directly proportional to temp when dissolving solids and liquids into other liquids/aqueous solutions -inversely proportional to temp when dissolving gases into liquids (colder temps make pop more fizzy) -solubility has no relation to P when dissolving solids and liquids into other liquids/aqueous solutions; hence pressure doesn’t affect solubility factor -solubility is directly proportional to pressure when dissolving gases. If you increase pressure, it will encourage that gas to dissolve into the liquid

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11
Q

What electrolytes are always soluble in H20?

A

Group 1 ions (i.e. Na+, K+), H+, NH4+ NO3-, CH3COO- (acetic acid), and ClO4- Note not all elements that have a +1 or -1 charge will completely be soluble in H2O, but all electrolytes that are completely soluble in H2O have a +1 or -1 charge

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12
Q

What electrolytes are usually soluble in H2O?

A

Ag+, Pb2+, Pb4+, Hg22+, Hg2+

CO32-, PO42-, S2-

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13
Q

If one mole of reactant makes 1 mol of product, and the experiment yield is 75%, how many moles of product will you get from 1 mol of reactant?

A

1 mol reactant = ( 1 mol product/ 1 mol reactant ) x 75% = 0.75 mol

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14
Q

under standard conditions, pure elements in their natural phase will have a Hf ____ and a Gf____?

A

Hf and Gf will be zero

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15
Q

True or False: cooling any substance to 0K will decrease entropy of that substance to 0?

A

False. Only entropy of a simple, chemically pure element will have 0 entropy at 0K

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16
Q

2H2 (g) + O2 (g) → 2H2O (g)

If Gf of H2O = -288. What is ∆Grxn at standard conditions?

A

Gf of H2 and O2 are zero at standard conditions

∆Grxn = Σn·products - Σn·reactants = (-288 x 2) - 0 ≈ -290 x 2 = 580

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17
Q

What is the natural phase of bromine at standard conditions?

A

liquid

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18
Q

In a rxn, Bromine gas is reacted with another reactant under standard conditions. Is the Gf bromine = 0?

A

No, because bromine is not in its standard state, as it’s standard state is liquid, not gas

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19
Q

What is the oxidation state of any pure element?

A

0

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20
Q

What is usually the oxidation state of an ion?

A

usually is the same number as the charge it has

i.e. Zn2+ has oxidation state of 2

Fe3+ has oxidation state of 3

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21
Q

What is the oxidation state of the following molecules?

1) Hg22+
2) O2
3) O
4) F2
5) F
6) H when bonded to a metal
7) H when bonded to a nonmetal

A

1) each Hg has an oxidation state of +1
2) oxidation state = 0 because its in its natural state
3) -2
4) 0 (because its in its natural state)
5) -1
6) -1
7) +1

22
Q

What is the preferred oxidation state of N?

A

-3

23
Q

What is the oxidation state of each of the molecules in the following compounds:

1) MgCl2
2) V2O5
3) SO4-2

A

1) Mg = +2, Cl = -1
2) V = +5, O = -2
3) SO4-2: S + O = -2 ⇒ S + 4(-2) = -2 ⇒ S - 8 = -2 ⇒ S = +6

24
Q

What is a ligand?

A

a molecule that attaches themselves to ions with high + charge density; bonds between the ligand and + charge molecule (usually a transition metal) will create a coordinate covalent bond (neither an ionic or covalent bond).

i.e. H2O, CN-, NH2, OH-

25
Q

What type of reaction takes place with a ligand and + charge molecule? (aka what type of reaction makes a coordinate covalent bond?)

A

A Lewis Acid-Lewis Base rxn, as the ligand acts as the e- donor and the cation acts as the e- acceptor

26
Q

Which has a bigger radius, N or F?

A

N because atomic radius decreases going from L to R across a period of the periodic table

27
Q

What is the trend of electron affinity across the periodic table?

A

EA (or the energy released when an e- is added) increases going from L to R and bottom to top across the periodic table. Thus, F has the highest negative EA value and releases the most amount of energy when an e- is added to it.

28
Q

The more negative an EA value is, the more ____(unstable or stable) that atom will be when you add an e-

A

stable

29
Q

a smaller atomic radius will ____ (decrease or increase) the negative value of EA

A

increase (because the higher the negative EA value, the more energy that is released from the molecule when an e- is added; hence the more exothermic the rxn is when adding an e-)

30
Q

What is effusion?

A

refers to the ability of a gas to travel through a small opening

31
Q

Out of solids, liquids, aqueous solutions, and gases, which are included in the equillibrium constant equation?

A

only aqueous solutions and gases. solids and liquids are not included into the equation

32
Q

Equation for Equillibrium constant

A

Kc = products / reactants = [C]c[D]d / [A]a[B]b

Generic equation = aA + bB → cC + dD

33
Q

What does each of the following mean:

1) Kc > 1
2) Kc = 1
3) Kc < 1

A

1) Kc > 1 Products are favored (aka the forward rxn is favored)
2) Kc = 1 Products and reactants are equally favored
3) Kc < 1 Reactants are favored (aka the reverse rxn is favored)

34
Q

What does each of the following mean:

1) Q > K
2) Q = K
3) Q < K

A

1) Q > K There are excess products; thus there will be a shift to the L to create more reactants (aka reverse rxn is favored to reach equillibrium)
2) Q = K reactants and products are in equillibrium
3) Q < K there are excess reactants; thus there will be a shift to the R to create more product (aka forward rxn is favored to get to equillibrium)

35
Q

How does K relate to ∆G?

A

K > 1 will give a - sign for ∆G, which makes sense because when products are favored, the rxn must be exothermic and spontaneous, and in an exothermic/spontaneous rxn ∆G is -

K < 1 will give a + sign for ∆G (forward rxn is endothermic and nonspontaeous)

36
Q

Consider the following rxn, which is at equillibrium: C (s) + H2O (g) ⇔ CO (g) + H2 (g)

How is the equillibrium (constant) affected in each of the following situations:

1) H2O is added
2) C is added
3) a catalyst is added
4) increasing the Ptotal by decreasing the V

A

1) there will be a shift to the R to create more product
2) there will be no shift because C is a solid and solids are not counted in equillibrium equations
3) a catalyst will not alter the equillibrium constant; it can only affect the rate of the rxn and thus make a reaction that is not at equillibrium reach equillibrium faster
4) this will shift the rxn towards the side that has the least amount of moles; in this case this would be towards the L, as there is 1 mole of H2O and a total of 2 moles of products

37
Q

How does increasing or decreasing Volume affect the equillibrium of a reaction?

A

Altering the volume will have an effect if there is an imbalance of moles on each side of the equation (again, not counting the moles making up the solid or liquid, only the aqueous or gas)

If Ptotal increases d/t a decrease in V, then there will be a shift toward the side with the least amount of moles

If Ptotal is decreased d/t an increase in V, there will be a shift toward the side with the more amount of moles

38
Q

How can you adjust the P and V of an equillibrium equation?

A

you adjust by addition of an inert gas in a flexible container (i.e. a cylinder with a moving piston)

39
Q

Effect of temperature on equillibrium:

1) for an endothermic rxn, heat is treated as a ____
2) for an exothermic rxn, heat is treated as a _____

A

1) reactant
2) product

40
Q

For an endothermic rxn, if you add heat to the rxn, there will be a shift towards the ____ and the K will ____

A

shift towards the right

K will increase

41
Q

For an exothermic rxn, if you add heat, there will be a shift towards the ____ and K will ____

A

shift towards the L (reactants are favored)

K will decrease

42
Q

What factor is the only factor that affects the value of the equillibrium constant?

A

temperature will only change the equillibrium constant value

adding reactants or products, and adjusting P and V will shift the rxn, but the equillibrium constant itself is unchanged

43
Q

How is equillibrium r/t rate constants?

A

Rforward = kf[A] aka the rate of the forward rxn is equal to the rate constant of the forward rxn times the concentration of the reactant

Rreverse = kr[B] aka the rate of the reverse rxn is equal to the rate constant of the reverse rxn times the concentration of product

At equillibrium: kf[A] = kr[B] ⇒ kf/kr = [B]/[A] aka products over reactants

Keq = kf/kr aka the equillibrium constant is equal to the ratio of the forward rxn and reverse rxn rate constants

44
Q

Reversing an equillibrium equation ____ the equillibrium constant

A

inverts

aka it is the reciprocal of the equillibrium constant

45
Q

Fomration Equillibria: combining multiple equillibria results in the ____ of the equillibrium constants

A

multiplication

i.e. Cu2+ (aq) + 4NH3 (aq) ⇔ Cu(NH3)42+ K1 = 1x1013

Cd2+ (aq) + 4NH3 (aq) ⇔ Cd(NH3)42+ K2 = 1x1012

Cd(NH3)42+ + Cu2+ ⇔ Cu(NH3)42+ + Cd2+

K2 must be the reciprocal because the equation must be reversed to give the last equation

K1 and 2 = K1 (1/K2) = 1013/1012 = 101

46
Q

As Ksp increases, molar solubility _____

A

increases

47
Q

Indicate in each of the following situations if a precipitate will form:

1) Qsp > Ksp
2) Qsp = Ksp
3) Qsp < Ksp

A

1) Qsp > Ksp Reverse rxn is favored bcz there are excess products; thus there will be a shift to the L and precipitate will form bcz you’ll be making more reactant. Represents a supersaturated solution
2) Qsp = Ksp you are at equillibrium; thus no more solute can dissolve and no precipitate is formed. Represents a saturated solution
3) Qsp < Ksp you have excess reactants; there will be a shift to the R, more solute is dissolving and thus no precipitate is formed. represents an unsaturated solution

48
Q

Equation to find Q

A

Q = products/reactants

same as K, but you are using initial concentration values instead of at equillibrium values

49
Q

What is the common ion effect?

A

a salt’s solubility will decrease if it is added to a solution containing a common ion

a salt’s solubility will increase if it’s added to a solution containing something that removes a common ion (adding the salt to an solution with acid)

50
Q

What is a dissociation constant indicate?

A

it tells you how difficult it is to separate a complex

For the rxn AB ⇔ A + B, Kd = [A][B] / [AB] = k2/k1

k2 = forward rate constant k1 = reverse rate constant

The larger the forward rate constant, the larger the value of Kd

The larger the value of Kd, the less difficult it is to separate the complex; in other words, the less affinity substrate A has for substrate B

51
Q

What is the affinity constant?

A

Kaff tells you the strength of binding of molecule to ligand

For rxn A + B ⇔ AB, the Affinity constant is Kaff = [AB] / [A][B] = k1/k2

Notice this is the inverse/reciprocal of the dissociation constant: Kaff = Kd

A smaller Kaff indicates a smaller affinity for the AB complex; aka the less affinity A will be attached to B