Small Regulatory RNAs Flashcards
what are 4 reasons c elegans are a good to work with in lab genetic studies?
1) Small (~1mm) free-living nematode
2) Self-fertilizing hermaphrodites making it easy to obtain homozygous lines
3) Can easily be grown in the lab
4) Large array of tools and techniques available.
what are 5 reasons why c elegans are good model system?
1) Relatively simple anatomy
2) Fate of each cell is known and can be monitored microscopically
3) Easy to generate mutants, easy genetics
4) Easy to manipulate genetically
5) Complete genome
What two mutations in C. elegans lead to repeated early developmental processes (usually found in early larval stages) leading to the absence of adult structures?
1) Lin-4 (recessive)
2) Lin-14 (dominant)
What mutation in C.elegans causes the developing larvae to skip early developmental processes leading to a premature differentiation of adult structures?
lin-14 (recessive)
what does heterochronic mean?
a developmental change in the timing or rate of events, leading to changes in size and shape
from an evolutionary perspective, what can small heterochronic changes do?
small heterochronic changes can have profound impacts on morphology
What is the major morphological difference between larval stage 3 and 4 of C. elegans?
In larval stage 3 no alae form and seam cells divide where as in stage 4 alae is formed and seam cells stop dividing.
What was deduced to be how LIN-14 acts based on the gain of function and loss of function mutations?
LIN-14 must be an activator of early developmental programs (larval stage 3) and the absence of LIN-14 induces the later larval stage 4.
What was determined to be the function of LIN-4 after double mutants were produced?
LIN-4 is a repressor of LIN-14, a activator of early developmental programs.
What happens to C. elegans when both LIN-4 and LIN-14 are operating normally?
Wild type. Activation of LIN-14 causes early processes and LIN-4 represses LIN-14 allowing progression to the late processes.
What happens to C. elegans when LIN-4 is missing?
What happens to C. elegans when LIN-4 is missing?
What happens to C. elegans when LIN-14 is constitutively active?
There is a reiteration of early stages
What happens to C. elegans when LIN-14 is constitutively active and LIN-4 is missing?
There is a reiteration of early stages
What happens to C. elegans when LIN-14 is missing?
The early stage is skipped.
What happens to C. elegans when both LIN-14 and LIN-4 are missing?
early stage is skipped
When looking at the F2 segregation’s of C. elegans LIN-4 and LIN-14 mutants what did researchers observe?
1:3 segregation of LIN-4 and 3:1 segregation of LIN-14 suggesting they were both single genes and LIN-4 is recessive while LIN-14 is dominant.
When LIN-4 and LIN-14 were mapped what was the recombination frequency to a RFLP marker?
0.1%
After finding a marker with a recombination frequency of 0.1% or LIN-4 and LIN-14 what did researchers do to generate a DNA code?
Used chromosome walking and complementation of phenotypes to find the gene region
Using chromosome walking and complementation of phenotypes to rescue the LIN-4 mutants how large of a genomic fragment was found sufficient to rescue the phenotype?
a 5kb genomic fragment was found sufficient to rescue the LIN-4 phenotype.
What did researchers discovered happened to the lin-4 mutant that causes the mutant phenotype that changes C. elegans developmental patterns when they used a pVT2D as a probe for genomic Southern Blots?
Several kb of genomic DNA including large parts of pVT2S are deleted in lin-4
After discovering that a deletion event had occurred and was the source of the lin-4 mutant phenotype in C. elegans, researchers narrowed to a small genomic fragment that was causing the phenotype. What was the size of the fragment needed to rescue the phenotype?
0.7kb genomic fragment is sufficient to rescue the lin-4 phenotype.
What type of mutation causes the lin-4 mutant phenotype in C. elegans?
lin-4 is a complete null, loss-of-function mutant.
After discovering what caused the lin-4 mutant in C. elegans, researchers wanted to know if there is a transcript corresponding to lin-4. They used pVT2D as a probe to screen a cDNA library, what did they find?
They identified only one type of cDNA that hybridized with the probe, but the 0.7kb region containing lin-4 is not part of the mRNA.
Why when researchers identified only one type of cDNA that hybridized with the probe, the 0.7kb region containing lin-4 was not part of the mRNA?
The genomic region downstream of the lin-4 fragment contains the splice junction causing lin-4 to be spliced out.