Section 2 - EM Radiation and Quantum Phenomena Flashcards
What happens if you shine a light of high enough frequency onto the surface of a metal?
Shining a light of high enough frequency onto the surface of a metal causes it to emit electrons.
What is the frequency required for the photoelectric effect in most metals?
In the UV range.
Describe how the photoelectric effect works.
- Free electrons on the surface absorb energy from photons.
- If an electron absorbs enough energy they will vibrate, the bonds holding it to the metal break and it is released.
- The emitted electrons are called photoelectrons.
What 4 conclusions can be made from experiments on the photoelectric effect?
- For a certain metal, no photoelectrons are emitted if the radiation is below a threshold frequency.
- Photoelectrons have varying kinetic energies, up to a maximum. This maximum kinetic energy increases with radiation frequency.
- Intensity of radiation is the amount of energy per second hitting an area of the metal. The maximum kinetic energy is not affected by intensity.
- The number of photoelectrons per second is proportional to the intensity of radiation.
What is the energy of an EM waves of a particular frequency proportional to? (Wave theory)
Energy carried should be proportional to the intensity of the beam.
(remember this is only for waves, not for the photoelectric effect)
How is the energy of a wave distributed across it’s wavefront?
Spread evenly.
What is the threshold frequency in the photoelectric effect?
The frequency of the radiation below which no photoelectrons are emitted.
How does the frequency of the light affect the photoelectric effect?
The higher the frequency of the EM wave , the greater the maximum kinetic energy of the photoelectrons.
How does the intensity of the light affect the photoelectric effect?
The higher the intensity, the more photoelectrons are emitted per second.
Does the light intensity affect the maximum kinetic energy of photoelectrons?
No.
What is light intensity?
The power (energy transferred per second) hitting a given area of a metal.
Why can’t the photoelectric effect be explained by wave theory?
According to wave theory:
• For a certain frequency, energy is proportional to intensity.
• Therefore each free electron should get a bit of energy from each incoming wave.
• Gradually, each electron would gain enough energy to leave the metal. If an EM wave had low frequency it would take longer for electrons to gain enough energy but would eventually happen.
So:
• (Kinetic) energy transferred to electron should increase with intensity - It doesn’t!
• Electrons should be emitted eventually, regardless of frequency - But in reality, there is a threshold frequency!
- Kinetic energy depends on only frequency in the photoelectric effect - wave theory can’t explain this.
For a certain frequency of light, the intensity is proportional to…
The energy carried.
Why can wave theory not explain why the kinetic energy of a photoelectron in the photoelectric effect only increases with frequency (and not intensity)?
As light intensity increases, the energy transferred to each electron should increase also. This doesn’t happen.
Why can wave theory not explain why the threshold frequency in the photoelectric effect?
The electrons should gradually gain energy and be emitted eventually, regardless of the radiation frequency. This doesn’t happen.
Who suggested a photon model of light?
Einstein
What is a photon?
A discrete packet of light.
What is the equation for the energy of a photon?
E=hf
Where h = 6.63 x 10^-34
In the photoelectric effect, how many electrons can each photon transfer its energy to?
Only one.
How can the photoelectric effect be demonstrated with a zinc plate, an electroscope and a gold leaf?
Zinc plate is attached to the top of an electroscope (box with a piece of metal with a strip of gold leaf attached).
Zinc plate is negatively charged - this means the metal in the box is negatively charged.
The negatively charged metal repels the gold leaf, causing it to rise up.
UV light is then shone onto the zinc plate.
The energy of the light causes electrons to be lost from the zinc plate via the photoelectric effect.
As the zinc plate and metal lose their negative charge, the gold leaf is no longer repelled and so falls back down (towards the metal).
How does a photocell work?
How does the photon model of light explain the photoelectric effect?
- When EM hits the metal surface, it is bombarded by photons
* If one of these photons collides with a free electron, the electron will gain energy equal to hf.
What is the work function of a metal?
The energy that must be supplied to an electron on the surface of a metal so that it can escape the metal as a photoelectron.
What is the symbol for the work function?
Phi ϕ
Is the work function of each metal the same?
No, it varies between metals.
What happens when the energy gained by an electron is less than the work function?
No electron is emitted, but the electron vibrates and releases the energy as another photon.
The metal heats up.
What happens when the energy gained by an electron is more than the work function?
The electron is emitted from the metal.
Give an equation for the threshold frequency.
f0 = ϕ / h
Give an explanation for the range in energies of the photoelectrons emitted from a metal.
The ones deeper down in the metal lose more energy when exiting than the ones nearer the surface. (For example they might have to do work to get to the surface of the metal)
What is the photoelectric equation?
hf = ϕ + Ek(max)
where:
Ek(max) = 1/2 x m x v(max)^2
What is the reasoning for the equation: hf = ϕ + Ek(max)?
The minimun amount of energy an electron can loose is the work function energy.
So the maximum kinetic energy is:
Ek(max) = hf - ϕ
This makes:
hf = ϕ + Ek(max)
What is the equation for the maximum kinetic energy of an electron in terms of mass and velocity?
Ek(max) = 1/2 x m x v(max)^2
Why is the kinetic energy of a photoelectron independent of the intensity of light?
Each electron can absorb only one photon at a time.
What is the definition of ionisation energy?
minimum energy needed to remove an electron from (an atom from) the ground state.
What can the stopping potential be used for?
Measuring the maximum kinetic energy of photoelectrons.
What is stopping potential?
The p.d. needed to stop the fastest moving photoelectrons emitted in the photoelectric effect.
How does calculating the stopping potential work?
- Emitted photoelectrons are made to lose their energy by doing work against a potential difference.
- The work done by the p.d. in stopping the fastest electrons is equal to the energy they were carrying.
What equation is used in calculating the maximum kinetic energy of photoelectrons using their stopping potential?
Ek(max) = e x Vs
Where:
e = Charge on the electron (1.6 x 10^-19)
Vs = Stopping potential
What is the unit for Ek(max)?
Joules (J)
Explain why the equation “Ek(max) = e x Vs” works.
- The work done by the potential difference is equal to p.d. x charge.
- This work done is equal to the kinetic energy lost by the electron.
Where in an atom can electrons exist?
Only in well-defined energy levels.