Respiration And Respiratory Monitoring

Question 0

Euthermic 70 kg pt, metabolic jumping off point

Answer 0

242 ml/min

Question 1

Metabolic jumping off point equation

Answer 1

Vo2= W^0.75 * 10 (ml/min)

Question 2

Respiratory quotient

Answer 2

R=Vco2/Vo2

Question 3

Resp quotient for metabolically euthermic patient

Answer 3

0.8

Question 4

CO2 production equation

Answer 4

Vco2=Vo2*R

Question 5

Vco2 for metabolically normal 70kg pt

Answer 5

Vco2=242 ml/min * 0.8

= 194 ml/min

Question 6

Co2 produced where in cell?

Answer 6

Mitochondria

Question 7

Minute ventilation

Answer 7

Total vol of gases moving into and out of the lungs each minute

Question 8

Minute ventilation for pt w equal tidal volumes (equation)

Answer 8

Ve=Vt*f

Question 9

Pt w breaths of diff vol, min vent equation

Answer 9

Ve=summation of Vt in one minute

Question 10

Co2 leaves gas exchange region by

Answer 10

Diffusion

Question 11

Co2 transported thru conducting airway by

Answer 11

Convection to the mouth and nose

Question 12

Pressure H2O

Answer 12

47 mmHg at 37C

Question 13

Pbar at sea level

Answer 13

760 mmHg

Question 14

Pbar atl

Answer 14

737 mmHg

Question 15

Boyles law

Answer 15

P1V1=P2V2

Question 16

Dalton’s law

Answer 16

P1+P2+…+Pn=Ptotal

Question 17

Fractional concentration

Answer 17

Fx=Px/Ptotal or f1+f2+…fn=1.00

Question 18

Alveolar ventilation (Va)

Answer 18

Total vol of gases flowing into and out of gas exchange region each minute

Question 19

Partial pressure of co2 in alveoli

Answer 19

Paco2=40mmhg (ideal alveolar value for a normal eucapnic pt)

Question 20

Normal range for paco2

Answer 20

36-44 mmHg

Question 21

Water vapor pressure

Answer 21

47 mmHg

Question 22

Total pressure of gases in alveoli under dry conditions

Answer 22

Pbar=737-47mmhg=690mmhg

Question 23

Calculate alveolar ventilation

Answer 23

Paco2Va=pbarvaco2 ==> paco2/Pbar=vaco2/va

Question 24

Alveolar ventilation (to get co2 out of parynchema) for 70kg euthermic pt

Answer 24

3346ml/min

Question 25

Faco2=paco2/Pbar for euthermic 70kg pt

Answer 25

0.06

Question 26

Va=vaco2/faco2

Answer 26

Va=194ml/min / 0.06 =3346 ml/min

Question 27

Volume of conducting airways

Answer 27

Anatomic dead space

Question 28

VdANAT

Answer 28

Anatomical dead space calculated based on weight

Question 29

VdAnat constant

Answer 29

2.2ml/kg =1ml/lb

Question 30

Anatomic dead space ventilation (V w dot on top) is product of

Answer 30

Anatomic dead space times respiratory rate

Question 31

For 70kg pt breathing 10 times per min , dead spaces ventilation would be

Answer 31

Vdanat=(vdanat*2.1ml/kg)*10

Question 32

Anatomic dead space ventilation

Answer 32

Less than amount needed to get rid of co2 in airway as compared to parynchema

Question 33

Minute ventilation

Answer 33

Total vol of gases moving into and out of lung each Minute

Question 34

Minute ventilation equation

Answer 34

Ve=va+vdanat

Question 35

Minute ventilation for 70kg pt breathing 10x/min

Answer 35

Ve=va+vdanat=3346 +1540 ml/min =4886 ml/'min

Question 36

How to calculate tidal volume

Answer 36

Vt=ve/f = 4886ml/min /10 ml =488.6 ml (set your tidal vol to this

Question 37

What's coming out when we breathe?

Answer 37

Upper, lower, alveolar gasses

Question 38

Plateau in waveform in capnography

Answer 38

Alveolar has leaving parenchyma

Question 39

The only true measure of effectiveness of ventilation

Answer 39

Arterial partial pressure of co2 (paco2)

Question 40

O2 is carried in whole blood in what 2 forms

Answer 40

Dissolved o2 and o2 bound to hemoglobin (in equilibrium w one another)

Question 41

Where does the gas exchange region begin?

Answer 41

17th generation

Question 42

Where does the gas exchange region end?

Answer 42

23rd generation

Question 43

Lung compliance is the

Answer 43

Ability for the lungs to expand

Question 44

Compliance equation

Answer 44

Change in volume divided by change in pressure

Question 45

Lung thoracic compliance equation

Answer 45

Clt=tidal volume / airway pressure . (Vt/Paw) in ml/cmh2o

Question 46

Total Compliance for normal awake pt

Answer 46

100 ml/cmh2o

Question 47

Smaller the lung thorax compliance number =

Answer 47

Less compliance meaning lungs r more stiff and rigid

Question 48

Lung and thorax in a series

Answer 48

1/Clt=1/Cl + 1/Ct where these are individual compliance a

Question 49

Normal lung compliance

Answer 49

200ml/cmh2o

Question 50

Normal thoracic compliance

Answer 50

200ml/cmh2o

Question 51

An obese patient more than likely will have a

Answer 51

Small thoracic compliance ie 50ml/cmh2o and can have a normal lung compliance (patients will vary)