Resonance Flashcards

1
Q

Where is resonance usually observed

A

electron density is dynamically shared in organic compounds, especially in pi-systems and atoms that possess p-orbitals

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2
Q

What is resonance

A

it essentially is the delocalization (movement) of pi-electron density across a consecutive number of atoms that all possess a p-orbital
- the p orbs act as a conduit for the flow of electron density and this delocalizability affords increased stability to the the molecule

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3
Q

How does electron density flow

A

from areas of high electron density to areas of electron deficiency

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4
Q

Concentrated electron density tends to be more ___ and delocalizing electron density enables multiple atoms to accommodate the density

A

concentrated E density is more reactive (higher in energy and thus less stable)

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5
Q

Resonance energy is

A
  • the amount of stability (lowering of energy) afforded to a molecule through electron destabilization
  • it depends on how many distinct contributors a compound has and how similar in energy resonance contributors are to one another
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6
Q

Compounds that have a greater number of resonance contributors tend to have a ____ resonance energy (exist at a lower energy)

A

more resonance contributors = greater resonance energy (aka more stable)

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7
Q

The more similar resonance contributors are in energy to one another, the ___ the resonance energy of the compound

A

the greater the resonance energy of the compound

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8
Q

___ of the atoms bearing charges can also impact the stability of contributors

A

The electronegativity

ex. O atom accommodates a negative charge much better than a C atom

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9
Q

Two factors that affect resonance stability

A

1) full octets - full octet species are more stable (lower in energy) than incomplete octet species
2) electronegativity

*** octets > electroneg

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10
Q

Positive and negative atoms are:

A

Positive atoms are stabilized by electron donation and destabilized by electron withdrawal

Negative atoms are stabilized by electron withdrawal and destabilized by electron donation

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11
Q

Carbocations are ____ species

A

incomplete octet species

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12
Q

You can delocalize lone pairs or pi-electrons towards:

A

1 - pi systems
2 - atoms with an empty p-orbital (eg. carbocations, boron, aluminum)

  • ** NEVER delocalize towards an sp3 atom - they do not possess p-orbitals
  • ** NEVER break sigma bonds
  • ** overall charge should be conserved between contributors
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13
Q

Electrons resonante in a ___ fashion for neutral and overall negative compounds

A

1,3 fashion - aka when drawing individual contributors if the electrons are in the 1 location they would move to the 3 location

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14
Q

A positive charge will resonate in a ___ fashion when a heteroatom resonates to stabilize a carbocation but a carbocation resonates in a ____ fashion along a carbon chain

A

1,2 fashion for positive charge that is stabilizing a carbocation

1,3 fashion for carbocations along a carbon chain

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15
Q

use ___ arrow for overall positive and heteroatoms resonating towards a carbocat

A

ONE arrow (two for negative and neutral)

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16
Q

Radicals resonate in a ____ fashion and ___ arrows that are __ __ are used to show next contributor

A

radicals resonate in a 1,3 fashion and need THREE single barbed arrows to show next contributor

17
Q

Delocalized vs. localized

A

delocalized lone pairs are located in p-orbitals

localized lone pairs will exist in hybrid orbitals - they are isolated and cannot be delocalized

**only electrons residing in p-orbs or in pi-bonds are delocalizable

18
Q

Pyrrole vs pyridine

A

pyrrole’s lone pair exists in a p-orbital while pyridine’s lone pair is in a sp2 hybrid orbital and will NOT be delocalized into the pi-system

explanation: N is already making 3 sigma bonds in pyrrole so all the sp2 orbitals are being utilized so lone pair will be in p orb, but N in pyridine is making 2 sigma bonds and 1 pi bond so the pi orb is used by the pi bond, leaving an sp2 orb available for the lone pair

19
Q

Furan and thiophene each have a ___ pair and a ____ pair

A

a localized lone pair and a delocalized lone pair

20
Q

General notes on N and P atoms:

A

** if the N atom is already visually making a pi bond, then its lone pair will reside in a hybrid orbital and will NOT be delocalizable

** if the N atoms is NOT visually pi-bonded, then the lone pair will reside in a p orb and will delocalize into the pi-system

21
Q

Note on O and S atoms

A

** O and S when adjacent to a pi-system will delocalize one lone pair and the other lone pair will not be delocalizable

22
Q

** when classifying compounds as aromatic/non or anti, do NOT count the pi-electrons of a carbonyl that is coming off the ring - these electrons are NOT part of the ring’s ___

23
Q

conjugated system

A

alternating double and single bonds (each consecutive atom possesses a p orb)
- pi bonds in conjugated systems can be delocalized

24
Q

Each pi bond is formed by ___ electrons aka ___ pair, but in conjugated systems, the electrons in the pi bonds can be delocalized

A

2 electrons aka one pair of electrons

25
Q

what is a heteroatom

A
  • a non carbon or hydrogen atom (O, N, Cl, S etc)
  • one lone pair of a heteroatom can be delocalized into a pi-system
  • if the heteroatom has 2 lone pairs, only one can be delocalized
26
Q

Carbocat- heteroatom resonance

A
  • heteroatoms that are bonded to a carbocat may resonate and form a pi bond
  • the heteroatom donates its lone pair into the carbocat’s empty p orb
  • carbocats are incomplete octet structures but the resonance contributor with the positive on the heteroatom is a full-octet contributor and is notably more stable than the carbocat
27
Q

Boron and aluminum heteroatom resonance

A
  • like carbocats, B and Al have empty p orbs when neutral so when B or Al are bonded to a heteroatom, the heteroatom can resonate into the empty p orb and form a pi bond
  • B and Al take on a formal negative charge when they make 4 bonds
28
Q

in negative charge resonance, two arrows are necessary to describe the flow of pi-electrons between contributors because

A

one pi bond is formed and one is broken

29
Q

in positive charge resonance, only one arrow is necessary to describe the flow of pi electrons between contributors because

A

all of the pi-density in one pi-bond is moved to the adjacent empty p-orbital to form a new pi-bond