Renal plasma clearance Flashcards

1
Q

Explain the inulin method

A

-inulin (not insulin)
-an inert polysaccharide
-filters freely through the glomerular membrane
-not absorbed, secreted or metabolised

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2
Q

Explain the relationship between the rate of filtration through glomerular membrane and rate of entry into bladder

A

Rate of filtration through the glomerular membrane = rate of entry into bladder

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3
Q

What is the equation for rate of inulin filtration

A

rate of inulin filtration= [Pin] x GFR

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4
Q

What is the equation of Pin x GFR

A

Pin x GFR = Uin x urine flow rate

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5
Q

What is the rate of entry into bladder

A

rate of entry into bladder= [Uin] x urine flow rate

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6
Q

What is the equation for GFR

A

GFR= Urine insulation concentration x urine flow rate x plasma inulin concentration

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7
Q

What is the definition of renal clearance

A

Renal clearance of a substance is the volume of plasma that is completely cleared (excreted into urine) of the substance by the kidney per unit of time (ml/min)

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8
Q

What are drawbacks of inulin method

A
  • Drawbacks inulin method:
  • prolonged infusion
  • repeated plasma samples
  • difficult routine clinical use
  • Use creatinine for clinical GFR measurement
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9
Q

What are advantages and disadvantages for measuring GFR (creatinine)

A

Advantages:
-an intrinsic inert substance
-released at steady level in plasma from skeletal muscle
-no infusion needed
-freely filtered
-not reabsorbed in the tubule

Disadvantages:
-some secreted into the tubule
-GFR < Ccr = Ucr x V*

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10
Q

Explain the mechanism of creatinine

A

Trimethoprim competes with Crn for same transporters that secrete Crn from tubular blood into urine —-> increase in serum levels of Crn

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11
Q

What is the equation for GFR

A

GFR/CCr= UCr x V* PCr

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12
Q

Explain EGFR

A

eGFR is estimated Glomerular Filtration Rate:

  • An equation using blood tests, age, sex, and other information to estimate GFR
  • Current equation = CKD-EPI Adults (Chronic Kidney Disease Epidemiology
    Collaboration)
    A New Equation to Estimate Glomerular Filtration Rate. Ann Intern Med. 2009; 150:604-612.
  • This isn’t as good as measuring it (i.e. 24h urine collection), but is much
    simpler as it requires just one blood test.
  • Can spot kidney disease earlier than would be possible using just
    creatinine measurements
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13
Q

What are the 5 stages of CKD stages

A

1) GFR* 90+
-normal kidney function but urine findings or structural abnormalities or genetic trait point to kidney disease
-treatment: observation, control of blood pressure

2) GFR* 60-89
-mildly reduced kidney function point to kidney disease
-treatment; observation, control of blood pressure and risk factors

3A/3B) GFR* 45-59 OR 30-44
-severely reduced kidney function
-planning for end stage renal failure

4) GFR* 15-29
-severely reduced kidney function
-planning for end stage renal failure

5) GFR* <15 or on
-very severe, or end stage kidney failure
-treatment choices

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14
Q

What are final notes on EGFR

A

-it is only an estimate (significant error is possible)

-eGFR is most likely to be inaccurate in people at extremes of body type

-it is not valid on pregnant women or children or patients over the age of 70

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15
Q

Explain the clearance of different substances

A

1) Substances with clearance= (inulin = GFR):
-approx 125ml/min in adult male and 10% less in females
-e.g. antibiotics ((streptomycin)

2) substances with clearance < inulin (<GFR):
-either not filtered freely
-or reabsorbed from tubule

3) substances with clearance > inulin (>GFR):
-secreted into tubule

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16
Q

Explain what happens when GFR > clearance

A

1) not freely filtered:
-albumin clearance
-similarly for drugs bound to albumin

2) substances that are reabsorbed:
-filters freely but is usually absent from urine—> completely reabsorbed

17
Q

Explain what happens when GFR > clearance in other substances

A

Actively reabsorbed:
-all amino acids
-clearance= 0ml.min-1 unless excess filtered
-pathological conditions
-production of Bence-Jones protein in plasma

-Ca2+, Na+, PO42-, Mg2+
-water soluble vitamins
-passively reabsorbed

18
Q

Explain what happens when clearance ? GFR and examples

A

-substances that are secreted:
-filters freely
-secreted actively against electrochemical gradient

Examples:
-endogenous
-weak organic acids and bases, adrenaline, dopamine, steroids

-exogenous :
-penicillin, probenecid, para-aminohippuric acid

19
Q

Explain renal plasma flow (RPF) and renal blood flow (RBF)

A

-RPF is the rate at which plasma flows through the kidney

-estimating the RPF through the kidneys allows us to estimate the rate of total blood (RBF) through the kidneys

-blood consists of about 55% plasma and about 45% cellular components

20
Q

Explain para-aminohippuric acid

A

-PAH is a weak acidic metabolite of glycine (originally found in horse urine)

-filtered freely and enters glomerular filtrate but large amount still in plasma

-majority is secreted back into proximal convoluted tubule —> excreted into urine

-suitable as a marker to measure renal plasma flow

21
Q

Explain how PAH secretion happens simply

A

-active transport occurs in basolateral membrane
-passive transport across luminal membrane into tubule

22
Q

What happens if PAH is low enough

A

if plasma (PAH) is low enough- it is virtually completely cleared in a single pass through the kidney

23
Q

Explain renal filtration fraction

A

-GFR and RPF can be used to calculate the filtration fraction

-filtration fraction= GFR

GFR is determined from inulin clearance
RPF determined from PAH clearance

24
Q

What are normal clearance values

A

1) Glucose:
-0ml/min-1
-completely reabsorbed

2) Inulin:
-125ml/min-1
-not reabsorbed and not secreted

3) PAH:
-625ml/min
-completely secreted