Reversed Curves Problem Solving

Question 1

Given a reversed curve of I1=20°, I2=24°, D1=8°, D2=7°. Compute the length of the common tangent of the reversed curve, use arc basis; station of the PC if V1 is at station 12 + 988.2; station of PT.

Answer 1

V1V2 = 60.057 m
Sta PC = 12 + 962.943 m
Sta PT = 13 + 081.514 m

Question 2

Two parallel tangents are connected by a reversed curve having equal radii of
360m. If the central angle of the curve is
8°, compute the distance between the parallel tangents. Compute the length of chord from PC to PT and the stationing of PT when PC is at 3 + 960.4.

Answer 2

d = 7.007 m
C = 100.449 m
Sta PT = 4 + 060.934 m

Question 3

A reversed curve connects two converging tangents intersecting at an angle of 30°. The distance of this intersection from the V1 of the curve is 150m. The
deflection angle of the common tangent from the
back tangent is 20° and the azimuth (from the south)
of the back tangent is 320°. The degree of curve of the second curve is 6° and the stationing of the vertex of the first curve is 4 + 450. Determine: R1, station PRC and station PT.

Answer 3

R1 = 50.19 m
Sta PRC = 4 + 458.67 m
Sta PT = 4 + 625.34 m