Small molecule activation Flashcards
N2
Isoelectronic with CO (but non-polar, weaker sigma-donor and weaker pi-acceptor)
Usually coordinates end-on as a terminal ligand, side on (eta2) coordination is rare (draw)
Metal tends to be in a low oxidation state (i.e. electron rich) to allow backbonding (draw)
N-N dissociation energy
E = 945.4 kJmol-1
Interesting reactivity of N2 complexes
Due to partial -ve charge on N
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N2 activation scheme
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Examples of N2 complexes
RuCl3 + N2H2 —> [Ru(NH3)5(N2)]2+
[Ru(NH3)5(OH2)]2+ + N2 —> [Ru(NH3)5(N2)]2+
N2 is non-activated in both systems
Displacing the coordinated H2O is facile because the electron-rich Ru would prefer to swap a sigma-donor for a pi-acceptor
Displacement of N2 by various ligands
e.g. PMe3, CO, imines, isocyanides
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Isocyanides
Can displace CO as well as N2
Isocyanides are stronger sigma-donors and weaker pi-acceptors than CO – but their pi-accpetor character is influenced by the nature of R
Isocyanide resonance forms
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Making NH3 from N2 using homogeneous complexes
N2 + 6H+ + 6e- —> 2NH3
We need:
Source of H+, where the counter ion X- can’t coordinate to the metal centre
Reducing agent (i.e. source of electrons), whose oxidised species also can’t form a complex (or pick up the H+)
Problems associated with homogeneous complexes for N2 activation
Can disproportionate and become deactivated (draw)
Ideal position of ligands with respect to coordinated N2
Want the ligand to be trans to N2
Sigma donors can push electron density onto the metal, which would allow increased back-bonding to N2 and therefore weaken the N-N bonds
So generally use tridentate/tetradentate ligands
Stoichiometric N2 activation using [MoCl3(THF)3] complex as starting material
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Mo is biomimetic
Metal centre is a low oxidation state (Mo0)
N ligand is sigma-donating
BUT get pi-backbonding into sigma* of phosphine ligand, rather than onto N :(
Catalytic N2 activation
Reducing agent = CoCp2 (Cp = bulky which prevents the reducing agent from forming other complexes)
Proton source = 2,6-lutidinium tetraarylborate
Ligand = tetradentate amide. Amides = good sigma and pi donors, phosphine ligands would limit the amount of back bonding to N2 because phosphines can accept electron density themselves. Bulky tetradentate ligand = stabilises the complex, forms a ‘cage’ around the metal centre that means N2 can only bind in a linear fashion
Side reaction in catalytic N2 activation
CoCp*2 can react with the H+ source and produce H2 rather than NH3 (loss of efficiency)
Only 4 full turnovers of catalytic cycle possible to produce 8 eq of NH3
Intermediates in catalytic N2 activation
All neutral intermediates can be crystallised
Mo-N bonds length decreases and N-N bond length increases from M